Đặt \(A=\frac{25^3.3+25^3.5}{2^{27}}\)

   Ta có:\(A=\frac{25^3\left(3+5\right)}{2^{27}}\)

             \(A=\frac{25^3.8}{2^{27}}\)

              \(A=\frac{25^3.2^3}{\left(2^9\right)^3}\)

              \(A=\frac{50^3}{512^3}\)

              \(A=\left(50:512\right)^3\)

              \(A=\left(\frac{25}{256}\right)^3\)

Vậy \(A=\left(\frac{25}{256}\right)^3\)

\(\frac{25^3\cdot3+25^3\cdot5}{2^{27}}=\frac{25^3\left(3+5\right)}{2^{27}}=\frac{5^3\cdot2^3}{2^{27}}=\frac{10^3}{\left(2^9\right)^3}=\left(\frac{5}{256}\right)^3\)

thì có bạn Nobi Nobita với tớ giải tiếp rồi đó.

a. \(-\frac{13}{6}:\frac{25}{7}+\frac{7}{25}.\left(-\frac{17}{6}\right)\)

\(=-\frac{13}{6}.\frac{7}{25}+\frac{7}{25}.\left(-\frac{17}{6}\right)\)

\(=\frac{7}{25}.\left[\left(-\frac{13}{6}\right)+\left(-\frac{17}{6}\right)\right]\)

\(=\frac{7}{25}.\left(-\frac{30}{6}\right)\)

\(=-\frac{7}{5}\)

b. \(\frac{-4^5.3^5}{2^4.6^4}+2015^0=\frac{\left(-4.3\right)^5}{\left(2.6\right)^4}+1=\frac{-12^5}{12^4}+1=-12+1=-11\)

a) \(\frac{-13.7}{6.25}\)+ \(\frac{-7.17}{25.6}\)=\(\frac{-210}{210}\)=-1

b) \(\frac{-4^4.4.3^4.3}{2^4.3^4.2^4}\)=\(\frac{-2^4.2^4.4.3^4.3}{2^4.3^4.2^4}\)=-12

Mình làm câu đầu. Câu sau đang nghĩ

\(\frac{2.7.13}{26.35}=\frac{2.1.1}{2.5}=\frac{1}{5}\)

Ủng hộ tk Đúng nhé ! ^^ 

\(2^3.3-13.2^4+3.8\)

\(2^3.3-13.2.2^3+3.2^3\)

\(2^3.3-26.2^4+3.2^3\)

\(=2^3\left(3-26+3\right)\)

\(=2^3.\left(-20\right)\)

\(=\left(-160\right)\)

\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}=\frac{1^{20}+1^{20}}{1^{25}+8^5}=\frac{1}{32769}\)

\(N=\frac{6^6+6^3\cdot3^3+3^6}{73}=\frac{53217}{73}=729\)

T khó quá!

minh khong hieu

minh khong hieu ban thanh oi