\(A=\frac{5}{1x2}+\frac{5}{2x3}+\frac{5}{3x4}+\frac{5}{4x5}+\frac{5}{5x6}+\frac{5}{6x7}+\frac{5}{7x8}\)
Ai nhanh mk tick nha!
Tính nhanh
A = \(\frac{3}{1x2}+\frac{7}{3x4}+\frac{11}{5x6}+\frac{15}{7x8}\) và B = \(\frac{5}{2x3}+\frac{9}{4x5}+\frac{13}{6x7}\)
\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}+\frac{1}{7x8}+\frac{1}{8x9}+\frac{1}{9x10}\)
\(\frac{1}{2x3}\)+\(\frac{1}{3x4}\)+\(\frac{1}{4x5}\)+\(\frac{1}{5x6}\)
=\(\frac{3-2}{2x3}\)+\(\frac{4-3}{3x4}\)+\(\frac{5-4}{4x5}\)+\(\frac{6-5}{5x6}\)
Làm tiếp phần còn lại của phép tính ?
\(\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}\)
\(=\frac{3-2}{2\times3}+\frac{4-3}{3\times4}+\frac{5-4}{4\times5}+\frac{6-5}{5\times6}\)
\(=\frac{3}{2\times3}-\frac{2}{2\times3}+\frac{4}{3\times4}-\frac{3}{3\times4}+\frac{5}{4\times5}-\frac{4}{4\times5}+\frac{6}{5\times6}-\frac{5}{5\times6}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\frac{1}{2}-\frac{1}{6}\)
\(=\frac{1}{3}\)
so sánh A vơi 1. Biết \(A=\frac{5}{5x6}+\frac{5}{6x7}+\frac{5}{7x8}+\frac{5}{8x9}+\frac{5}{9x10}+\frac{5}{10x11}\)
Mong các bạn giúp giùm thank
A= 5.(1/5.6+1/6.7+...+1/10.11)
A=5.(1/5-1/6+1/6-1/7+.....+1/10-1/11)
A=5.(1/5-1/11)
A=5.6/55=6/11
Ta có: \(A=\frac{5}{5x6}+\frac{5}{6x7}+\frac{5}{7x8}+\frac{5}{8x9}+\frac{5}{9x10}+\frac{5}{10x11}.\)
\(=5\left(\frac{1}{5x6}+\frac{1}{6x7}+\frac{1}{7x8}+...+\frac{1}{10x11}\right)\)
\(=5\left(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+...+\frac{1}{10}-\frac{1}{11}\right)\)
\(=5\left(\frac{1}{5}-\frac{1}{11}\right)=5x\frac{6}{55}=\frac{6}{11}\)
\(A=\frac{5}{11x16}+\frac{5}{16x21}+\frac{5}{21x26}+....+\frac{5}{61x66}\)
\(C=\frac{2}{3x4}+\frac{2}{4x5}+....+\frac{2}{40x41}+\frac{2}{41x42}\)
Ai nhanh mk tik nha!!!
Ta có : \(C=\frac{2}{3.4}+\frac{2}{4.5}+\frac{2}{5.6}+......+\frac{2}{41.42}\)
\(C=2\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+.....+\frac{1}{41.42}\right)\)
\(C=2\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....+\frac{1}{41}-\frac{1}{42}\right)\)
\(C=2\left(\frac{1}{3}-\frac{1}{42}\right)\)
\(C=2.\frac{13}{42}=\frac{13}{21}\)
Các bạn chỉ cần trả lời câu C thôi nha!!!
Ta có : \(A=\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.26}+......+\frac{5}{61.66}\)
\(\Rightarrow A=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+.......+\frac{1}{61}-\frac{1}{66}\)
\(\Rightarrow A=\frac{1}{11}-\frac{1}{66}\)
\(\Rightarrow A=\frac{5}{66}\)
Tính :
a) \(\frac{2^{12}x3^5-4^6x9^2}{\left(2^2x3\right)^6+8^4x3^5}\)
b) \(\frac{1}{9x10}\)\(-\)\(\frac{1}{8x9}\)\(-\)\(\frac{1}{7x8}\)\(-\)\(\frac{1}{6x7}\)\(-\)\(\frac{1}{5x6}\)\(-\)\(\frac{1}{4x5}\)\(-\)\(\frac{1}{3x4}\)\(-\)\(\frac{1}{2x3}\)\(-\)\(\frac{1}{1x2}\)
c) \(\frac{1}{2}:\left(-1\frac{1}{2}\right):1\frac{1}{3}:\left(-1\frac{1}{4}\right):1\frac{1}{5}:\left(-1\frac{1}{6}\right):.....:\left(-1\frac{1}{100}\right)\)
Làm đc phần nào thì gúp mk với . ToT
a) \(\frac{2^{12}x3^5-4^6.9^2}{\left(2^2x3\right)^6+8^4x3^5}=\frac{2^{12}x3^5+\left(2^2\right)^6x\left(3^2\right)^2}{2^{12}x3^6+\left(2^3\right)^4x3^5}\)
\(=\frac{2^{12}x3^5-2^{12}x3^4}{2^{12}x3^6+2^{12}x3^5}=\frac{2^{12}x3^4x\left(3-1\right)}{2^{12}x3^5x\left(3+1\right)}\)
\(=\frac{2}{3.4}=\frac{1}{3.2}=\frac{1}{6}\)
b) \(\frac{1}{9x10}-\frac{1}{8x9}-\frac{1}{7x8}-\frac{1}{6x7}-\frac{1}{5x6}-\frac{1}{4x5}-\frac{1}{3x4}-\frac{1}{2x3}-\frac{1}{1x2}\)
\(=-\left(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}+\frac{1}{7x8}+\frac{1}{8x9}+\frac{1}{9x10}\right)\)
\(=-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=-\left(1-\frac{1}{10}\right)\)
\(=\frac{-9}{10}\)
sorry bn nha! mk ko bk lm phần c
Đặng Thị Dung cả 2 phần bạn CÔNG CHÚA ÔRI làm sai hết rồi. Nếu muốn biết sai ở đâu thì kb rồi nhắn tin mk chỉ cho
c,\(\frac{1}{2}\div\left(-1\frac{1}{2}\right)\div1\frac{1}{3}:\left(-1\frac{1}{4}\right)\div...\div1\frac{1}{99}\div\left(-1\frac{1}{100}\right)\)
\(=\frac{1}{2}\div\left(-\frac{3}{2}\right)\div\frac{4}{3}\div\left(-\frac{5}{4}\right)\div...\div\frac{100}{99}\div\left(-\frac{101}{100}\right)\)
\(=\frac{1}{2}\times\left(-\frac{2}{3}\right)\times\frac{3}{4}\times...\times\left(-\frac{100}{101}\right)\)
=\(=\frac{1.\left(-2\right).3.....\left(-100\right)}{2.3.4.....101}=\frac{1}{101}\)
a, \(\frac{1}{5x6}+\frac{1}{6x7}+\frac{1}{7x8}+\frac{1}{8x9}+\frac{1}{9x10}\)
b ,\(\frac{2}{10x12}+\frac{2}{12x14}+\frac{2}{14x16}+.........+\frac{2}{998x1000}\)
.c, \(\frac{4}{1x2}+\frac{4}{2x3}+\frac{4}{3x4}+........+\frac{4}{69x90}\)
Các bạn giúp mình nhé !
a) \(\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\)
\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)
\(=\frac{1}{5}-\frac{1}{10}\)
\(=\frac{1}{10}\)
b) \(\frac{2}{10.12}+\frac{2}{12.14}+\frac{2}{14.16}+...+\frac{2}{998.1000}\)
\(=\frac{1}{10}-\frac{1}{12}+\frac{1}{12}-\frac{1}{14}+\frac{1}{14}-\frac{1}{16}+...+\frac{1}{998}-\frac{1}{1000}\)
\(=\frac{1}{10}-\frac{1}{1000}\)
\(=\frac{99}{1000}\)
c) \(\frac{4}{1.2}+\frac{4}{2.3}+\frac{4}{3.4}+...+\frac{4}{69.90}\)
\(=4.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{89.90}\right)\)
\(=4.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{89}-\frac{1}{90}\right)\)
\(=4.\left(1-\frac{1}{90}\right)\)
\(=4.\frac{89}{90}\)
\(=\frac{178}{45}\)
_Chúc bạn học tốt_
a) 1/10
b) ............
c)............
Mình giúp rồi t.i.c.k mình :v
Tính nhanh:
a.
\(\frac{16x18-6}{16x17+10}\)
b.
\(\frac{3}{3x4}+\frac{3}{4x5}+\frac{3}{5x6}+\frac{3}{6x7}+\frac{3}{7x8}+\frac{3}{8x9}\)
trình bày ra cho mình nhé!
Tìm \(X\), biết :
\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+.....+\frac{1}{Xx\left(x+1\right)}=\frac{499}{500}\)
Ai giúp mk cho 5 tick
Ta có: 1/1x2 + 1/2x3 + 1/3x4 +...+ 1/X x (X + 1) = 499/500
=> 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 +...+ 1/X - 1/(X + 1) = 499/500
=> 1 - 1/(X + 1) = 499/500
=> 1/(X + 1) = 1 - 499/500
=> 1/(X + 1) = 1/500
=> X + 1 = 500
=> X = 500 - 1
=> X = 499
Đáp số: X = 499