y x ( 26 + 327 ) = 327 x 7 + 26 x 7 

y x 353  = 2471

  y = 2471 : 353 

  y = 7

y x (25 + 327) = 327 x 7 + 26 x 7

         y x 352 = (327 + 26) x 7

        y x 352 = 353 x 7

         y x 352 = 2471

                  y = 2471 : 352

                 y = 2471/352

đúng thì ủng hộ vs

sorry tính lộn

y x (26 + 327) = 327 x 7 + 26 x 7

         y x 353 = 2471

                 y = 2471 : 353 

                 y  = 7

bài kia lộn nha

1000-345+345:y= 655 +345 :5

ko biết

y x ( 26 + 327 ) = 327 x 7 + 26 x 7

y x 353 = ( 327 + 26 ) x 7

y x 353 = 353 x 7

y x 353 = 2472

y = 2471 : 353

y = 7

y.(233+327)=327.99+99.233

<=>y.(233+327)=99.(233+327)

=>y=99

y x ( 233 + 327 ) = 327 x 99 + 99 x 233

y x ( 233 + 327 ) = 99 x ( 327 + 233 )

Suy ra y = 99

~ Chúc bạn hok tốt ~

327y-27y=8100

300y=8100

y=27

327xy là một số hay tích vậy?mik sẽ làm sau khi bạn trả lời.

327*y-27*y=8100

y*(327-27)=8100

y*300=8100

y=8100:300

y=27

\(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)+\frac{x+329}{5}=0\)

\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

(x + 329) . (1/327 + 1/326 + 1/325 + 1/324 + 1/5) = 0

1/327 + 1/326 + 1/325 + 1/324 + 1/5 khác 0 

< = > x + 329 = 0

x=  -329 

Sửa đề: Tìm x \(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+349}{5}=0\)

Bài giải

\(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+349}{5}=0\)

\(\Leftrightarrow\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+329+20}{5}=0\)

\(\Leftrightarrow\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+329}{5}+\dfrac{20}{5}=0\)

\(\Leftrightarrow\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+329}{5}+4=0\)

\(\Leftrightarrow\dfrac{x+2}{327}+1+\dfrac{x+3}{326}+1+\dfrac{x+4}{325}+1+\dfrac{x+5}{324}+1+\dfrac{x+329}{5}=0\)

\(\Leftrightarrow\dfrac{x+329}{327}+\dfrac{x+329}{326}+\dfrac{x+329}{325}+\dfrac{x+329}{324}+\dfrac{x+329}{5}=0\)

\(\Leftrightarrow\left(x+329\right)\left(\dfrac{1}{327}+\dfrac{1}{326}+\dfrac{1}{325}+\dfrac{1}{324}+\dfrac{1}{5}\right)=0\)

\(\Rightarrow x+329=0\). Do \(\dfrac{1}{327}+\dfrac{1}{326}+\dfrac{1}{325}+\dfrac{1}{324}+\dfrac{1}{5}\ne0\)

\(\Rightarrow x=-329\)