\(\frac{311}{256}\)và  \(\frac{199}{203}\)

Vì \(\frac{311}{256}>1;1>\frac{199}{203}\)nên \(\frac{311}{256}>\frac{199}{203}\)

Học tốt #

311/256>199/203

A/49/211<13/1999

B/311/256>199/203

C/26/27<96/27

CHÚC BẠN HỌC TỐT

ta có: 311>256=>311/256>1=>-311/256<-1

199<203=>199/203<1=>-199/203>-1

=>-311/256<199/203

-311/256 lớn hơn vì 

199/-203 < 1 < -311/256

de qua

`#3107.101107`

`a)`

Ta có:

\(\dfrac{2727}{3131}=\dfrac{2727\div27}{3131\div31}=\dfrac{27}{31}\)

Vì \(\dfrac{27}{31}=\dfrac{27}{31}\)

\(\Rightarrow\dfrac{27}{31}=\dfrac{2727}{3131}\)

`b)`

Ta có:

\(\dfrac{11}{31}=1-\dfrac{20}{31}=1-\dfrac{200}{310}\)

\(\dfrac{111}{311}=1-\dfrac{200}{311}\)

Vì \(\dfrac{200}{310}>\dfrac{200}{311}\)

\(\Rightarrow1-\dfrac{200}{310}< 1-\dfrac{200}{311}\)

\(\Rightarrow\dfrac{11}{31}< \dfrac{111}{311}.\)

27/31 = 2727/3131

11/31 bé hơn 111/311

\(a,\\ Ta.có:\dfrac{16}{-19}< 0;\dfrac{15}{17}>0\\ \Rightarrow\dfrac{16}{-19}< \dfrac{15}{17}\\ b,\\ Ta.có:\dfrac{419}{-723}< 0;\dfrac{-697}{-313}>0\\ \Rightarrow\dfrac{419}{-723}< \dfrac{-697}{-313}\\ c,\dfrac{311}{256}>\dfrac{256}{256}=1;\dfrac{199}{293}< \dfrac{203}{203}=1\\ \Rightarrow\dfrac{311}{256}>\dfrac{199}{203}\)