a) \(-4\frac{3}{5}\cdot2\frac{4}{23}\le x\le-2\frac{3}{15}:1\frac{6}{15}\)

=> \(-\frac{23}{5}\cdot\frac{50}{23}\le x\le\frac{-33}{15}:\frac{21}{15}\)

=> \(-10\le x\le\frac{-11}{7}\)

=> \(x\in\left\{-10;-9,-8,-7,-6,-5,-4,-3,-2,-1\right\}\)

\(e,\frac{22}{15}-x=-\frac{8}{27}\)

=> \(x=\frac{22}{15}-\left[-\frac{8}{27}\right]\)

=> \(x=\frac{22}{15}+\frac{8}{27}\)

=> \(x=\frac{198}{135}+\frac{40}{135}=\frac{198+40}{135}=\frac{238}{135}\)

\(g,\left[\frac{2x}{5}-1\right]:\left[-5\right]=\frac{1}{4}\)

=> \(\left[\frac{2x}{5}-\frac{1}{1}\right]=\frac{1}{4}\cdot\left[-5\right]\)

=> \(\left[\frac{2x}{5}-\frac{5}{5}\right]=-\frac{5}{4}\)

=> \(\frac{2x-5}{5}=-\frac{5}{4}\)

=> \(2x-5=-\frac{5}{4}\cdot5=-\frac{25}{4}\)

=> \(2x=-\frac{5}{4}\)

=> \(x=-\frac{5}{8}\)

\(h,-2\frac{1}{4}x+9\frac{1}{4}=20\)

=> \(-\frac{9}{4}x+\frac{37}{4}=20\)

=> \(-\frac{9}{4}x=20-\frac{37}{4}=\frac{43}{4}\)

=> \(x=\frac{43}{4}:\left[-\frac{9}{4}\right]=\frac{43}{4}\cdot\left[-\frac{4}{9}\right]=\frac{43}{1}\cdot\left[-\frac{1}{9}\right]=-\frac{43}{9}\)

\(i,-4\frac{3}{5}\cdot2\frac{4}{23}\le x\le-2\frac{3}{5}:1\frac{6}{15}\)

=> \(-\frac{23}{5}\cdot\frac{50}{23}\le x\le-\frac{13}{5}:\frac{21}{15}\)

=> \(-\frac{1}{1}\cdot\frac{10}{1}\le x\le-\frac{13}{5}\cdot\frac{15}{21}\)

=> \(-10\le x\le-\frac{13}{1}\cdot\frac{3}{21}\)

=> \(-10\le x\le-\frac{13}{1}\cdot\frac{1}{7}\)

=> \(-10\le x\le-\frac{13}{7}\)

Đến đây tìm x

Không ghi lại đề

Ta có : \(-4\frac{3}{5}×2\frac{4}{23}\)

\(=-\frac{23}{5}×\frac{50}{23}\)

\(=-\frac{50}{5}=-10\)

\(-2\frac{3}{5}\div1\frac{6}{15}\)

\(=-\frac{13}{5}\div\frac{7}{5}\) 

\(=-\frac{13}{5}×\frac{5}{7}\)

\(=-\frac{13}{7}\)

\(\Rightarrow\) \(-10\le x\le\frac{-13}{7}\)

\(\Rightarrow\) \(\frac{-70}{7}\le x\le\frac{-13}{7}\)

\(\Rightarrow x\in\left\{\frac{-70}{7};\frac{-69}{7};...;-2;\frac{-13}{7}\right\}\)

Vậy...

Câu 1,

x+y=-1/3 ; y+z=5/4 ; x+z= 4/3

=> 2(x+y+z)=9/4

=> x+y+z=9/8

Ta lại có: x+y=-1/3

=> z=9/8 -(-1/3)=35/24

Ta lại có: z+y=5/4

=> y=-5/24

=> x=.....

Câu 2:

\(-4\le x\le-\frac{11}{18}\)