x=-1               

x=-1                                 

x = -1

ai tk mk

mk tk lại

hứa luôn

thank nhiều

x/3 = 3/4

=> x/12 = 9/12

=> x = 9

\(\frac{5}{8}-\frac{x}{3}=\frac{-1}{8}\)

\(\frac{x}{3}=\frac{3}{4}\)

\(x\div3=\frac{3}{4}\)

\(x=\frac{9}{4}\)

Vậy \(x=\frac{9}{4}\)

\(\frac{7}{9}-\frac{4}{x}=\frac{5}{18}\)

\(\frac{4}{x}=\frac{1}{2}\)

\(4\div x=\frac{1}{2}\)

\(x=8\)

Vậy \(x=8\)

Ap dung t/c day ti so bang nhau

ta co x+1/9=x+2/8=x+3/7=x+4/6=x+1-x-2-x-3+x+4 tat ca phan 9-8-7+6 =0

suy ra x+1/9=0 suy ra x-1+0 x+-1

\(x\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)

\(\frac{9}{20}x-\frac{15}{56}=0\)

\(\frac{9}{20}x=\frac{15}{56}\)

\(x=\frac{25}{42}\)

\(x\left[\frac{1}{4}+\frac{1}{5}\right]-\left[\frac{1}{7}+\frac{1}{8}\right]\) = \(0\)

\(\frac{9}{20}x-\frac{15}{56}\)= \(0\)

\(\frac{9}{20}x-\frac{15}{56}\)

\(x=\frac{25}{42}\)

Theo đầu bài ta có:
\(\frac{x-7}{7}+\frac{x-7}{8}=\frac{15}{56}\)
\(\Rightarrow\left(x-7\right)\cdot\frac{1}{7}+\left(x-7\right)\cdot\frac{1}{8}=\frac{15}{56}\)
\(\Rightarrow\left(x-7\right)\cdot\left(\frac{1}{7}+\frac{1}{8}\right)=\frac{15}{56}\)
\(\Rightarrow\left(x-7\right)\cdot\frac{15}{56}=\frac{15}{56}\)
\(\Rightarrow x-7=1\)
\(\Rightarrow x=8\)

\(\frac{1}{2}\left(x+1\right):\frac{3}{7}=\frac{32}{135}\)

\(\frac{1}{2}\left(x+1\right)=\frac{32}{135}.\frac{3}{7}\)

\(\frac{1}{2}\left(x+1\right)=\frac{32}{315}\)

\(x+1=\frac{32}{315}:\frac{1}{2}\)

\(x+1=\frac{64}{315}\)

\(x=\frac{64}{315}-1=-\frac{251}{315}\)

khi x>0, ta có

x - 38/7*x - 3/4 = 2*x + (-8/7)

-45/7*x=-11/28

x=-11/180( ko thoả )

khi x<0 có

-x -38/7x - 3/4 = -2x -8/7

bạn​ tự​ giải​ nhé​ rồi​ ktra dđiều​ kiện​ nhé !

\(\frac{7+x}{8}=\frac{x-10}{3}\)

\(\Leftrightarrow3\left(7+x\right)=8\left(x-10\right)\)

\(\Leftrightarrow21+3x=8x-80\)

\(\Leftrightarrow3x-8x=-80-21\)

\(\Leftrightarrow-5x=-101\)

\(\Leftrightarrow x=\frac{101}{5}\)

\(\Rightarrow3\left(7+x\right)=8\left(x-10\right)\)

\(\Rightarrow21+3x=8x-80\)

\(\Rightarrow5x=101\)

\(\Rightarrow x=\frac{101}{5}\)

\(\frac{7+x}{8}=\frac{x-10}{3}\)

\(\Rightarrow3\left(7+x\right)=8\left(x-10\right)\)

\(21+3x=8x-80\)

\(3x-8x=-80-21\)

\(-5x=-101\)

\(\Rightarrow x=20.2\)

Vậy \(x=20.2\)