1/2+1/4+1/16+.....+1/100000
tinh cac tong sau 1 cach hop li
Những câu hỏi liên quan
Tinh cac tong sau day mot cach hop li:
a) A= 1+ 5+ 52+ 53+........+ 51998
b) B= 1+ 4+ 42 + .................+ 4 n
Ta có : a) A= 1+ 5+ 52+ 53+........+ 51998
=> 5A = 5+ 52+ 53+........+ 51999
=> 5A - A = 51999 - 1
=> 4A = 51999 - 1
\(\Rightarrow A=\frac{5^{1999}-1}{4}\)
b) Ta có : b) B= 1+ 4+ 42 + ...... + 4n
=> 4B = 4 + 42 + 43 + ...... + 4n + 1
=> 4B - B = 4n + 1 - 1
=> 3B = 4n + 1 - 1
=> \(B=\frac{4^{n+1}-1}{3}\)
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tinh cac tong sau bang cach thuan tiện nhat P=1\2+1\4+1\8+1\16+...+1\256
P=1/2+1/4+...+1/256
2P=2.(1/2+1/4+...+1/256)
2P-P=(1+1/2+...+1/128)-(1/2+1/4+...+1/256)
P= 1- 1/256
P= 255/256
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Tinh tong sau bang cach hop li nhat: (1+3+5+...+99)-(2+4+6+...+100)
Tinh bang cach hop li
1/2+1/4+1/8+1/16+1/32
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)
=> \(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
=> \(2A-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\right)\)
=> \(A=1-\frac{1}{32}=\frac{31}{32}\)
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dat dau ngoac 1 cach thich hop nhat de tinh cac tong dai so sau :
a, 834 - 268 +2365 - 1834
b, 13 - 12 + 11 + 10 - 9 +8 -7 - 6 +5 - 4 +3 +2 - 1
dat dau ngoac 1 cach thich hop nhat de tinh cac tong dai so sau :
a, 834 - 268 +2365 - 1834
b, 13 - 12 + 11 + 10 - 9 +8 -7 - 6 +5 - 4 +3 +2 - 1
dat dau ngoac 1 cach thich hop nhat de tinh cac tong dai so sau :
a, 834 - 268 +2365 - 1834
b, 13 - 12 + 11 + 10 - 9 +8 -7 - 6 +5 - 4 +3 +2 - 1
thuc hien cac phep tinh sau 1 cach hop ly (3.4.2^16)^2/11.2^13.4^11-16^0
bai1.Tinh tong cua cac so nguyen am tu -1738 den -16
bai2.Tinh tong sau bang 2 cach
A=1+(-2)+3+(-4)+....+99+(-100)
bai1 tu -1738 den -16 co so cac so nguyen am la : (1738-16)/2+1=862
C1
B=1+3+5+..+99=50.(99+1)/2=50.50=2500
C=-(2+4+6+...+100)=50.(100+2)/2=50*51=-2550
A=B+C=2500-2550=-50
C2
A=1+(3-2)+(5-4)+...+(99-98)+100
=1+1+1+...+1-100
=1+49-100=-50
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