\(\frac{1+15^4+15^8+...+15^{96}+15^{100}}{1+\frac{15}{2}+\frac{15}{4}+...+\frac{15}{100}+\frac{15}{102}}\)
Rút gọn:
\(B=\frac{1+15^4+15^8+...+15^{96}+15^{100}}{\left(1+15^4+15^8+...+15^{96}+15^{100}\right)+\left(15^2+15^6+...+15^{98}+15^{102}\right)}\)
B=\(\frac{1+15^4+15^8+...+15^{96}+15^{100}}{1+15^2+15^4+...+15^{98}+15^{100}+15^{102}}\)
Tính B
llllllllllllllllllllllllllllllllllllllllllll
1=15^4+15^8+...+15^96+15^100/1+15^2+15^4+...+15^98+15^100+15^102
\(\frac{50-\frac{4}{13}+\frac{2}{15}-\frac{2}{17}}{100-\frac{8}{13}+\frac{4}{15}-\frac{4}{17}}\)
\(\frac{50-\frac{4}{13}+\frac{2}{15}-\frac{2}{17}}{100-\frac{8}{13}+\frac{4}{15}-\frac{4}{17}}\)= \(\frac{50-\frac{4}{13}+\frac{2}{15}-\frac{2}{17}}{2.\left(50-\frac{4}{13}+\frac{2}{15}-\frac{2}{17}\right)}\)= \(\frac{1}{2.1}\)=\(\frac{1}{2}\)
1+15^4+15^8+...+15^96+...+15^100
1+15^4+15^8+...+15^96+15^100+15^102
giúp mình nha mình cick cho -_-
Bai 1
đặt A = 1 + 15^4 + 15^8 + .... + 15^100
=> 15^4A = 15^4 + 15^8 + 15^12 + .... + 15^104
ta có
15^4A = 15^4 + 15^8 + 15^12 + .... + 15^100 + 15^104
-
A = 15^4 + 15^8 + 15^12 + .... + 15^100 + 1
50624A = 15^104 - 1
=> A = (15^104-1)/50624
bài 2 làm tương tự cũng đặt A và nhân A với 15^4 (bạn thông cảm mình không có nhiều thời gian)
Tính
A= \(\frac{50-\frac{4}{13}+\frac{2}{15}-\frac{2}{17}}{100-\frac{8}{13}+\frac{4}{15}-\frac{4}{17}}\)
\(=\frac{50-\frac{4}{13}+\frac{2}{15}-\frac{2}{17}}{2\left(50-\frac{4}{13}+\frac{2}{15}-\frac{2}{17}\right)}=\frac{1}{2}\)
Rút gọn:
B=\(\dfrac{1+15^4+15^8+...+15^{96}+15^{100}}{1+15^2+15^4+...+15^{98}+15^{100}+15^{102}}\)
B=\(\dfrac{1+15^4+15^8+...+15^{96}+15^{100}}{\left(1+15^4+15^8+..+15^{96}+15^{100}\right)+\left(15^2+15^6+...+15^{98}+15^{102}\right)}\)
=\(\dfrac{1+15^4+15^8+...+15^{96}+15^{100}}{\left(1+15^4+15^8+...+15^{96}+15^{100}\right)+15^2.\left(1+15^{14}+15^8+...+15^{96}+15^{100}\right)}\)
\(\dfrac{\left(1+15^4+15^8+...+15^{96}+15^{100}\right)}{\left(1+15^4+15^8+...+15^{96}+15^{100}\right)\left(1+15^2\right)}\)
=\(\dfrac{1}{1+15^2}=\dfrac{1}{226}\)
So sánh:
a) A=\(\frac{15^{16}+1}{15^{17}+1}\)và B=\(\frac{15^{15}+1}{15^{16}+1}\)
b) A=\(\frac{100^{100}+1}{100^{90}+1}\)và B=\(\frac{100^{99}+1}{100^{98}+1}\)
a) \(A=\frac{15^{16}+1}{15^{17}+1}\)và\(B=\frac{15^{15}+1}{15^{16}+1}\)
ta có \(A=\frac{15^{16}}{15^{17}}\)và\(B=\frac{15^{15}}{15^{16}}\)
ta dễ nhận thấy phần cơ số của hai phân số A và B = nhau
mà phần mũ của các lũy thừa phân số A đều lớn hơn phân số B
\(\Rightarrow\frac{15^{16}}{15^{17}}>\frac{15^{15}}{15^{16}}\)
\(\Rightarrow\frac{15^{16}+1}{15^{17}+1}>\frac{15^{15}+1}{15^{16}+1}\)
\(\Rightarrow A>B\)
\(A=\frac{15^{16}+1}{15^{17}+1}vaB=\frac{15^{15}+1}{15^{16}+1}\)
+)Ta thấy\(A=\frac{15^{16}+1}{15^{17}+1}< 1\)
\(\Rightarrow A< \frac{15^{16}+1+14}{15^{17}+1+14}=\frac{15^{16}+15}{15^{17}+15}=\frac{15.\left(15^{15}+1\right)}{15.\left(15^{15}+1\right)}=\frac{15^{15}+1}{15^{16}+1}=B\)
Vậy A<B
b)Đề sai
Chúc bạn học tốt
\(\frac{8}{15}+\frac{4}{15}+\frac{6}{15}=....nhân\frac{2}{15}\)
Gọi phần (.....) là x, ta có:
\(\frac{8}{15}+\frac{4}{15}+\frac{6}{15}=x\cdot\frac{2}{15}\)
\(\Rightarrow\frac{18}{15}=x\cdot\frac{2}{15}\)
\(\Rightarrow x\cdot\frac{2}{15}=\frac{18}{15}\)
\(\Rightarrow x=\frac{18}{15}:\frac{2}{25}\)
\(\Rightarrow x=9\)
Vậy x=9.