404 + 150 = 150 +.....
112 + 75 =.....+ 112
180 +.....= 371 + 180
M=20/112+20/180+20/520+20/832 = ?
A =( \(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...\frac{112}{62.69}\)): ( \(\frac{-5}{9.13}-\frac{-7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\)) = ?
Tính :
a) - 23 . 75 - 25 . 23 - 15 . 23
b) 150 - ( 150 . 2 + 180 . 3 + 180 . 2 : 3 )
c) 24 . 33 . [ - 500 - ( - 125 - 35 . 7 ) ]
d) - 101 - 103 - 105 - ..... - 197 - 199
Giúp mih với !! HUHU
A = (\(\frac{112}{13.20}+\frac{112}{20.27}+\frac{112}{27.34}+...+\frac{112}{62.69}\)) : \(\frac{-5}{9.13}-\frac{-7}{9.25}+\frac{-13}{19.25}+\frac{-31}{19.69}\))
Cố gắng giúp mik với nhé
Trên nửa mặt phẳng có bờ chứa tia OAvẽ góc AOB = 180 độ , AOC = 112 độ ,. tính BOC
Tính :
a) - 23 . 75 - 25 . 23 - 15 . 23
b) 150 - ( 150 . 2 + 180 . 3 + 180 . 2 : 3 )
c) 24 . 33 . [ - 500 - ( - 125 - 35 . 7 ) ]
d) - 101 - 103 - 105 - ..... - 197 - 199
GIÚP MÌNH VỚI ! HUHU !!!!
a,=23(-75-25)-15.8
=23.(-100)-120
=-100.(23+12)
=-100.45=-4500
b,=150-(300+540+130)
=150-960=-810
a) - 23 . 75 - 25 . 23 - 15 . 23
= - 23 . 75 - 25 . 23 - 15 . 8
=-2420
b) 150 - ( 150 . 2 + 180 . 3 + 180 . 2 : 3 )
= 150 - ( 300 + 540 + 120 )
= 150 - 300 - 540 - 120
=-810
Cậu gửi nhìu câu hỏi thế thì ai mà trả lời được???
150.....170 | 180.....190 | 160.....130 |
160.....140 | 150.....150 | 180.....200 |
120.....170 | 190.....130 | 110.....140 |
Phương pháp giải:
- So sánh các chữ số cùng hàng theo thứ tự từ trái sang phải.
- Điền dấu thích hợp vào chỗ trống.
Lời giải chi tiết:
150 < 170 | 180 < 190 | 160 > 130 |
160 > 140 | 150 = 150 | 180 < 200 |
120 < 170 | 190 > 130 | 110 < 140 |
150<170 | 180<190 | 160>130 |
160>140 | 150=150 | 180<200 |
120<170 | 190>130 | 110<140 |
Tính \(A=\left(\frac{112}{13.20}+\frac{112}{20.27}+...+\frac{112}{62.69}\right)\div\)\(\left(\frac{-5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\right)\)
Ta có: \(\left(\frac{112}{13.20}+\frac{112}{20.27}+...+\frac{112}{62.69}\right)\)
=\(\left(\frac{112}{13}-\frac{112}{20}+\frac{112}{20}-\frac{112}{27}+...+\frac{112}{62}-\frac{112}{69}\right)\)
112 là tử chung
=>\(112\cdot\left(\frac{1}{13}-\frac{1}{20}+\frac{1}{20}-\frac{1}{27}+...+\frac{1}{62}-\frac{1}{69}\right)\)
Rút gọn các phân số cho nhau, ta còn:
\(112.\left(\frac{1}{13}-\frac{1}{69}\right)\)=\(112\cdot\frac{56}{897}=\frac{6272}{897}\)(1)
Ta có: \(\left(\frac{-5}{9\cdot13}-\frac{7}{9\cdot25}-\frac{13}{19\cdot25}-\frac{31}{19\cdot69}\right)\)=\(\left(-\frac{24}{325}-\frac{122}{32775}\right)\)=\(\left(-\frac{1322}{17043}\right)\)(2)
(1);(2) => \(A=\)\(\frac{6272}{897}\)\(:\left(-\frac{1322}{17043}\right)\)\(\)\(=\)\(-\frac{59584}{661}\)
C
Tìm M = \(\dfrac{20}{112}+\dfrac{20}{180}+\dfrac{20}{520}+\dfrac{20}{832}\)
\(M=\dfrac{20}{112}+\dfrac{20}{180}+\dfrac{20}{520}+\dfrac{20}{832}\)
\(M=\dfrac{20}{8.14}+\dfrac{20}{14.20}+\dfrac{20}{20.26}+\dfrac{20}{26.32}\)
\(M=\dfrac{20}{6}\left(\dfrac{6}{8.14}+\dfrac{6}{14.20}+\dfrac{6}{20.26}+\dfrac{6}{26.32}\right)\)
\(M=\dfrac{20}{6}\left(\dfrac{1}{8}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{20}+\dfrac{1}{20}-\dfrac{1}{26}+\dfrac{1}{26}-\dfrac{1}{32}\right)\)
\(M=\dfrac{20}{6}\left(\dfrac{1}{8}-\dfrac{1}{32}\right)\)
\(M=\dfrac{20}{6}.\dfrac{3}{32}\)
\(M=\dfrac{5}{16}\)
\(M=\dfrac{20}{8.14}+\dfrac{20}{14.20}+....+\dfrac{20}{26.32}\)
\(M=\dfrac{20}{6}.\left(\dfrac{1}{8}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{20}+.....+\dfrac{1}{26}-\dfrac{1}{32}\right)\)
\(M=\dfrac{20}{6}.\left(\dfrac{1}{8}-\dfrac{1}{32}\right)\)=\(\dfrac{20}{6}.\dfrac{3}{32}=\dfrac{5}{16}\)
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