=382.459149

=382.459149

Đặt A = 34/7x13 + 51/13x22 + 85/22x37 + ... + 68/37x49

\(\frac{3}{17}.A=\frac{6}{7x13}+\frac{9}{13x22}+\frac{15}{22x37}+\frac{12}{37x49}\)

\(\frac{3}{17}.A=\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{22}+\frac{1}{22}-\frac{1}{37}+\frac{1}{37}-\frac{1}{49}\)

\(\frac{3}{17}.A=\frac{1}{7}-\frac{1}{49}\)

\(\frac{3}{17}.A=\frac{6}{49}\)
\(A=\frac{6}{49}:\frac{3}{17}\)

\(A=\frac{6}{49}x\frac{17}{3}=\frac{34}{49}\)

Đặt A = 34/7x13 + 51/13x22 + 85/22x37 + 68/37x49

\(A=17x\left(\frac{2}{7x13}+\frac{3}{13x22}+\frac{5}{22x37}+\frac{4}{37x49}\right)\)

\(\frac{3}{17}xA=\frac{6}{7x13}+\frac{9}{13x22}+\frac{15}{22x37}+\frac{12}{37x49}\)

\(\frac{3}{17}xA=\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{22}+\frac{1}{22}-\frac{1}{37}+\frac{1}{37}-\frac{1}{49}\)

\(\frac{3}{17}xA=\frac{1}{7}-\frac{1}{49}\)

\(\frac{3}{17}xA=\frac{6}{49}\)

\(A=\frac{6}{49}:\frac{3}{17}\)

\(A=\frac{6}{49}x\frac{17}{3}=\frac{34}{49}\)

khó thế bạn =))) kết bạn vs mk nha

bn phải viết đề bài rõ hơn thì mới giúp dc ..đề bài này rối lắm

C. 51; 68 nha bn

\(B\left(17\right)\in\left\{17;34;51;68;85;...\right\}\)

Mà B(17) >50, <70

\(\Rightarrow B\left(17\right)\in\left\{51;68\right\}\)

Chọn C