d) \(\frac{5x+2}{6}-\frac{8x-1}{3}=\frac{4x-2}{5}-5\)

\(\Leftrightarrow\frac{5\left(5x+2\right)}{30}-\frac{10\left(8x-1\right)}{30}=\frac{6\left(4x-2\right)}{30}-\frac{150}{30}\)

\(\Leftrightarrow25x+10-80x+10=24x-12-150\)

\(\Leftrightarrow25x-80x-24x=-12-150-10-10\)

\(\Leftrightarrow-79x=-182\)

\(\Leftrightarrow x=\frac{182}{79}\).

Vậy tập nghiệm phương trình \(s=\left\{\frac{182}{79}\right\}\)

a)\(\frac{3x+2}{2}-\frac{3x+1}{6}=\frac{5}{3}+2x\)

\(\Leftrightarrow\frac{3\left(3x+2\right)}{6}-\frac{3x+1}{6}=\frac{10}{6}+\frac{12x}{6}\)

\(\Leftrightarrow9x+6-3x+1=10+12x\)

\(\Leftrightarrow9x-3x-12x=10-6-1\)

\(\Leftrightarrow-6x=3\)

\(\Leftrightarrow x=\frac{-1}{2}\).

Vậy tập nghiệm phương trình \(S=\left\{\frac{-1}{2}\right\}\)

- Bạn ưi đầu bài phần b sai à ??

\(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)

\(\Rightarrow\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\)

\(\frac{\Rightarrow1}{4}:x=-\frac{7}{20}\)

\(\Rightarrow x=\frac{1}{4}:\frac{-7}{20}\)

\(\Rightarrow x=-\frac{5}{7}\)

\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\)

\(\frac{1}{4}:x=\frac{-7}{20}\)

\(x=\frac{-28}{20}=\frac{-14}{10}=-1,4\)

Chúc bạn học tốt!!!

1/4:x=2/5-3/4

1/4:x=-7/20

x=1/4:-7/20

x=-5/7

a)\(-\frac{2}{5}+\frac{2}{3}x+\frac{1}{6}x=-\frac{4}{5}\Leftrightarrow\frac{5}{6}x=-\frac{2}{5}\Leftrightarrow x=-\frac{12}{25}\)
Vậy nghiệm là x = -12/25

b)\(\frac{3}{2}x-\frac{2}{5}-\frac{2}{3}x=-\frac{4}{15}\Leftrightarrow\frac{5}{6}x=\frac{2}{15}\Leftrightarrow x=\frac{4}{25}\)
Vậy nghiệm là x = 4/25

c)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
\(\Leftrightarrow x+1=0\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne0\right)\)\(\Leftrightarrow x=-1\)
Vậy nghiệm là x = -1
 

Cảm ơn bạnh nha. Chúc bạn buổi tối ấm =)))) <3

 a.x+30/100x=-1,1

13/10x=-1,1

x=-11/13

b. (x-1/2):1/3 +5/7=9/5/7

(x-1/2):1/3=9

x-1/2=3

x=7/2

c. -5/6-x=7/12-1/3

x=-5/6-7/12-1/3

x=-7/4

d. 3(x+3)=-15

x+3=-5

x=-8

e. (4,5-2x)(-11/7)=11/14

4,5-2x=11/14:-11/7

4,5-2x=-1/2

2x=4,5+1/2

2x=5

x=5/2

\(a,\left(4\frac{1}{2}-\frac{2}{5}x\right):1\frac{3}{4}=\frac{11}{14}\)

\(\Rightarrow\left(\frac{9}{2}-\frac{2}{5}x\right):\frac{7}{4}=\frac{11}{4}\)

\(\Rightarrow\left(\frac{9}{2}-\frac{2}{5}x\right)=\frac{11}{4}\cdot\frac{7}{4}\)

\(\Rightarrow\left(\frac{9}{2}-\frac{2}{5}x\right)=\frac{77}{16}\)

\(\Rightarrow\frac{9}{2}-\frac{2}{5}x=\frac{77}{16}\)

\(\Rightarrow-\frac{2}{5}x=\frac{77}{16}-\frac{9}{2}\)

\(\Rightarrow-\frac{2}{5}x=\frac{5}{16}\)

\(\Rightarrow x=\frac{5}{16}:\left(-\frac{2}{5}\right)\)

\(\Rightarrow x=-\frac{25}{32}\)

\(b,\frac{2}{3}\cdot x-\frac{2}{5}x=\frac{9}{3}\)

\(\Rightarrow x\left(\frac{2}{3}-\frac{2}{5}\right)=\frac{8}{3}\)

\(\Rightarrow x\cdot\frac{4}{15}=\frac{8}{3}\)

\(\Rightarrow x=\frac{8}{3}:\frac{4}{15}\)

\(\Rightarrow x=10\)

\(c,\frac{-2}{3}|x|+1\frac{1}{2}=\frac{2}{5}\)

\(\Rightarrow\frac{-2}{3}|x|+\frac{3}{2}=\frac{2}{5}\)

\(\Rightarrow\frac{-2}{3}|x|=\frac{2}{5}-\frac{3}{2}\)

\(\Rightarrow\frac{-2}{3}|x|=-\frac{11}{10}\)

\(\Rightarrow|x|=\frac{-11}{10}:\frac{-2}{3}\)

\(\Rightarrow|x|=\frac{33}{20}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{33}{20}\\x=-\frac{33}{20}\end{cases}}\)

\(d,|2x-\frac{1}{3}|+\frac{1}{6}=\frac{3}{4}\)

\(\Rightarrow|2x-\frac{1}{3}|=\frac{3}{4}-\frac{1}{6}\)

\(\Rightarrow|2x-\frac{1}{3}|=\frac{7}{12}\)

\(\Rightarrow\orbr{\begin{cases}2x-\frac{1}{3}=\frac{7}{12}\\2x-\frac{1}{3}=-\frac{7}{12}\end{cases}\Rightarrow\orbr{\begin{cases}2x=\frac{11}{12}\\2x=-\frac{1}{4}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{11}{24}\\x=-\frac{1}{8}\end{cases}}}\)

Cuối cùng cũng có 2 người trả lời !!!😅😅😅

f/ ĐKXĐ: x khác 0

\(\Leftrightarrow\frac{1}{x}+2=2x^2+x+4+\frac{2}{x}\)

\(\Leftrightarrow2x^2+x+2+\frac{1}{x}=0\)

\(\Leftrightarrow x\left(2x+1+\frac{2}{x}+\frac{1}{x^2}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\left(loại\right)\\2x+1+\frac{2x+1}{x^2}=0\end{matrix}\right.\)

\(\Rightarrow\left(2x+1\right)\left(1+\frac{1}{x^2}\right)=0\Rightarrow x=-\frac{1}{2}\)( vì 1+1/x^2>0)

a/\(\Leftrightarrow\frac{x+4}{\left(x-1\right)\left(x-2\right)}+\frac{x+1}{\left(x-1\right)\left(x-3\right)}=\frac{2x+5}{\left(x-1\right)\left(x-3\right)}\)

\(\Leftrightarrow\frac{x+4}{\left(x-1\right)\left(x-2\right)}-\frac{x+4}{\left(x-1\right)\left(x-3\right)}=0\)

\(\Leftrightarrow\left(x+4\right)\left(\frac{1}{\left(x-1\right)\left(x-2\right)}-\frac{1}{\left(x-1\right)\left(x-3\right)}\right)=0\)

\(\Rightarrow x=-4\)

b/\(\Leftrightarrow x+\frac{1}{x}=x^2+2+\frac{1}{x^2}-2\)

\(\Leftrightarrow x+\frac{1}{x}=\left(x+\frac{1}{x}\right)^2-2\)

Đặt \(x+\frac{1}{x}=y\) ta sẽ có

\(y=y^2-2\)

\(\Leftrightarrow y^2-y-2=0\)

\(\Leftrightarrow\left(y+1\right)\left(y-2\right)=0\Rightarrow\left[{}\begin{matrix}y=-1\\y=2\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x+\frac{1}{x}=-1\\x+\frac{1}{x}=2\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x^2+x+1=0\\x^2-2x+1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}\varnothing\\\left(x-1\right)^2=0\Rightarrow x=1\end{matrix}\right.\)

\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)

\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)

\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)

\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)

\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)

\(\Rightarrow-1\le x< 6\)

\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)

Bài b tương tự

bạn ơi bạn giải câu b được ko. mk ko biết làm câu b

x=3/7 nha ban !!! K TUI NHA

X=3/7:5/7-3/11:5/11+3/13:5/13

+

1/2:5/4-1/3+1/4:5/6

=3/5-3/5+3/5 + 2/5-1/3+3/10

=3/5 +  11/10

=17/10