a,3/7 +1/2-[-3]/70

=13/14 -[-3]/70

=65/70 -[-3]/70

=34/35

b,3/5+-1/25 -35/100

=14/25 - 35/100

=56 /100 -35/100

= 21/100

c ,5/12 -3/-16+3/4

=29/48 +3/4

= 29/48 +36/48

=65/48

d, 5/15 +4/-12 +1/7 -1/-6

= 1/3 +1/-3 +1/7-1/-6

=0+1/7-1/-6

= 13/42

A.\(\dfrac{3}{7}+\dfrac{1}{2}+\dfrac{\left(-3\right)}{70}\)

=\([\dfrac{30}{70}+\dfrac{\left(-3\right)}{70}]\)+\(\dfrac{1}{2}\)

= \(\dfrac{27}{70}+\dfrac{35}{70}\)

=\(\dfrac{62}{70}=\dfrac{31}{35}\)

B.\(\dfrac{3}{5}+\dfrac{-1}{25}-\dfrac{35}{100}\)

=\(\dfrac{60}{100}+\dfrac{-4}{100}-\dfrac{35}{100}\)

=\(\dfrac{60+\left(-4\right)-35}{100}\)

=\(\dfrac{21}{100}\)

C.\(\dfrac{5}{12}-\dfrac{3}{-16}+\dfrac{3}{4}\)

=\(\left(\dfrac{5}{12}+\dfrac{9}{12}\right)-\dfrac{-3}{16}\)

=\(\dfrac{7}{6}-\dfrac{-3}{16}\)

=\(\dfrac{56}{48}-\dfrac{-9}{48}\)=\(\dfrac{65}{48}\)

D.\(\dfrac{5}{15}+\dfrac{4}{-12}+\dfrac{1}{7}-\dfrac{1}{-6}\)

=\(\dfrac{1}{3}+\dfrac{1}{7}+(\dfrac{-2}{6}-\dfrac{-1}{6})\)

=\(\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{-1}{6}\)

=\((\dfrac{1}{3}+\dfrac{-1}{6})+\dfrac{1}{7}\)

=\(\dfrac{1}{6}+\dfrac{1}{7}\)=\(\dfrac{13}{42}\)

32+-1/8+1/4

257/8

\(A=\left(x+1\right)\left(x+3\right)\left(x+5\right)\left(x+7\right)+15\)

\(A=\left[\left(x+1\right)\left(x+7\right)\right]\left[\left(x+3\right)\left(x+5\right)\right]+15\)

\(A=\left(x^2+8x+7\right)\left(x^2+8x+15\right)+15\)

Đặt \(a=x^2+8x+11\)

\(\Rightarrow A=\left(a-4\right)\left(a+4\right)+15\)

\(\Leftrightarrow A=a^2-16+15\)

\(\Leftrightarrow A=a^2-1\)

Thay a vào A ( :v ) ta có :

\(A=\left(x^2+8x+11\right)^2-1\)

\(A=\left(x^2+8x+11+1\right)\left(x^2+8x+11-1\right)\)

\(A=\left(x^2+8x+12\right)\left(x^2+8x+10\right)\)

\(A=\left(x^2+2x+6x+12\right)\left(x^2+8x+10\right)\)

\(A=\left[x\left(x+2\right)+6\left(x+2\right)\right]\left(x^2+8x+10\right)\)

\(A=\left(x+6\right)\left(x+2\right)\left(x^2+8x+10\right)⋮x+6\left(đpcm\right)\)

a) 13/60

b)43/4

 \(\frac{4}{5}+\frac{-7}{15}.1,25\)

\(=\frac{4}{5}+\frac{-7}{12}\)

\(=\frac{13}{60}\)

 \(\)

\(\)

\(\)

\(\)

a)  \(\frac{4}{5}\)+\(\frac{-7}{15}\) x  \(1,25\)

= \(\frac{4}{5}\)+ \(\frac{-7}{15}\)x   \(\frac{5}{4}\)

= \(\frac{4}{5}\)+\(\frac{-7}{12}\)

= \(\frac{48}{60}\)+ \(\frac{-35}{60}\)

=  \(\frac{13}{60}\)

b \(\frac{2}{5}\)+ \(\frac{3}{5}\)x  \(\left(4\frac{1}{2}-3,25\right)\)

= \(\frac{2}{5}\)+\(\frac{3}{5}\)x \(\left(\frac{9}{2}-\frac{13}{4}\right)\)

=\(\frac{2}{5}\)+\(\frac{3}{5}\)x\(\frac{5}{4}\)

=\(\frac{2}{5}\)+\(\frac{3}{4}\)

= \(\frac{8}{20}\)+\(\frac{15}{20}\)

=\(\frac{23}{20}\)

Bài 2:a)<=>5(x+4) =125-38

<=>5(x+4)=87

<=>x+4=17,4

<=>x=17,4-4=13.4

b)<=> ( 3x – 2⁴) . 7³ = 2.7⁴

<=> (3x – 16) = 2.7⁴ : 7³

<=> (3x – 16) =2.7

<=>3x – 16 = 14

<=> 3x = 30

<=> x = 10

c)=> xϵ​
ƯC (70, 84) và x > 8
Ta có: 70 = 2. 5. 7 => ƯCLN( 70,84) = 2. 7 = 14
84 = 22. 3. 7
=> ƯC (70, 84) = Ư(14) = { 1 ;2; 7; 14 }
Vì x > 8 => x = 14

d)=>xϵ​
BCNN (12, 25, 30) và 0 < x < 500


=>BC(12,25,30)=B(300) = { 0; 300; 600; …}
Vì 0 < x < 500
=> x = 300

giup minh nha cac ban . lam duoc minh se tick cho va ket ban . cam on cac ban

minh lay cac ban day