Phân tích ra bình thường pạn ạ

5.4^15.9^9-4.3^20.8^9

5.2^9.6^19-7.2^29.27^6

       = 5.2^30.3^18-2^2.3^20.2^27

          5.2^9.2^19.3^19-7.2^29.3^18

       = 2^29.3^18(5.2-3^2)

          2^28.3^18(5.3-7.2)

       = 2^29.3^18

          2^28.3^18

       =2

Cái 4^15=2^30 là 4^15=(2^2)^15= 4^15

Những cái sau Tương tự pạn nhé

\(B=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)

   \(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

   \(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}\)

   \(=\frac{2^{29}.3^{18}.1}{2^{28}.3^{18}.1}\)

   \(=2\)

Ta có:

\(A=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{19}.3^{19}.2^9-7.2^{29}.3^{18}}\)

\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{2^{29}.3^{18}\left(2.5-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}\)

\(=\frac{2^{29}.3^{18}}{2^{28}.3^{18}}=2\)

k nha

\(5.4^{15}.9^9-4.3^{20}.8^9\)

\(=5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9\)

\(=5.2^{30}.3^{18}-2^2.3^{20}.2^{27}\)

\(=5.2^{27}.2^3.3^{18}-2^2.3^{18}.3^2.2^{27}\)

\(=\left(2^{27}.3^{18}\right)\left(5.2^3-2^2.3^2\right)\)

\(=2^{27}.3^{18}.4\)

\(=\left(3^3\right)^9.\left(3^2\right)^9.4\)

\(=27^9.9^9.4\)

\(=\left(27.9\right)^9.4\)

\(=243^9.4\)