\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)

\(=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)

\(=\frac{2^{19}.3^9+2^{18}.3^9.5}{2^{19}.3^9+2^{19}.2.3^9.3}\)

\(=\frac{2^{18}.3^9.\left(2+5\right)}{2^{19}.3^9.\left(1+6\right)}\)

\(=\frac{7}{2.7}\)

\(=\frac{1}{2}\)

3⁸.16²/12⁴.8³

= 3⁸.(2⁴)²/(2².3)⁴.(2³)³

= 3⁸.2⁸/2⁸.3⁴.2⁹

=3⁴/2⁹

=81/512

\(\frac{3^8\cdot16^2}{12^4\cdot8^3}\)

\(=\frac{3^8\cdot2^8}{3^4\cdot2^8\cdot2^9}\)

\(=\frac{81}{512}\)

\(=\frac{3^8.\left(2^4\right)^2}{\left(3.4\right)^4.\left(2^3\right)^3}=\frac{3^8.2^8}{3^4.\left(2^2\right)^4.2^9}=\frac{3^4}{2^9}=\frac{81}{512}\)

giải giùm tui đi 

a) \(\frac{4x^2}{5y^2}.\frac{5y}{6x}.\frac{3y}{2x}=\frac{4x^2.5y.3y}{5y^2.6x.2x}=1\)

b)\(\frac{\left(x-2\right)\left(x+2\right)}{3\left(x+4\right)}.\frac{x+4}{2\left(x-2\right)}=\frac{x+2}{6}\)

c) \(\frac{\left(x-6\right)\left(x+6\right)}{2\left(x+5\right)}.\frac{-3}{x-6}=\frac{-3\left(x+6\right)}{2\left(x+5\right)}\)

15^3+5.15^2-5^3 / 18^3+6.18^2-6^3

=3375+5.225-125 /5832+6.324-216

=3375+1125-125 /5832+1944-216

=4500-125 /7826-216

=4375 /7610

=875 /1522

mk ko bt viết phần nên viết phần bằng dấu gạch / nhé.mk cx ko bt đúng hay sai đâu nhé

\(\frac{-1}{12}-\left(2\frac{5}{8}-\frac{1}{3}\right)\)

\(=\frac{-1}{12}-\left(\frac{21}{8}-\frac{1}{3}\right)\)

\(=\frac{-1}{12}-\left(\frac{63}{24}-\frac{8}{24}\right)\)

\(=\frac{-1}{12}-\frac{55}{24}\)

\(=\frac{-2}{24}-\frac{55}{24}\)

\(=\frac{-19}{8}\)

=(2-4-6+8)+(10-12-14+16)+...+(2002-2004-2006+2008)+(2010-2012)

=0+0+...+0+(-2)

=-2

\(\dfrac{1}{4}-\dfrac{1}{3}+\dfrac{5}{12}\\ =\dfrac{3}{12}-\dfrac{4}{12}+\dfrac{5}{12}\\ =\dfrac{3-4+5}{12}\\ =\dfrac{4}{12}\\ =\dfrac{1}{3}\)

kết quả là 1

kết quả là 13/7 nhé

\(\frac{6}{7}+\frac{1}{7}.\frac{2}{7}+\frac{1}{7}.\frac{5}{7}=\frac{6}{7}+\frac{2}{14}+\frac{5}{14}=\frac{12}{14}+\frac{7}{14}=\frac{19}{14}\)