\(\sqrt{36}=\)
\(-\sqrt{16}=\)
\(\sqrt{\frac{9}{25}}=\)
\(\sqrt{\left(-3\right)^2}=\)
\(\sqrt{121}=\)
Hộ mình cái :):):):):)
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Giúp mik với
Tính
a)\(\frac{2}{3}\sqrt{81}-\left(\frac{-3}{4}\right).\sqrt{\frac{9}{64}}+\left(\frac{\sqrt{2}}{3}\right)^2\)
b)\(\left(-\sqrt{\frac{5}{4}}\right)^2-\sqrt{\frac{9}{4}}:\left(-4,5\right)-\sqrt{\frac{25}{16}}.\sqrt{\frac{64}{9}}\)
c)\(-2^4-\left(-2\right)^2:\left(-\sqrt{\frac{16}{121}}\right)-\left(-\sqrt{\frac{2}{3}}\right)^2:\left(-2\frac{2}{3}\right)\)
a) sqrt{9}+sqrt{4} b) sqrt{0,25}-sqrt{0,01} c) sqrt{frac{16}{25}}-sqrt{frac{1}{81}} d) 2-sqrt{0,36}2. a) sqrt{64}-sqrt{16}+sqrt{left(-3^2right)} b) sqrt{121}+sqrt{left(-5right)^2}-sqrt{9}c) sqrt{frac{9}{4}}-sqrt{frac{16}{36}}-sqrt{49} d) sqrt{left(-4right)^2}+sqrt{left(-5right)^2}-sqrt{left(-6right)^2}
Đọc tiếp
a) \(\sqrt{9}+\sqrt{4}\) b) \(\sqrt{0,25}-\sqrt{0,01}\) c) \(\sqrt{\frac{16}{25}}-\sqrt{\frac{1}{81}}\) d) \(2-\sqrt{0,36}\)
2. a) \(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3^2\right)}\) b) \(\sqrt{121}+\sqrt{\left(-5\right)^2}-\sqrt{9}\)
c) \(\sqrt{\frac{9}{4}}-\sqrt{\frac{16}{36}}-\sqrt{49}\) d) \(\sqrt{\left(-4\right)^2}+\sqrt{\left(-5\right)^2}-\sqrt{\left(-6\right)^2}\)
1. a) 3+2=5
b) 0,5-0,1=0,4
c) 4/5-1/9=31/45
d) 2-0,6=1,4
2. a) 8-4+3=7
b) 11+5-3=13
c) 3/2-4/6-7-37/6
d) 4+5-6=3
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Tính
a) \(2\sqrt{\frac{25}{16}}-3\sqrt{\frac{49}{36}}+4\sqrt{\frac{81}{64}}\)
b) \(\left(3\sqrt{2}\right)^2-\left(4\sqrt{\frac{1}{2}}\right)^2+\frac{1}{16}.\left(\sqrt{\frac{3}{4}}\right)^2\)
c) \(\frac{2}{3}\sqrt{\frac{81}{16}}-\frac{3}{4}\sqrt{\frac{64}{9}}+\frac{7}{5}.\sqrt{\frac{25}{196}}\)
a) = \(\frac{7}{2}\)
b) = \(\frac{643}{64}\)
c) = 0
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ĐỀ: THỰC HIỆN PHÉP TÍNH ( Trình bày hộ mình <3 )
a) \(\frac{\left|\left(-5\right)^3\right|^2}{27}.\frac{3}{2^3}.\frac{6^2}{\left(-5\right)^5}\)
b) \(\left(-3\right)^2+\sqrt{\frac{16}{25}-\sqrt{9}+\frac{\sqrt{81}}{\left|-3\right|}}\)
\(\sqrt{\frac{16}{36}}+\sqrt{\frac{9}{49}}+\sqrt{\frac{121}{25}}\)
= 2/3+3/7+11/5
=23/21+11/5
=346/105
Xin lỗi bn máy mình ko viết được căn
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\(\sqrt{\frac{16}{36}}+\sqrt{\frac{9}{49}}+\sqrt{\frac{121}{25}}=\frac{2}{3}+\frac{3}{7}+\frac{11}{5}=\frac{346}{105}\)
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Xem thêm câu trả lời
a) \(\frac{8^{15}.3^{16}}{4^{23}.9^8}\)
b) \(\sqrt{121}-4.\sqrt{9}+\sqrt{36}\)
c) \(\frac{2^2}{5^2}+5\frac{1}{2}.\left(4,5-2,5\right)+\frac{2^3}{-4}+\left(-2016\right)^0\)
a, \(\frac{8^{15^{ }}.3^{16}}{4^{23^{ }}.9^8}=\frac{2^{45}.3^{16}}{2^{46}.3^{16}}=\frac{2^{45}}{2^{46}}=\frac{1}{2}\)
b, \(\sqrt{121}-4.\sqrt{9}+\sqrt{36}=11-4.3+6=11-12+6=5\)
c,
\(\frac{2^5}{5^2}+5\frac{1}{2}.\left(4,5-2,5\right)+\frac{2^3}{-4}+\left(-2016\right)^0\)
\(\frac{4}{25}+\frac{11}{2}.2+\frac{8}{-4}+1=\frac{4}{25}+11+\left(-2\right)+1=\frac{4}{25}+10\)
= \(\frac{254}{25}\)
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a
\(\sqrt{25-3\sqrt{\frac{4}{3}}}\)
b\(\left(-2^3\right)+\frac{1}{2}:\frac{1}{8}-\sqrt{25}+\left|-64\right|\)
c\(\left(-2^2\right)+\sqrt{36}.2-\sqrt{9}.3+\sqrt{25}\)
1)tính kết quả:
a, A=\(2\times\sqrt{a}-3\times\sqrt{16}+5\times\sqrt{31}\)
b, B=\(\left(\sqrt{\frac{1}{16}}+\sqrt{\frac{4}{25}}\right)\div\sqrt{\frac{25}{36}}\)
c, \(\left(\sqrt{5}\right)^2-\left(2\times\sqrt{3}\right)^2+\left(4\times\sqrt{2}\right)^2\)
\(\sqrt{\frac{25}{4}}+\left(\sqrt{\frac{1}{2}}\right)^2:\left(\frac{-\sqrt{9}}{4}\right).\sqrt{\frac{16}{81}}-4^2-\left(-2\right)^3\)
\(\sqrt{\frac{25}{4}}+\left(\sqrt{\frac{1}{2}}\right)^2:\left(\frac{-\sqrt{9}}{4}\right).\sqrt{\frac{16}{81}}-4^2-\left(-2\right)^3\)
\(=\frac{5}{2}+\frac{1}{2}:\frac{-3}{4}.\frac{4}{9}-16+8\)
\(=\frac{5}{2}-\frac{8}{27}-8\)
\(=\frac{-313}{54}\)
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-9/25 nghĩa là (âm chín phần hai mươi năm ) nha bạn
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