so sánh
a: 17/18 và 15/16
b: 2015/2016 và 2018/2017
c:2015+2017/2016+2018 và 2015+2017/2016+2018
so sánh
P=2015/2016+2016/2017+2017/2018 và Q=2015+2016+2017/2016+2017+2018
Ta có:\(Q=\frac{2015+2016+2017}{2016+2017+2018}=\frac{2015}{2016+2017+2018}+\frac{2016}{2016+2017+2018}+\frac{2017}{2016+2017+2018}\)
Vì \(\hept{\begin{cases}\frac{2015}{2016}>\frac{2015}{2016+2017+2018}\\\frac{2016}{2017}>\frac{2016}{2016+2017+2018}\\\frac{2017}{2018}>\frac{2017}{2016+2017+2018}\end{cases}}\)
\(\Rightarrow\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}>\frac{2015}{2016+2017+2018}+\frac{2016}{2016+2017+2018}+\frac{2017}{2016+2017+2018}\)
\(\Rightarrow P>Q\)
Vậy P > Q
so sánh : A= 2015/2016 + 2016/2017 + 2017/2018 và B= 2015+2016+2017 / 2016+2017+2018
A=2015/2016+2016/2017+2017/2018>2015/2018+2016/2018+2017/2018
=6048/2018>1
B=2015+2016+2017/2016+2017+2018=6048/6051<1
=>A>B
so sánh : A= 2015/2016 + 2016/2017 + 2017/2018 và B= 2015+2016+2017 / 2016+2017+2018
Có: B = 2015 + 2016 + 2017/2016 + 2017 + 2018
B= 2015 / (2015 + 2016+2017) + 2016/(2016+2017+2018) + 2017/(2016 + 2017 + 2018)
vì 2015/2016 > 2015/(2016 + 2017+2018) ; 2016/2017>2016/(2016+2017+2018) ; 2017/2018 > 2017/(2016+2017+2018)
=> A>B
có ai là ARMY ko nếu là ARMY thì mọi người cày view chưa
so sánh : A= 2015/2016 + 2016/2017 + 2017/2018 và B= 2015+2016+2017 / 2016+2017+2018
A = 2015/2016 + 2016/2017 + 2017/2018 và B = (2015 + 2016 + 2017)/(2016 + 2017 + 2018)
So sánh A và B:
A=2015/2016+2016/2017+2017/2018
B=2015+2016+2017/2016+2017+2018
giúp mk nha!!!!!!!
A<B(2015/2016<2015;2016/2017<2016;2017/2018<2017)
A = 2015/2016 + 2016/2017 + 2017/2018 và B = (2015 + 2016 + 2017)/(2016 + 2017 + 2018)
so sánh nha
GIÚP MÌNH VS MAI THHI RỒI
Ta có:2015/2016>2015/2016+2017+2018
2016/2017>2016/2016+2017+2018
2017/2018>2017/2016+2017+2018-Mình áp dụng so sánh phân số cùng tử đấy.
Suy ra2015/2016+2016/2017+2017/2018>(2015+2016+2017)/(2016+2017+2018)=B
So sánh A và B :
A = 2015 . 2016 + 2017 / 2015 . 2016 + 2016
B = 2015 . 2016 + 2018 / 2015 . 2016 + 2017
Đặt 2015.2016+2016=n
suy ra A=(n+1)/n và B=(n+2)/(n+1)
Ta có A - B=(n+1)/n -(n+2)/(n+1)=((n+1)2-n(n+2))/n(n+1)=(n2+2n+1-n2-2n)/n(n+1)=1/n(n+1)
Vì A-B lớn hơn 0 nên A>B
So sánh hai phân số : A=\(\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\)và B=\(\frac{2015+2016+2017}{2016+2017+2018}\)
\(A=\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\)
\(B=\frac{2015+2016+2017}{2016+2017+2018}\)
\(B=\frac{2015}{2016+2017+2018}+\frac{2016}{2016+2017+2018}+\frac{2017}{2016+2017+2018}\)
Ta có:
\(\frac{2015}{2016}>\frac{2015}{2016+2017+2018}\)
\(\frac{2016}{2017}>\frac{2016}{2016+2017+2018}\)
\(\frac{2017}{2018}>\frac{2017}{2016+2017+2018}\)
Cộng vế theo vế, ta có:
\(\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}>\frac{2015}{2016+2017+2018}+\frac{2016}{2016+2017+2018}+\frac{2017}{2016+2017+2018}\)
\(hay\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}>\frac{2015+2016+2017}{2016+2017+2018}\)
\(\Rightarrow A>B\)
Vậy A > B