tim x biet [x-5][x+5]-x[x-10]=5
tim x biet :3/[x+2][x+5]+5[x+5][x+10]+7/[x+10][x+15]=x/[x+12][x+17]
tim x biet
3/(x+2).(x+5) + 5/(x+5).(x+10) + 7/(x+10).(x+17) = x/(x+2).(x+17)
Với x thuộc tập hợp A = -2;-5;-10;-17
tim x biet x +5 =10
Tim x biet(4x-3)-(x+5)=(x+2)-2×(x-10)
mình không biết cách làm, nhưng mình biết x = 7,5
\(4x-3-x-5-=x+2-2x+2.10\)
\(3x-8=x+2-2x+20\)
\(3x=x+10-2x+20\)
\(3x=-x+30\)
\(4x=30\)
\(x=\frac{30}{4}=7,5\)
Cam on cac b mk cx ra ket qua la 7,5
2.(x-5)-3.(x+6)=10+x
tim x biet
\(2(x-5)-3(x+6)=10+x\)
\(\Rightarrow2x-10-3x+18=10x\)
\(\Rightarrow2x-10-3x-18=10+x\)
\(\Rightarrow-x-28=10+x\)
\(\Rightarrow-x-x=10+28\)
\(\Rightarrow-2x=38\)
\(\Rightarrow x=-19\)
Vậy ..
\(2\left(x-5\right)-\left(3x+6\right)=10+x\)
\(\Rightarrow2x-10-3x-18=10+x\)
\(\Rightarrow-x-28=10+x\)
\(\Rightarrow-x=38+x\)
\(\Rightarrow-2x=38\Leftrightarrow x=-19\)
tim x biet
2.(x-5)-3.(x+6)=10+x
3(x - 5) - 3(x + 6) = 10 + x
\(\Rightarrow\) 3x - 15 - (3x + 18) = 10 + x
\(\Rightarrow\) 3x - 15 - 3x - 18 = 10 + x
\(\Rightarrow\) -3 = 10 + x
\(\Rightarrow\) x = -13
tim so nguyen x biet x+5-6+8-9+3-5+9-10=9
tim x biet (x^3+5)(x^3+10)(x^3+15)(x^3+30)<0
a, tim x€Z biet (x-6) chia het cho (x-5)
b, tim x€Z, y€Z biet (x-1).(xy-5)=5