\(x\times\left(0,1+4+2,9+2+1\right)=25,2\)

\(10\times x=25,2\)

\(x=2,52\)

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mình đang cần gấp ạ

\(x\times0,1+x:0,25+x\times2,9+x:0,5+x=25,2\\ x\times0,1+x\times4+x\times2,9+x\times2+x=25,2\\ x\times\left(0,1+4+2,9+2+1\right)=25,2\\ x\times10=25,2\\ x=2,52\)

\(x\left(0,1+4+2+1\right)=25,2\)

\(7,1x=25,2\)

\(x\approx3,55\)

36

Sao không đăng câu mới mà lại sửa vào đề luôn vậy

\(x\left(0,1+4+2+1+2,9\right)=25,2\)

\(10x=25,2\)

\(x=2,52\)

x : 10 + x : 0,25 + x : 2,19 + x : 0,5 = 25,2

x : ( 10 + 0,25 + 2,19 + 0,5) = 25,2

x : 12,94 = 25,2

x = 25,2 x 12,94 

x =326,088]

\(x\times\left(0,1+4+2,9+2+1\right)=25,2\)

\(10x=25,2\)

\(x=2,52\)

\(x\times0,1+x\times4+x\times2,9+x\times2+x=25,2\)

\(x\times\left(0,1+4+2,9+2+1\right)=25,2\)

\(x\times10=25,2\)

\(x=25,2:10\)

\(x=2,52\)

tìm x mè giải thích sao :v?

tìm X hay tính thuận tiện

\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)

\(\Leftrightarrow2x-4,36=1\)

\(\Leftrightarrow2x=5,36\)

\(\Leftrightarrow x=2,68\)

b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)

\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)

\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)

\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)

Bài 1:

a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)

\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)

\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)

\(\frac{2\cdot x-4,36}{0,125}=8\)

\(2\cdot x-4,36=8\cdot0,125\)

\(2\cdot x-4,36=1\)

\(2\cdot x=1+4,36\)

\(2\cdot x=5,36\)

\(x=\frac{5,36}{2}=2,68\)

b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)

\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)

\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)

\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)

\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)

Bài 2:

a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )

\(x+5,2=4,7\cdot3,2+0,5\)

\(x+5,2=15,54\)

\(x=15,54-5,2=10,34\)

b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)

\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)

\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)

Bài 3:

a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)

\(x\cdot\left(104,5-14,1+9,6\right)=25\)

\(x\cdot100=25\)

\(x=\frac{25}{100}=\frac{1}{4}=0,25\)

b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)

\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)

\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)

??????????????

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4/x=-y/6=0,5

4/x=-y/6=1/2

Ta có: 4/x=1/2.Suy ra:4.2=x

                                   8=x

          -y/6=1/2. Suy ra:-y.2=6

                                    -y=3

                                     y=-3 

   vậy x=8 , y=-3

4/x = -y/6 = 0,5

4/x = -y/6 = 1/2

y/-6 = 1/2

y. 2 = -6. 1

y. 2 = -6

 y = -6 : 2

  y = -3

4/x = -1/3

4. 3 = x. -1

12 = x. -1

 12 : -1 - x

  -12 = x

Vậy x = -12, y =-3

Chưa chắc đã đúng đâu, mk nghĩ vậy thôi