a)

\(\dfrac{6}{13}\cdot\dfrac{8}{7}\cdot\dfrac{-26}{3}\cdot\dfrac{-7}{8}\)

\(=\dfrac{6}{13}\cdot\dfrac{-26}{3}\cdot\dfrac{8}{7}\cdot\dfrac{-7}{8}\)

\(=-4\cdot\left(-1\right)\\ =4\)

b)

\(\dfrac{6}{11}+\dfrac{11}{3}\cdot\dfrac{3}{22}\)

\(=\dfrac{6}{11}+\dfrac{1}{2}\\ =\dfrac{12}{22}+\dfrac{11}{22}\\ =\dfrac{23}{22}\)

a)=  (6/13*-26/3)* (8/7*-7/8)

= -4*-1=4

b=6/11+1/2=(12+11)/22=23/22

a. \(\dfrac{6.8.\left(-26\right).\left(-7\right)}{13.7.3.8}=\dfrac{2.3.8.\left(-13\right).2.\left(-7\right)}{13.7.3.8}=\dfrac{4}{1}=4\)

\(b.\dfrac{6}{11}+\dfrac{11.3}{3.11.2}\)

\(=\dfrac{6}{11}+\dfrac{1}{2}=\dfrac{23}{22}\)

4/x=-y/6=0,5

4/x=-y/6=1/2

Ta có: 4/x=1/2.Suy ra:4.2=x

                                   8=x

          -y/6=1/2. Suy ra:-y.2=6

                                    -y=3

                                     y=-3 

   vậy x=8 , y=-3

4/x = -y/6 = 0,5

4/x = -y/6 = 1/2

y/-6 = 1/2

y. 2 = -6. 1

y. 2 = -6

 y = -6 : 2

  y = -3

4/x = -1/3

4. 3 = x. -1

12 = x. -1

 12 : -1 - x

  -12 = x

Vậy x = -12, y =-3

Chưa chắc đã đúng đâu, mk nghĩ vậy thôi 

a, x/4 - 3x + 11 = 5/6 - x +7x

\(\frac{44-11x}{4}=\frac{36x+5}{6}\Rightarrow\left(44-11x\right)6=4\left(36x+5\right)\)

\(\Rightarrow264-66x=144x+20\)

\(\Rightarrow-210x=-244\)

\(\Rightarrow x=\frac{122}{105}\)

b,x^2 - 2x = 0

=>x(x-2)=0

=>x=0 hoặc x-2=0

=>x=0 hoặc x=2

c, x^2 - 7x - 10 =0

đề có khi sai

Làm ơn..!!

\(3x\left(x-\frac{11}{7}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}3x=0\\x-\frac{11}{7}=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0:3\\x=0+\frac{11}{7}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0\\x=\frac{11}{7}\end{cases}}}\)

Vậy \(x=0;x=\frac{11}{7}\)

x=0,

x=1 4/7

Ta có: \(3x.\left(x-\frac{11}{7}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}3x=0\\x-\frac{11}{7}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{11}{7}\end{cases}}}\)

KL:....................