Làm như zậy bạn nhé ^_^"

Đặt :

\(A=\left(\frac{1}{1}.\frac{1}{2}+\frac{1}{2}.\frac{1}{3}+\frac{1}{3}.\frac{1}{4}+\frac{1}{4}.\frac{1}{5}+\frac{1}{5}.\frac{1}{6}\right)\)

\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{5.6}\)( mik lười viết bạn thông cảm nhé !!! )

\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{5}-\frac{1}{6}\)

\(A=\frac{1}{1}-\frac{1}{6}\)

\(A=\frac{5}{6}\)

Thay A vào biểu thức :

Ta có : \(\frac{5}{6}.10-x=0\)

=> \(\frac{25}{3}=x+0\)

=> \(x=\frac{25}{3}\)

(1/1*1/2+1/2*1/3+1/3*1/4+1/4*1/5+1/5*1/6)*10-x=0

=> (1/1.2+1/2.3+1/3.4+1/4.5+1/5.6)*10-x=0

=> (1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6)*10-x=0

=> (1-1/6)*10-x=0

=> 5/6*10-x=0

=> 25/3-x =0

=> x=0+25/3

=> x=25/3

Vậy x=25/3

đề sai đấy

( 2+ 5)*( 3- 1)+ 27/( 18- 5)- 6=7* 2+ 27/ 13- 6= 14+ 27/13- 6= 209/13- 6= 131/13.

\(A=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.....\frac{9999}{10000}\)

\(A=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}.....\frac{99.101}{100.100}\)

\(A=\frac{\left(1.2.3.....99\right).\left(3.4.5.....101\right)}{\left(2.3.4.....100\right).\left(2.3.4.....100\right)}\)

\(A=\frac{1.101}{2.100}=\frac{101}{200}\)

\(A=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}......\frac{9999}{10000}\)

\(A=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}.....\frac{99.101}{100.100}\)

\(A=\frac{1.2.3.4.....99}{2.3.4.5.....100}.\frac{3.4.5.6.....101}{2.3.4.5.....100}\)

\(A=\frac{1}{100}.\frac{101}{2}\)

\(A=\frac{101}{200}\)

\(A=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...\frac{9999}{10000}\)

\(A=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}...\frac{99.101}{100.100}\)

\(A=\frac{1.2...99}{2.3...100}.\frac{3.5...101}{2.3...100}\)

\(A=\frac{1}{100}.\frac{101}{2}\)

\(=\frac{101}{200}\)

\(B=\left(1-\frac{1}{3}\right)\left(1-\frac{1}{6}\right)\left(1-\frac{1}{10}\right)\left(1-\frac{1}{15}\right)...\left(1-\frac{1}{780}\right)\)

\(B=\frac{2}{3}.\frac{5}{6}.\frac{9}{10}.\frac{14}{15}...\frac{779}{780}\)

\(B=\frac{4}{6}.\frac{10}{12}.\frac{18}{20}....\frac{1558}{1560}\)

\(B=\frac{1.4}{2.3}.\frac{2.5}{3.4}.\frac{3.6}{4.5}...\frac{38.41}{39.40}\)

\(B=\frac{1.2.3...38}{2.3...39}.\frac{4.5...41}{3.4...40}\)

\(B=\frac{1}{39}.\frac{41}{3}\)

\(B=\frac{41}{117}\)

(1-1/3).(1-1/6).(1-1/10)...(1-1/780) (ko có dấu "...") 
Giải: (1-1/3).(1-1/6).(1-1/10)...(1-1/780) 
= 2/3 . 5/6....779/780 
= 4/6 . 10/12.....1558/1560 
= 1.4 . 2.5 .... 38.41/ 2.3 . 3. 4. .....39.40 
= ( 1.2.3....38).(4.5....41)/(2.3.4....39)(3... 
triệt tiêu xong còn 41/39.3= 41/117 
ĐS = 41/117

k cho mh nha bạn

D=2/3.5/6.9/10.....779/780

  =       

\(\left(1-\frac{1}{3}\right).\left(1-\frac{1}{6}\right).\left(1-\frac{1}{10}\right).\left(1-\frac{1}{15}\right)...\left(1-\frac{1}{780}\right).a=1\)

\(\left(\frac{2}{3}.\frac{5}{6}.\frac{9}{10}.\frac{14}{15}...\frac{779}{780}\right).a=1\)

\(\left(\frac{4}{6}.\frac{10}{12}.\frac{18}{20}.\frac{28}{30}...\frac{1558}{1560}\right).a=1\)

\(\left(\frac{1.4}{2.3}.\frac{2.5}{3.4}.\frac{3.6}{4.5}.\frac{4.7}{5.6}...\frac{38.41}{39.40}\right).a=1\)

\(\left(\frac{1.2.3.4...38}{3.4.5.6..40}.\frac{4.5.6.7...41}{2.3.4.5..39}\right).a=1\)

\(\left(\frac{2}{39.40}.\frac{40.41}{2.3}\right).a=1\)

\(\frac{41}{39.3}.a=1\)

\(\frac{41}{117}.a=1\)

\(a=1:\frac{41}{117}\)

\(a=1.\frac{117}{41}=\frac{117}{41}\)

Vậy a = 117/41

Ủng hộ mk nha ^_-

các bn giups mk đi mai mk phải nộp bài rùi

OK chờ tí nhé

câu a tách ra nha

câu b thì tính trong ngoặc rồi tách

hok tốt

...

Câu a tham khảo link này nha bn

https://olm.vn/hoi-dap/detail/186073292336.html

Giúp mk đi mà! Mk hứa sẽ cho

b.-3/2007

Cách làm:

=(-3/4).(-4/5).(-5/6).....(-2006/2007)

=-3/2007

1/2+1/3+14

= 5/6 + 14

= 89/6

Chúc bạn học tốt nhé! ^-^

=5/6+14

=89/6

89/6 nha

\(-\frac{2}{3}x+\frac{1}{5}=\frac{1}{3}\times\left(\frac{-1}{6}\right)\)

\(-\frac{2}{3}x+\frac{1}{5}=-\frac{1}{18}\)

\(-\frac{2}{3}x=-\frac{1}{18}-\frac{1}{5}\)

\(\frac{-2}{3}x=\frac{-5}{90}-\frac{18}{90}=-\frac{23}{90}\)

\(x=-\frac{23}{90}:\frac{-2}{3}\)

\(x=-\frac{23}{90}.\frac{3}{-2}=\frac{23}{60}\)

Vậy \(x=\frac{23}{60}\)