\(\frac{5.18-10.27+15.36}{10.36-20.54+30.72}\)

\(=\frac{5.18-10.27+15.36}{5.2.18.2-10.2.27.2+15.2.36.2}\)

\(=\frac{5.18-10.27+15.36}{5.8.2.2-10.27.2.2+15.36.2.2}\)

\(=\frac{1}{2.2-2.2+2.2}\)

\(=\frac{1}{2.2}=\frac{1}{4}\)

Giúp mik với

trước 5h nha

a) \(\frac{120-\left(-0,5\right).\left(-40\right).\left(-5\right).\left(-0,2\right).20.0,25}{5+10+15+...+1995}\)

\(=\frac{120-\left[\left(-0,5\right).\left(-0,2\right)\right].\left[\left(-40\right).0,25\right].\left[\left(-5\right).\left(20\right)\right]}{\left(1995+5\right).\left[\left(1995-5\right)\div5+1\right]\div2}\)

\(=\frac{120-0,1.\left(-10\right).\left(-100\right)}{2000.399\div2}\)

\(=\frac{120-100}{1000.399}\)

\(=\frac{1}{19950}\)

b) \(\frac{5.18-10.27+15.36}{10.36-20.54+30.72}\)

\(=\frac{5.18-2.5.27+3.5.36}{10.2.18-20.2.27+5.2.3.2.36}\)

\(=\frac{5.18-2.5.27+3.5.36}{20.18-20.2.27+20.3.36}\)

\(=\frac{5.\left(18-2.27+3.36\right)}{20.\left(18-2.27+3.36\right)}\)

\(=\frac{1}{4}\)

c) \(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right)\left(\frac{1}{4}-1\right)...\left(\frac{1}{1999}-1\right)\)

\(=\left(\frac{-1}{2}\right).\left(\frac{-2}{3}\right).\left(\frac{-3}{4}\right)...\left(\frac{-1998}{1999}\right)\)

\(=\frac{\left(-1\right).\left(-2\right).\left(-3\right)...\left(-1998\right)}{2.3.4...1999}\)

\(=\frac{\left(-1\right).\left(-1\right).\left(-1\right)...\left(-1\right)}{1.1.1...1999}\)

Ta có : 1998 số (-1) mà 1998 là số chẵn

Vậy tích của 1998 số (-1) = 1

\(\Rightarrow\frac{\left(-1\right).\left(-1\right).\left(-1\right)...\left(-1\right)}{1.1.1...1999}\)

\(=\frac{1}{1999}\)

Trả lời

120-(-0,5).(-40).(-5).(-0,2).20.0,25/5+10+10+1995

=120-[(-0,5).(0,2)].[(-40).0,25].[20.(-5)]/2020

=120-0,1.(-10).-100/2020

=120-101/2020

=120-101/2020

=19/2020

\(=\frac{-120+\frac{1}{2}.\left(-40\right).\left(-5\right).\frac{-1}{5}.20.\frac{1}{4}}{5+20.1+1995}\)

\(=\frac{-120+1.\left(-1\right).-5.1.5}{5+1995}\)

\(=\frac{120.-1.1.-5.1.5}{2000}\)

\(=\frac{-120.1\left(-5+5\right)}{2000}\)

\(=0\)

giúp  mik với

rut gọn ak

c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)

a.211,0465116

Sai thôi nha

\(\frac{5.18-10.27+15.36}{10.36-20.54+30.72}\)

\(=\frac{5.18-5.2.27+5.3.36}{10.36-10.2.54+10.3.72}\)

\(=\frac{5.18-5.54+5.108}{10.36-10.108+10.216}\)

\(=\frac{5.\left(18-54+108\right)}{10.\left(36-108+216\right)}\)

\(=\frac{5.72}{10.144}\)

\(=\frac{1.1}{2.2}\)

\(=\frac{1}{4}\)

Học tốt ❤⚽

\(=\frac{90-90.3+90.6}{90.4-90.12+90.24}=\frac{90.\left(1-3+6\right)}{90\left(4-12+24\right)}=\frac{4}{16}=\frac{1}{4}\)

nhầm sửa lạ nha 

tử bằng 1

 mẫu bằng 

(1/2-1/5+1/4-1/5):(3/10-1/5)=7/20:1/10=7/2

vậy 1:7/2=2/7