a,7429-(3125+429)

=7429-3125-429

=(7429-429)-3125

=7000-3125

=3875

b,\(\frac{19}{37}+\left(1-\frac{19}{37}\right)\)

=\(\frac{19}{37}+1-\frac{19}{37}\)

=\(\frac{19}{37}-\frac{19}{37}+1\)

=\(0+1\)

=\(1\)

a) 7429-(3125+429)=7429-3125-429=7429-429-3125=7000-3125=3875

b) 19/37+(1-19/37)=(19/37-19/37)+1=0+1=1

a) 7429-(3125+429)=7429-3125-429=7429-429-3125=7000-3125=3875

b) 19/37+(1-19/37)=(19/37-19/37)+1=0+1=1

a,7429-(3125+4297)

=7407-93103+4297)

=7407-7400

7

b,9/8-(17/7-3/7)+7/8

=(9/8 +7/8)-(17/7-3/7)

=2-2

=0

c,tự làm nhé..

 = 19/37 - 19/37 + 1

= 0/37 + 1

= 0/37 + 37/37

=1

1 + 19/37 - 19/37

1 + 0 = 1

19.9+9.(37+43)+9

=19.9+9.80+9

=9.(19+80+1)

=9.100

=900

`#Ya`

`= 19 × 9 + 9 × 80 + 9 × 1`

`= 9 × ( 19 + 80 + 1 )`

`= 9 × 100= 900`

`19xx9+9xx(37+43)+9`

`=9xx(19+37+43+1)`

`=9xx100=900`

a) Ta có:

\(\frac{19}{15}\)= 1+ \(\frac{4}{15}\).

\(\frac{15}{11}\)= 1+ \(\frac{4}{11}\).

Vì \(\frac{4}{15}\)< \(\frac{4}{11}\).

=> 1+ \(\frac{4}{15}\)< 1+ \(\frac{4}{11}\).

=> \(\frac{19}{15}\)< \(\frac{15}{11}\).

a) 19/37 + (1 - 19/37)

= (19/37  - 19/37) + 1

=  0 + 1 = 1

b) 15,27 - 4,13 - 1,14

= 15,27 - ( 4,13 + 1,14)

= 15,27 - 5,27

= 10

c) 60 - 13,75 - 26,25

= 60 - ( 13,75 + 26,25)

= 60 - 40

= 20

a) 19/37 + ( 1 - 19/37 )

= ( 19/37 - 19/37 ) + 1

= 0 + 1

= 1

b) 15,27 - 4,13 - 1,14

= 15,27 - ( 4,13 + 1,14 )

= 15,27 - 5,27

= 10

c) 60 - 13,75 - 26,25

= 60 - ( 13,75 + 26,25 )

= 60 - 40

= 20

a) \(\frac{19}{37}+\left(1-\frac{19}{39}\right)\)

\(=\left(\frac{19}{37}-\frac{19}{37}\right)+1\)

\(=1\)

b) 15.27 - 4.13 - 1.14

= 15.27 - ( 4.13 + 1.14 )

= 15.27 - 5.27

= 10

c) 60 - 13.75 - 26.25

= 60 - ( 13.75 + 26.25 )

= 60 - 40

= 20

19/37+1-19/37

=(19/37-19/37)+1

=0+1

=1

9/8-(17/7-3/7)+7/8

=(9/8+7/8)-(17/7-3/7)

=2-2

=0

1/2+3/4+1/2

=(1/2+1/2)+3/4

=1+3/4

=7/4

19/37 + 1 - 19/37 = (19/37 - 19/37) + 1 = 1

9/8 - (17/7 - 3/7) + 7/8 = (9/8 + 7/8) - (17/7 - 3/7) = 16/8 - 14/7 = 2 - 2 = 0

1/2 + 3/4 + 1/2 = (1/2 + 1/2) + 3/4 = 1 + 3/4 = 7/4

a, 19/37+1-19/37

= (19/37-19/37)+1

=1

b, 9/8- (17/7-3/7)+7/8

= (9/8+7/8) - (17/7-3/7)

=16/8 - 14/7

= 2 - 2

=0

c, 1/2+3/4+1/2

= (1/2+1/2)+3/4

=1+3/4

=7/4

\(\frac{1919}{2323}.\frac{4646}{7474}.\frac{37}{19}\)

\(=\frac{19}{23}.\frac{23}{37}.\frac{37}{19}\)

\(=\frac{19.23.37}{23.37.19}\)

\(=1\)

_Chúc bạn học tốt_

ta có:

 \(\frac{1919}{2323}=\frac{19}{23}\)

\(\frac{4646}{7474}=\frac{46}{74}\)

=> \(\frac{1919}{2323}\cdot\frac{4646}{7474}.\frac{37}{19}=\frac{19}{23}\cdot\frac{46}{74}\cdot\frac{37}{19}\)= \(\frac{19}{23}\cdot\frac{2\cdot23}{37\cdot2}\cdot\frac{37}{19}\)= 1

= 1 nhé bạn