3^x+2+4.3^x+1=7.3^6
tìm x
3^(x+2)+4.3^(x+1)=7.3^6
3x+2 + 4.3x+1 = 7.36
3x+1.(3 + 4) = 7.36
3x+1.7 = 7.36
=> 3x+1 = 36
=> x + 1 = 6
=> x = 5
3 mũ x + 2 + 4.3 mũ x+ 1= 7.3 mũ 6
viết thế này thánh hiểu
3^x + 2 + 4.3 +1 = 7.3^6
3^x + 2 + 12 + 1 = 21^6
3^x + 15 = 21^6
ko làm được nữa thì hịu
Bài 6: 1) 3^x+2+4.3^x+1=7.3^6 2)5^x+4-3.5^x+3=2.5^11 3)4^x+3-3.4^x+1=13.4^11
Lời giải:
1.
$3^{x+2}+4.3^{x+1}=7.3^6$
$3^{x+1}.3+4.3^{x+1}=7.3^6$
$3^{x+1}(3+4)=7.3^6$
$3^{x+1}.7=7.3^6$
$\Rightarrow 3^{x+1}=3^6$
$\Rightarrow x+1=6$
$\Rightarrow x=5$
2.
$5^{x+4}-3.5^{x+3}=2.5^{11}$
$5^{x+3}.5-3.5^{x+3}=2.5^{11}$
$5^{x+3}(5-3)=2.5^{11}$
$2.5^{x+3}=2.5^{11}$
$\Rightarrow 5^{x+3}=5^{11}$
$\Rightarrow x+3=11$
$\Rightarrow x=8$
3.
$4^{x+3}-3.4^{x+1}=13.4^{11}$
$4^{x+1}.4^2-3.4^{x+1}=13.4^{11}$
$4^{x+1}.16-3.4^{x+1}=13.4^{11}$
$13.4^{x+1}=13.4^{11}$
$\Rightarrow 4^{x+1}=4^{11}$
$\Rightarrow x+1=11$
$\Rightarrow x=10$
3x+2+4.3x+1=7.36
Ta có: 3x+2+4.3x+1=7.36
=> 3x + 1.(3 + 4) = 7.36
=> 3x + 1 . 7 = 7.36
=> 3x + 1 = 36
=> x + 1 = 6
=> x = 5
3.3x+1 + 4.3x+1 = 7.36
3x+1(3 +4) = 7.36
x+1 = 6
x = 5
tìm x bt:
a) 3^x+2-4.3^x+1=7.3^6
b) (-6)^2x+2=1/36
Tìm x,biết
A) (-3)^2x=9^5
B) 9.5^ x-3=6.5^6+3.5^6
C) 5^x+4-3.5^x+3=5^11.2
D) 3^x+2+4.3^x+1=7.3^6
E) 5^x+3=10^5.6^3:4^4.3^3
Tìm số nguyên x biết
3x+2+4.3x+1=7.36
Tìm x thuộc Z, biết:
\(3^{x+2}+4.3^{x+1}=7.3^6\)
\(3.5^{x+2}+4.5^{x-3}=19.5^{10}\)
Mình làm câu đầu tiên.Câu thứ 2 tương tự nhé bạn.
3^x ( 3^2 + 4x3)=7x3^6
3^x = 7x3^6: 21 = 3^5
=> x=5
tìm số nguyên x
3x+2+4.3x+1=7.3
\(3^{x+2}+4.3^{x+1}=7.3\)
\(\Leftrightarrow3^x\left(3^2+4.3\right)=21\)
\(\Leftrightarrow3^x.21=21\)
\(\Leftrightarrow3^x=1\Leftrightarrow x=0\)
\(3^{x+2}+4.3^{x+1}=7.3\)
\(\Leftrightarrow3^{x+2}+4.3^{x+1}=21\)
\(\Leftrightarrow3^x\left(3^2+4.3\right)=21\)
\(\Leftrightarrow3^x.21=21\Leftrightarrow3^x=1\)
\(\Leftrightarrow x=0\)