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Lưu Nguyễn Hà An
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Nguyễn Thị Hà Chi
6 tháng 1 lúc 20:00

mình cũng có sở thichs giống bạn đã chia sẻ

Ma Trần Viên Nguyên
23 tháng 1 lúc 21:46

Mình thì cũng thích olm với cô Thương Hoài vì cô giảng rất dễ hiểu và còn dễ làm nữa.

Thư gửi cô Nguyễn Thị Thương Hoài:

#Cảm ơn cô Hoài đã giúp em học tập tiến bộ hơn ạ!#

Darya Dutes
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Cô làm rồi em nhá làm theo đúng cách của tiểu học luôn em nha, cảm ơn em đã tin tưởng và yêu thương olm, chúc em học tốt. 

https://olm.vn/cau-hoi/cho-phan-so-ab-rut-gon-ab-ta-duoc-phan-so-la-37-neu-dem-tu-so-cua-phan-so-da-cho-cong-voi-25-va-giu-nguyen-mau-so-thi-duoc-phan-so-moi-sau-khi-r.8121397970933

Darya Dutes
13 tháng 7 2023 lúc 9:17

Vâng e cảm ơn cô cô thật vui tính, hii

Darya Dutes
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Bài 8: Trong 1 giờ hai người cùng làm được: 1 : 5 = \(\dfrac{1}{5}\) (công việc)

         Trong 3 giờ hai người cùng làm được: \(\dfrac{1}{5}\) \(\times\) 3 = \(\dfrac{3}{5}\) (công việc)

          Trong 6 giờ người thứ hai làm một mình được:

                                1 - \(\dfrac{3}{5}\) = \(\dfrac{2}{5}\) (công việc)

          Trong 1 giờ người thứ hai làm một mình được:

                                \(\dfrac{2}{5}\): 6 = \(\dfrac{1}{15}\) (công việc)

         Người thứ thợ thứ hai làm một mình xong công việc sau:

                               1 : \(\dfrac{1}{15}\) = 15 (giờ)

            Đáp số: 15 giờ 

Phạm Quang Chính
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6a01dd_nguyenphuonghoa.
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\(\dfrac{x}{9}\) < \(\dfrac{4}{7}\) < \(x\) + \(\dfrac{1}{9}\)

\(\dfrac{7x}{63}\) < \(\dfrac{36}{63}\) < \(\dfrac{63x}{63}\) + \(\dfrac{7}{63}\)

7\(x\) < 36 < 63\(x\) + 7

\(\left\{{}\begin{matrix}7x< 36\\63x+7>36\end{matrix}\right.\)\(\left\{{}\begin{matrix}x< \dfrac{36}{7}\\63x>36-7\end{matrix}\right.\)\(\left\{{}\begin{matrix}x< \dfrac{36}{7}\\63x>29\end{matrix}\right.\)\(\left\{{}\begin{matrix}x< \dfrac{36}{7}\\x>\dfrac{29}{63}\end{matrix}\right.\)

\(\dfrac{29}{63}\)<  \(x\) < \(\dfrac{36}{7}\) vì \(x\in\) Z nên \(x\in\) { 1; 2; 3; 4; 5}

⇒ \(\dfrac{x}{9}\) = \(\dfrac{1}{9}\)\(\dfrac{2}{9}\)\(\dfrac{3}{9}\)\(\dfrac{4}{9}\);\(\dfrac{5}{9}\)

 

 

6a01dd_nguyenphuonghoa.
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Nguyễn Xuân Thành
9 tháng 8 2023 lúc 20:47

\(\dfrac{x}{9}< \dfrac{4}{7}< \dfrac{x+1}{9}\)

=>\(\dfrac{7x}{63}< \dfrac{36}{63}< \dfrac{7x+7}{63}\)

\(\Rightarrow7x< 36< 7x+7\)

\(\Rightarrow x< \dfrac{36}{7}< x+1\)

\(\Rightarrow x< 5\dfrac{1}{7}< x+1\)

\(\Rightarrow x=5\)

 

Nguyễn Xuân Thành
9 tháng 8 2023 lúc 20:48

tik cho mình nhé

Bùi Linh Chi
10 tháng 8 2023 lúc 5:44

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Đặng Quỳnh Chi
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Trần Đình Hoàng Quân
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Bài 1 : (4a - b).(4a + b)    = 16a2 + (-b2)

       (\(x^2y\) + 2y)(\(x^2\)y - 2y    = \(x^4\).y2 + (- 4y2)

   (\(\dfrac{3}{4}\)\(x\) + \(\dfrac{3}{5}\)y)(\(\dfrac{3}{5}\)y - \(\dfrac{3}{4}\)\(x\))     = \(\dfrac{9}{25}\)y2 + (- \(\dfrac{9}{16}\)\(x^2\))

    2; (\(x+2\))(\(x^2\) - 2\(x\) + 4)  =       \(x^3\) + 8

         (3\(x\) + 2y)(9\(x^2\) - 6\(xy\) + 4y2)   = 27\(x^3\) + 8y3

       3,  (5- 3\(x\))(25 + 15\(x\) + 9\(x^2\))      = 125 + ( -27\(x^3\))

        (\(\dfrac{1}{2}\)\(x\) - \(\dfrac{1}{5}\)y).(\(\dfrac{1}{4}\)\(x^2\) + \(\dfrac{1}{10}\)\(xy\) + \(\dfrac{1}{25}\)y2 =  \(\dfrac{1}{8}\)\(x^3\) + (-\(\dfrac{1}{125}\)y3)

Trần Đình Hoàng Quân
30 tháng 7 2023 lúc 19:58

em cảm ơn cô ạ

 

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