iTính 2/3.[1/3-(-2/5)]+3/11:(-2)^2/121
cho mk hỏi tí nhé
1*2*3*2018 - 1*2*3*.....*2017- 1*2*3*......*2017^2
1500 - 5^3 *2^3 -11 *[7^2 - 5*2^3 +8 *(11^2 -121)]
1500 - {5^3 . 2^3 - 11. [(7^1011)^2 : 7^2020 - 6 . 2^3 + 8. (11^2 - 121)]}
1. So sánh:
a) 25^50 và 2^300
b) 625^15 và 12^45
2. Tính hợp
a) -4 5/7 . 33 1/3 + 4 5/7 . 47 . 1/3
b) (3/5 + 5 2/3 ) : 121/19 + ( -5 2/3 + 2/3 ) : 121/19
c)( -1/4) . ( 6 2/11) + 3 9/11 . (-1/4)
d) 4 . ( -1/3)^3 - 2 . ( -1/2)^2 + 3. (-1/2) +1
3. Tìm x
a) GTTĐ của x - 2 = 5
b) 3x . ( x - 2/5) = 0
c) 3 ^x+2 +3^x = 270
d) 3/4 + 1/4 :x = 2/5
e) (9/5 - x)^2 = 16/25
1. So sánh
a) \(25^{50}\) và \(2^{300}\)
\(25^{50}=25^{1.50}=\left(25^1\right)^{50}=25^{50}\)
\(2^{300}=2^{6.50}=\left(2^6\right)^{50}=64^{50}\)
Vì \(25< 64\) nên \(25^{50}< 64^{50}\)
Vậy \(25^{50}< 2^{300}\)
b) \(625^{15}\) và \(12^{45}\)
\(625^{15}=625^{1.15}=\left(625^1\right)^{15}=625^{15}\)
\(12^{45}=12^{3.15}=\left(12^3\right)^{15}=1728^{15}\)
Vì \(625< 1728\) nên \(625^{15}< 1728^{15}\)
Vậy \(625^{15}< 12^{45}\)
1.So sánh
a)\(25^{50}\) và \(2^{300}\)
Ta có : \(2^{300}=\left(2^6\right)^{50}=64^{50}\)
Vì \(25^{50}< 64^{50}\) nên \(25^{50}< 2^{300}\)
b)\(625^{15}\) và \(12^{45}\)
Ta có : \(12^{45}=\left(12^3\right)^{15}=1728^{15}\)
Vì \(625^{15}< 1728^{15}\) nên \(625^{15}< 12^{45}\)
1500 - { 53 . 23 -11. [ 72 - 5 . 23 + 8.( 112 - 121)]}
1500- { 53 . 23- 11. [ 72 - 5 . 23 + 8.( 112 - 121)]}
=1500- { 53 . 23- 11. [ 72 - 5 . 23 + 8.( 121 - 121)]}
=1500- { 53 . 23- 11. [ 72 - 5 . 23 + 8.0 ]}
=1500- { 53 . 23- 11. [ 49 - 5 . 8 + 0 ]}
=1500- { 53 . 23- 11. [ 49 - 40 + 0 ]}
=1500- { 53 . 23- 11. [ 9 + 0 ]}
=1500- { 53 . 23- 11. 9 }
=1500- { 125 . 8 - 11. 9 }
=1500- { 1000 - 99 }
=1500- 901
=599
BÀI HƠI DÀI TÍ
CỐ GẮNG LÊN BẠN NHÉ
Tính : -1500 - { 53. 23 -11.[ 72-5 .23+8 (112-121)]} .(-2)
= - 1500 - { 125.8 - 11[ 49 - 5.8 + 8.(121-121) ] } . ( - 2 )
= - 1500 - (1000 - 11.9) ( - 2 )
= - 1500 - 901.( - 2 )
= - 1500 + 1802
= 302
\(\left\{1\dfrac{3}{4}-\dfrac{4}{6}\right\}:\left\{1\dfrac{1}{5}+2\dfrac{2}{5}+\dfrac{1}{5}\right\}< x< 1\dfrac{1}{5}.1\dfrac{3}{4}+3\dfrac{2}{11}:2\dfrac{3}{121}\) với x là số tự nhiên
\(\left(1\dfrac{3}{4}-\dfrac{4}{6}\right):\left(1\dfrac{1}{5}+2\dfrac{2}{5}+\dfrac{1}{5}\right)< x< 1\dfrac{1}{5}.1\dfrac{1}{4}+3\dfrac{2}{11}:2\dfrac{3}{121}\)
\(\Leftrightarrow\left(\dfrac{7}{4}-\dfrac{4}{6}\right):\left(\dfrac{6}{5}+\dfrac{12}{5}+\dfrac{1}{5}\right)< x< \dfrac{6}{5}.\dfrac{5}{4}+\dfrac{35}{11}:\dfrac{245}{121}\) \(\Leftrightarrow\left(\dfrac{21}{12}-\dfrac{8}{12}\right):\dfrac{19}{5}< x< \dfrac{3}{2}+\dfrac{35}{11}.\dfrac{121}{245}\) \(\Leftrightarrow\dfrac{13}{12}.\dfrac{5}{19}< x< \dfrac{3}{2}+\dfrac{2}{7}\) \(\Leftrightarrow\dfrac{65}{228}< x< \dfrac{21}{14}+\dfrac{4}{14}\) \(\Leftrightarrow\dfrac{65}{228}< x< \dfrac{25}{14}\) \(\Leftrightarrow x=1\)Tính giá trị biểu thức: a) 2 3 2 3 2 A 1500 5 . 2 11. 7 5.2 8. 11 121
x - 10/3 = 7/15. 3/5
x+ 3/22 = 27/121 . 11/9
1/5 : x = 1/2
3/5 + 2/5 . x = 1
Ai nhanh tick
\(x-\frac{10}{3}=\frac{7}{15}.\frac{3}{5}\)
\(x-\frac{10}{3}=\frac{7}{25}\)
\(x=\frac{7}{25}+\frac{10}{3}=\frac{271}{75}\)
Vậy x = 271/75
\(x-\frac{10}{3}\)\(=\)\(\frac{7}{15}\)\(.\)\(\frac{3}{5}\)
\(x-\frac{10}{3}\)\(=\) \(\frac{7}{25}\)
\(x\) \(=\)\(\frac{7}{25}\)\(+\)\(\frac{10}{3}\)
\(x\) \(=\) \(\frac{271}{75}\)
Trả lời:
x-10/3=7/15.3/5
x-10/3=7/25
x=10/3+7/25
x=271/75
x+3/22=27/121.11/9
x+3/22=3/11
x=3/11-3/22
x=3/22
1/5:x=1/2
x=1/5:1/2
x=1/5.2
x=2/5
3/5+2/5.x=1
2/5.x=1-3/5
2/5.x=2/5
x=2/5:2/5
x=1
các bạn giúp mình nhé !
a ; 1500 - { 5^3 . 2^3 -11 [7^2 -5 . 2^3 +8 ( 11^2 -121) ]}
B, S= 5+5^2 +5^3+5^4 +5^5+5^6 ....... 5^2012
a.
\(1500-\left\{5^3.2^3-11\left[7^2-5.2^3+8\cdot\left(11^2-121\right)\right]\right\}\)
\(=1500-\left\{\left(5.2\right)^3-11\left[9+8\left(11^2-11^2\right)\right]\right\}\)
\(=1500-\left\{10^3-11.9\right\}\)
\(=1500-901=599\)
b/
\(S=5+5^2+5^3+...+5^{2012}\)
\(5S=5^2+5^3+5^4+...+5^{2013}\)
\(4S=5S-S=5^{2013}-5\)
\(S=\frac{5^{2013}-5}{4}\)
a ; 1500 - { 5 ^ 3 . 2 ^ 3 - 11 [ 7 ^ 2 - 5 . 2 ^ 3 + 8 ( 11 ^ 2 - 121) ] }
a ; 1500 - { 5 ^ 3 . 2 ^ 3 - 11 [ 7 ^ 2 - 5 . 2 ^ 3 + 8 ( 121 - 121) ] }
a ; 1500 - [ 5 ^ 3 . 2 ^ 3 - 11 ( 7 ^ 2 - 5 . 2 ^ 3 + 8 . 0 ) ]
a ; 1500 - [ 5 ^ 3 . 2 ^ 3 - 11 ( 49 - 5 .8 + 8 . 0) ]
a ; 1500 - [ 5 ^ 3 . 2 ^ 3 - 11 ( 49 - 40 + 0 ) ]
a ; 1500 - ( 5 ^ 3 . 2 ^ 3 - 11 . 9 )
a ; 1500 - [ ( 5 . 2 ) ^ 3 - 99]
a ; 1500 - ( 10 ^ 3 - 99)
a ; 1500 - ( 1000 - 99)
a ; 1500 - 901
a = 599