bằng 1/7 nha không tên

=27/182 - 1/182 

= 26/182 

= 1/7

tổng của hai số lẻ liên tiếp là 636 . Tìm số bé hơn

Bài 1:

\(\frac{3}{7}\cdot\frac{9}{2}-\frac{1}{14}\cdot\frac{1}{13}\)=\(\frac{27}{14}-\frac{1}{14}\cdot\frac{1}{13}\)

                                          = \(\frac{1}{14}\left(27-\frac{1}{3}\right)\)

                                         = \(\frac{1}{14}\cdot\frac{350}{13}\)=\(\frac{25}{13}\)

bài 2:\(\frac{5}{9}\cdot\frac{7}{13}+\frac{5}{9}\cdot\frac{9}{13}\cdot\frac{3}{13}\)= \(\frac{5}{9}\cdot\frac{1}{13}\left(7+9\cdot\frac{3}{13}\right)\)

                                                            = \(\frac{5}{9}\cdot\frac{1}{13}\cdot\frac{94}{13}\)=\(\frac{470}{1521}\)

có j sai xin mn chỉ bảo!

\(\frac{3}{7}.\frac{9}{26}-\frac{1}{14}.\frac{1}{13}\)

\(=\frac{27}{182}-\frac{1}{182}\)

\(=\frac{1}{7}\)

\(\frac{3}{5}.\frac{13}{46}-\frac{1}{10}.\frac{16}{23}\)

\(=\frac{6}{10}.\frac{13}{46}-\frac{1}{10}.\frac{16}{23}\)

\(=\frac{1}{10}.\frac{78}{46}-\frac{1}{10}.\frac{16}{32}\)

\(=\frac{1}{10}\left(\frac{78}{46}-\frac{32}{46}\right)\)

\(=\frac{1}{10}.1=\frac{1}{10}\)

khanh sai r,câu 1 là 8/10 chứ

80/100 

100 

8/10

25

<<<<<<học tốt>>>>>>

\(\dfrac{3}{7}.\dfrac{9}{36}-\dfrac{1}{14}.\dfrac{1}{13}\)

\(=\dfrac{3.9}{7.36}-\dfrac{1.1}{14.13}\)

\(=\dfrac{3}{28}-\dfrac{1}{182}=\dfrac{37}{364}\)

3/7 . 9/36 - 1/14 . 1/13

= 3/28 - 1/182 

= 37/364

37/364

a) B = 5/16 : 0,125 - ( 9/4 - 0,6 ) * 10/11

B = 5/16 * 8 - 9/4 * 10/11 + 0,6 * 10/11

B = 5/2 - 45/22 + 3/11

B = 55/22 - 45/22 + 6/22

B = 8/11

b) \(\left(\frac{1}{2}+1\right)\left(\frac{1}{3}+1\right).....\left(\frac{1}{99}+1\right)\)

\(=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}.....\frac{100}{99}\)

\(=\frac{3.4.5.....100}{2.3.4.....99}\)

\(=\frac{\left(3.4.....99\right).100}{2\left(3.4.....99\right)}\)

\(=\frac{100}{2}\)

\(=50\)

a)B= 5/6 : 1/8 - (9/4 - 3/5 ) * 10/11

= 5/2 - 33/20 * 10/11

= 5/2 - 3/2

= 1

b) 3/2.4/3.5/4....100/99

= 3.4.5...100/2.3.4...99

=100/2

=50

\(1\frac{1}{3}\cdot1\frac{1}{8}\cdot1\frac{1}{15}\cdot1\frac{1}{24}\cdot...\cdot1\frac{1}{99}\)

\(=\frac{4}{3}\cdot\frac{9}{8}\cdot\frac{16}{15}\cdot\frac{25}{24}\cdot...\cdot\frac{100}{99}\)

\(=\frac{2.2\cdot3.3\cdot4.4\cdot5.5\cdot...\cdot10.10}{1.3\cdot2.4\cdot3.5\cdot4.6\cdot...\cdot9.11}\)

\(=\frac{2.10}{1.11}=\frac{20}{11}\)

"." = nhân

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