giúp mình với! Thanks

vì số nào nhân vs o đều bàng 0 nên x trong cả hai bài trên đều bằng 0

1, x=0

2, x=0

\(a,\frac{3\times4\times7}{12\times8\times9}\)

\(=\frac{3\times4\times7}{3\times4\times8\times9}\)

\(=\frac{7}{72}\)

\(b,\frac{4\times5\times6}{12\times10\times8}\)

\(=\frac{4\times5\times3\times2}{4\times3\times5\times2\times8}\)

\(=\frac{1}{8}\)

\(c,\frac{5\times6\times7\times9}{12\times7\times27}\)

\(=\frac{5\times6\times7\times9}{6\times2\times7\times9\times3}\)

\(=\frac{5}{6}\)

\(d,\frac{5\times6\times7}{12\times14\times15}\)

\(=\frac{5\times6\times7}{6\times2\times7\times2\times5\times3}\)

\(=\frac{1}{12}\)

a) \(\frac{3\times4\times7}{12\times8\times9}=\frac{3\times4\times7}{3\times4\times8\times9}=\frac{7}{8\times9}=\frac{7}{72}\)

b) \(\frac{4\times5\times6}{12\times10\times8}=\frac{4\times5\times6}{6\times2\times2\times5\times4\times2}=\frac{1}{2\times2\times2}=\frac{1}{8}\)

c) \(\frac{5\times6\times7\times9}{12\times7\times27}=\frac{5\times6\times9}{12\times27}=\frac{5\times6\times9}{2\times6\times3\times9}=\frac{5}{2\times3}=\frac{5}{6}\)

d) \(\frac{5\times6\times7}{12\times14\times15}=\frac{5\times6\times7}{2\times6\times2\times7\times3\times5}=\frac{1}{2\times2\times3}=\frac{1}{12}\)

a) \(\frac{3\times4\times7}{12\times8\times9}=\frac{3\times4\times7}{3\times4\times8\times9}=\frac{7}{8\times9}=\frac{7}{72}\)

b) \(\frac{4\times5\times6}{12\times10\times8}=\frac{4\times5\times6}{6\times2\times2\times5\times4\times2}=\frac{1}{2\times2\times2}=\frac{1}{8}\)

c) \(\frac{5\times6\times7\times9}{12\times7\times27}=\frac{5\times6\times9}{12\times27}=\frac{5\times6\times9}{2\times6\times3\times9}=\frac{5}{2\times3}=\frac{5}{6}\)

d) \(\frac{5\times6\times7}{12\times14\times15}=\frac{5\times6\times7}{2\times6\times2\times7\times3\times5}=\frac{1}{2\times2\times3}=\frac{1}{12}\)

\(\frac{\left(2^3\cdot5\cdot7\right)\cdot\left(5^2\cdot7^3\right)}{\left(2\cdot5\cdot7\right)^2}\)

\(=\frac{2^3\cdot5^3\cdot7^4}{2^2\cdot5^2\cdot7^2}\)

\(=2\cdot5\cdot7^2\)

\(=10\cdot49=490\)

\(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7\right)^2}\)

\(=\frac{2^3.5^3.7^4}{2^2.5^2.7^2}\)

\(=2.5.7^2\)

\(=\left(2.5\right).7^2\)

\(=10.49\)

\(=490\)

\(\frac{\left(2^3\times5\times7\right)\times\left(5^2\times7^3\right)}{\left(2\times5\times7\right)^2}=\frac{2^3\times5^3\times7^4}{2^2\times5^2\times7^2}=2\times5\times7^2=10\times49=490\)

a) 3.4.5 chia hết cho 3; và 6.7 chia hết 3. Nên tổng chia hết 3. Vậy là hợp số.

b) Hiệu chia hết 7 và 3nên là hợp số.

c) Tổng có tận cùng là 5 nên chia hết cho 5. Vậy là hợp số.

16354+67541=83895

\(=\dfrac{4}{7}\)

8 x 7 x 5 / 11 x 8 x 7 = 5 /11

\(\frac{8\times7\times5}{11\times8\times7}\)= \(\frac{8\left(bỏ8\right)\times7\left(bỏ7\right)\times5}{11\times8\left(bỏ8\right)\times7\left(bỏ7\right)}\)= \(\frac{5}{11}\)

\(\frac{8\times7\times5}{11\times8\times7}=\frac{8\times7}{8\times7}\times\frac{5}{11}=\)\(\frac{5}{11}\)

    m = 1/3-1/5+1/5-1/7+1/7-1/9+...+1/97-1/99

    m = 1/3-1/99=32/99

   Sorry chị em ko làm đc câu b vì em mới học lớp 4

   k em ha

a) \(M=\frac{2}{3\times5}+\frac{2}{5\times7}+\frac{2}{7\times9}+...+\frac{2}{97\times99}\)

\(\Rightarrow M=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\)

\(\Rightarrow M=\frac{1}{3}-\frac{1}{99}\)

\(\Rightarrow M=\frac{33}{99}-\frac{1}{99}=\frac{32}{99}\)

b)  \(N=\frac{3}{5\times7}+\frac{3}{7\times9}+\frac{3}{9\times11}+...+\frac{3}{197\times199}\)

\(\Rightarrow N=3\times\left(\frac{1}{5\times7}+\frac{1}{7\times9}+\frac{1}{9\times11}+...+\frac{1}{197\times199}\right)\)

\(\Rightarrow N=3\times\left[2\times\left(\frac{1}{5\times7}+\frac{1}{7\times9}+\frac{1}{9\times11}+...+\frac{1}{197\times199}\right)\right]\)

\(\Rightarrow N=3\times\left(\frac{2}{5\times7}+\frac{2}{7\times9}+\frac{2}{9\times11}+...+\frac{2}{197\times199}\right)\)

\(\Rightarrow N=3\times\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{197}-\frac{1}{199}\right)\)

\(\Rightarrow N=3\times\left(\frac{1}{5}-\frac{1}{199}\right)\)

\(\Rightarrow N=3\times\frac{194}{995}=\frac{582}{995}\)

----Chúc em học giỏi !----

a M=1/3-1/5+1/5-1/7+1/7-1/9+....+1/97-1/99

M=1/3-1/99

M= 33/99-1/99

M=32/99

b

N=3/2( 2/5x7+2/7x9+2/9x11+...+ 2/ 197x199)

N=3/2x(1/5-1/7+1/7-1/9+1/9-1/11+.....+ 1/197-1/199)

N=3/2x( 1/5-1/199)

N=3/2x194/995

N=291/995

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