Tìm số tự nhiên biết x ,y biet :

a [x +1] [ y - 1] = 7 

b [ 2 x +1] [ y+1] = 8

c x [y-2] = 4

d  [x+6 ] [y+3 - 12] = 2²  . [- 3 ]

TIM X BIET : (X+1)^2(X+2)+(X-1)^2(X-2)=12 .

GIUP MK NHA 

bài 1 tìm x nguyên n biết

a)n+2 : n-1

3n-5:n-2

bai 2 tim  cac so nguyen x,y biet 

(x-1).(b-2)-(ab+2)

x ( y-3)=-12

tim x biet 2^(x-1) +5^(x-2) =7/12

tìm số nguyên x biet

-2.(x+6)+6.(x-10)=8

x+5=20-(12-7)

(3x-9).(2x+6)=0

(2x+1).(3-x)=0

biet rang 1^2+2^2+3^2+....+10^2=385.Tim x biet x+10^2+12^2+14^2+...+20^2=2011+1^2+3^2+...+9^2

tim 2 so tu nhien x va y biet (x+1)x(2y-1)=12

a, Tim so tu nhien x, y biet rang 4<9/x<12/y<18

b, Tim so nguyen x, y biet rang x/2 - 2/y = 1/2

bai 1: Tim x biet

\(\hept{\begin{cases}x-y=\frac{3}{10}\\y\left(x-y\right)=-\frac{3}{50}\end{cases}}\)

bai 2: Tim x, y biet:

x+\(\left(-\frac{31}{12}\right)^2\)=\(\left(\frac{49}{12}\right)^2\)-x=y²

Bai 9: Tim x,y,z biet:

(x-1)²+(x+y)²+(xy-z)²=0