1+3+5+..........+97+99=(x+2)²

[(99-1)/2+1]*(99+1)/2=(x+2)²

2500=(x+2)*(x+2)

Vì 2500=50*50 nên x=50-2=48

1.
\(\left(\frac{3}{1\times3}+\frac{3}{3\times5}+\frac{3}{5\times7}+...+\frac{3}{97\times99}\right)-x:\frac{3}{2}=\frac{7}{3}\\ \left(\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+...+\frac{2}{97\times99}\right):\frac{3}{2}-x:\frac{3}{2}=\frac{7}{3}\\\left[\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\right)-x\right]:\frac{3}{2}=\frac{7}{3}\\ \left(1-\frac{1}{99}\right)-x=\frac{7}{3}\times\frac{3}{2}\\ \frac{98}{99}-x=\frac{7}{2}\\ x=\frac{98}{99}-\frac{7}{2}=\frac{-497}{198}\)

2.\(\frac{x}{y}=\frac{4}{3}\Rightarrow\hept{\begin{cases}x=4a\\y=3a\\x-y=4a-3a=a\end{cases}}\\ \left(x-y\right)^{2015}=5^{2015}\Rightarrow x-y=5\\ \Rightarrow a=5\Rightarrow\hept{\begin{cases}x=4\times5=20\\y=3\times5=15\end{cases}}\)

1.

 a, (x+1) + (x+3) + (x+5) +.......+(x+99) =0

\(\Rightarrow\)x+x+x+...+x(50 số hạng)  +  1+3+5+...+99=0

\(\Rightarrow\)50.x+4950=0

50.x=0-4950

50.x=(-4950)

x=(-4950):50

x=(-99)

theo công thức đã cho => 1^3+2^3+..+10^3=(1+2+3+..+10)^2 

=55^2 = (x+1)^2

=> x= 55-1=54

phần b tính ra rồi lm SCP rồi tính ra