7x - 6x² - 2

= - ( 6x² - 7x + 2)

= - ( 6x² - 3x - 4x + 2 )

= - [ 3x ( 2x - 1 ) - 2 ( 2x - 1 ) ]

= - ( 2x - 1 ) ( 3x - 2 )

~ Học tốt ~

\(7x-6x^2-2\)

\(=-\left(6x^2-7x+2\right)\)

\(=-\left(6x^2-3x-4x+2\right)\)

\(=\left[3x\left(2x-1\right)-2\left(2x-1\right)\right]\)

\(=-(2x-1)-(3x-2)\)

\(7x-6x^2-2\)

\(=\left(3x-6x^2\right)-\left(2-4x\right)\)

\(=3x\left(1-2x\right)-2\left(1-2x\right)\)

\(=\left(3x-2\right)\left(1-2x\right)\)

      \(x^4+6x^3+7x^2-6x+1\)

\(=x^4+6x^3+9x^2-2x^2-6x+1\)

\(=\left(x^2\right)^2+2.x^2.3x+\left(3x\right)^2-2\left(x^2+3x\right)+1\)

\(=\left(x^2+3x\right)^2-2\left(x^2+3x\right).1+1^2\)

\(=\left(x^2+3x-1\right)^2\)

Chúc bạn học tốt.

\(x^4+6x^3+7x^2-6x+1\)

\(=x^4+6x^3+9x^2-2x^2-6x+1\)

\(=x^2\left(x+3\right)^2-2\left(x^2+3x\right)+1\)

\(=\left(x^2+3x\right)^2-2\left(x^2+3x\right)+1=\left(x^2+3x-1\right)^2\)

https://olm.vn/hoi-dap/tim-kiem?q=Cho+%CE%94ABC+vu%C3%B4ng+t%E1%BA%A1i+A+c%C3%B3+AB+%3E+AC,+M+l%C3%A0+%C4%91i%E1%BB%83m+tu%E1%BB%B3+%C3%BD+tr%C3%AAn+BC.+Qua+M+k%E1%BA%BB+Mx+vu%C3%B4ng+g%C3%B3c+v%E1%BB%9Bi+BC+v%C3%A0+c%E1%BA%AFt+AB+t%E1%BA%A1i+I+c%E1%BA%AFt+CA+t%E1%BA%A1i+D.a.+Ch%E1%BB%A9ng+minh+%CE%94ABC+%C4%91%E1%BB%93ng+d%E1%BA%A1ng+v%E1%BB%9Bi+%CE%94MDCb.+Ch%E1%BB%A9ng+minh:+BI.BA+=+BM.BCc.+Cho+g%C3%B3c+ACB+=+60o+v%C3%A0+S%CE%94CDB+=+60+cm2.+T%C3%ADnh+S%CE%94CMAGi%C3%BAp+m%C3%ACnh+c%C3%A2u+c+v%E1%BB%9Bi&id=573451

\(7x-6x^2-2=\left(3x-6x^2\right)+\left(4x-2\right)=3x\left(1-2x\right)-2\left(1-2x\right)=\left(1-2x\right)\left(3x-2\right)\)

x^4+6x^3+7x^2–6x+1

=x^4+(6x^3–2x^2)+(9x^2–6x+1)

= x^4+2x^2(3x–1)+(3x–1)^2

=(x^2+3x–1)^2

TƯƠNG TỰ CÁC BÀI TRONG NÂNG CAO PHÁT TRIỂN 8

\(x^4-6x^3+7x^2-6x+1\)

\(=x^4+x^2+1-6x^3+6x^2-6x\)

\(=\left(x^2+1\right)^2-x^2-6x\left(x^2-x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^2-x+1\right)-6x\left(x^2-x+1\right)\)

\(=\left(x^2-x+1\right)\left(x^2+x+1-6x\right)\)

\(=\left(x^2-x+1\right)\left(x^2-5x+1\right)\)

= x⁴ - x³ + x² - 5x³ + 5x² - 5x + x² - x +1  = x² ( x² - x +1 ) - 5x ( x² - x +1 ) + x² - x +1 = ( x² - x +1 ) ( x² - 5x + 1 )

mk ko biết

x⁴+6x³+7x²-6x+1

=(x⁴-2x²+1)+(6x³-6x)+9x²

=(x²-1)²+6x(x²-1)+9x²

=(x²-1).(x²-1+6x)+9x²

=(x²+3x-1)²

x⁴+6x³+7x²-6x+1

 =(x⁴-2x²+1)+(6x³-6x)+9x²

=(x²-1)²+6x(x²-1)+9x²

=(x²-1). (x²-1+6x)+9x²

=(x²+3x-1)²

\(6x^2-7x-20\)

\(=6x^2+8x-15x-20\)

\(=2x\cdot\left(3x+4\right)-5\left(3x+4\right)\)

\(=\left(3x+4\right)\left(2x-5\right)\)

\(6x^2-7x+1=6x^2-6x+1\)

\(\left(x-1\right)-\left(x-1\right)=\left(6x-1\right)\left(x-1\right)\)

6x²  - 7x - 20

= 6x² - 15 + 8x - 20

= 3x ( 2x - 5 )+ 4 ( 2x - 5 )

= (3x+4) (2x-5)

\(7x-6x^2-2=-\left(6x^2-7x+2\right)\)

\(=-\left(6x^2-3x-4x+2\right)\)

\(=-\left[3x\left(2x-1\right)-2\left(2x-1\right)\right]\)

\(=-\left(3x-2\right)\left(2x-1\right)\)

\(7x-6x^2-2\)

\(=-6x^2+7x-2\)

\(=\left(x-\frac{2}{3}\right)\left(x-\frac{1}{2}\right)\)