a) x = 99/20

b) x = 7

c) x = 2

( chỉ lm đc đến đó thui nk )

tính giá trị biểu thức chứ còn cái gì nữa

a, \(A=\frac{22}{27}\)

b,\(B=\frac{1}{57}\)

C,\(C=\frac{1}{50}\)

d, \(D=0\)

Bài 1:

a) \(\frac{2}{5}+\frac{1}{5}.\left(\frac{3}{4}\right)\)

= \(\frac{2}{5}+\frac{3}{20}\)

= \(\frac{11}{20}\)

b) \(\frac{5}{12}.\left(-\frac{3}{4}\right)\) + \(\frac{7}{12}.\left(-\frac{3}{4}\right)\)

= \(\left(\frac{5}{12}+\frac{7}{12}\right).\left(-\frac{3}{4}\right)\)

= 1.\(\left(-\frac{3}{4}\right)\)

= \(-\frac{3}{4}\)

Còn câu c) đang nghĩ.

Bài 2:

a) \(\frac{5}{7}+\frac{2}{7}\)x = 1

1.x = 1

x = 1 : 1

x = 1

Vậy x = 1.

b) 0,2 + | x - 1, 3 = 1, 5|

0,2 + x = 1, 5 + 1, 3

0,2 + x = 2, 8

x = 2, 8 - 0, 2

x = 2, 6

Vậy x = 2, 6.

c) 2^x + 5 = 37

2^x = 37 - 5

2^x = 32

2^x = 2⁵

=> x = 5

Vậy x = 5.

d) 2^x + 2^{x + 1} = 48

2^x . 1 + 2^x . 2¹ = 48

2^x . ( 1 + 2) = 48

2^x . 3 = 48

2^x = 48 : 3

2^x = 16

2^x = 2⁴

=> x = 4

Vậy x = 4.

Chúc bạn học tốt!

làm bước trung gian giùm mình luôn nhé

thanks trước những bạn làm giùm nhé

mình đang cần gấp lắm sáng mai là mình cần ai đang on làm giùm mình nhé

thanks

Thuy Huynh mk làm nốt câu c bạn ấy chưa làm:

c/ \(\frac{2^{15}.9^4}{6^5.8^3}\)

\(=\frac{2^{15}.\left(3^2\right)^4}{\left(3.2\right)^5.\left(2^3\right)^3}\)

\(=\frac{2^{15}.3^8}{3^5.2^5.2^9}\)

\(=\frac{2^{15}.3^8}{3^5.2^{14}}\)

\(=2.3^3\)

= 2.27

= 54

a) \(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}+\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}+\frac{3}{293}}+\frac{\frac{7}{12}+\frac{5}{6}-1}{5-\frac{3}{4}+\frac{1}{3}}\) \(=\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}+\frac{\frac{5}{12}}{\frac{55}{12}}\)

\(=\frac{2}{3}+\frac{1}{11}=\frac{25}{33}\)

b) \(\left(1-\frac{1}{7}\right).\left(1-\frac{2}{7}\right)....\left(1-\frac{10}{7}\right)=\left(1-\frac{1}{7}\right).\left(1-\frac{2}{7}\right)...\left(1-\frac{7}{7}\right).\left(1-\frac{8}{7}\right).\left(1-\frac{9}{7}\right).\) \(\left(1-\frac{10}{7}\right)\) = 0

a)\(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}+\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}+\frac{3}{293}}+\frac{\frac{7}{12}+\frac{5}{6}-1}{5-\frac{3}{4}+\frac{1}{3}}\)

\(=\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}+\frac{\frac{7}{12}+\frac{10}{12}-\frac{12}{12}}{\frac{60}{12}-\frac{9}{12}+\frac{4}{12}}\)

\(=\frac{2}{3}+\frac{\frac{5}{12}}{\frac{55}{12}}\)

\(=\frac{2}{3}+\frac{1}{11}\)

\(=\frac{25}{33}\)

b)\(\left(1-\frac{1}{7}\right)\cdot\left(1-\frac{2}{7}\right)\cdot...\cdot\left(1-\frac{10}{7}\right)\)

Ta nhận thấy trong tích này có 1 thừa số là\(\left(1-\frac{7}{7}\right)=0\)nên tích trên sẽ bằng 0.

Ta có \(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}+\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}+\frac{3}{293}}+\frac{\frac{7}{12}+\frac{5}{6}-1}{5-\frac{3}{4}+\frac{1}{3}}\)

 = \(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}+\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}+\frac{3}{293}}+\frac{\frac{7}{12}+\frac{10}{12}-\frac{12}{12}}{\frac{60}{12}-\frac{9}{12}+\frac{4}{12}}\)

= \(\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}+\frac{\frac{5}{12}}{\frac{55}{12}}\)

=     \(\frac{2}{3}+\frac{1}{11}\)

=       \(\frac{25}{33}\)

a) \(\frac{3}{5}.x-\frac{1}{5}=\frac{4}{5}\)

\(\Leftrightarrow\frac{3}{5}.x=\frac{4}{5}+\frac{1}{5}\)

\(\Leftrightarrow\frac{3}{5}.x=1\)

\(\Leftrightarrow x=1:\frac{3}{5}\)

\(\Leftrightarrow x=\frac{5}{3}\)

Vậy : \(x=\frac{5}{3}\)

b) \(\frac{4}{7}+\frac{5}{7}:x=1\)

\(\Leftrightarrow\frac{5}{7}:x=1-\frac{4}{7}\)

\(\Leftrightarrow\frac{5}{7}:x=\frac{3}{7}\)

\(\Leftrightarrow x=\frac{5}{7}:\frac{3}{7}\)

\(\Leftrightarrow x=\frac{5}{3}\)

Vậy : \(x=\frac{5}{3}\)

c) \(-\frac{12}{7}.\left(\frac{3}{4}-x\right).\frac{1}{4}=-1\)

\(\Leftrightarrow\frac{-12.1}{7.4}.\left(\frac{3}{4}-x\right)=-1\)

\(\Leftrightarrow-\frac{3}{7}.\left(\frac{3}{4}-x\right)=-1\)

\(\Leftrightarrow\frac{3}{4}-x=-1:\left(-\frac{3}{7}\right)\)

\(\Leftrightarrow\frac{3}{4}-x=\frac{7}{3}\)

\(\Leftrightarrow x=\frac{3}{4}-\frac{7}{3}=-\frac{19}{12}\)

Vậy : \(x=-\frac{19}{12}\)

d) \(x:\frac{17}{8}=-\frac{2}{5}.-\frac{9}{17}+3\)

\(\Leftrightarrow x:\frac{17}{8}=\frac{273}{85}\)

\(\Leftrightarrow x=\frac{273}{85}.\frac{17}{8}\)

\(\Leftrightarrow x=\frac{273}{40}\)

Vậy : \(x=\frac{273}{40}\)

\(\)

\(x-40\%x=3,6\)

\(\Rightarrow100\%x-40\%x=3,6\)

\(\Rightarrow60\%x=3,6\)

\(\Rightarrow\frac{60}{100}x=3,6\)

\(\Rightarrow x=6\)

\(3\frac{2}{7}x-\frac{1}{3}=-2\frac{3}{4}\)

\(\Rightarrow\frac{23}{7}x-\frac{1}{3}=-\frac{11}{4}\)

\(\Rightarrow\frac{23}{7}x=-\frac{33}{12}+\frac{4}{12}\)

\(\Rightarrow\frac{23}{7}x=\frac{29}{12}\)

\(\Rightarrow x=\frac{29}{12}:\frac{23}{7}=\frac{203}{276}\)

\(-\frac{4}{7}+\frac{5}{7}:x=\frac{1}{6}\)

\(\Rightarrow\frac{5}{7}:x=\frac{1}{6}+\frac{4}{7}\)

\(\Rightarrow\frac{5}{7}:x=\frac{7}{42}+\frac{24}{42}\)

\(\Rightarrow\frac{5}{7}:x=\frac{33}{42}\)

\(\Rightarrow x=\frac{5}{7}:\frac{33}{42}\)

\(\Rightarrow x=\frac{5}{7}.\frac{6.7}{33}=\frac{30}{33}\)

Bài 2 :

1) \(x-70=-45\) 2) \(\frac{4}{7}:x=\frac{12}{28}\)

\(\Rightarrow\) \(x=-45+70\) \(\Rightarrow x=\frac{4}{7}:\frac{12}{28}\)

\(\Rightarrow\) \(x=25\) \(\Rightarrow x=\frac{4}{3}\)

Vậy \(x=25\) Vậy \(x=\frac{4}{3}\)

3) Giống câu c) ở bài 1

4) \(x-50=-35\) 5) \(\frac{4}{7}.x=\frac{11}{18}\)

\(\Rightarrow x=-35+50\) \(\Rightarrow x=\frac{11}{28}:\frac{4}{7}\)

\(\Rightarrow x=15\) \(\Rightarrow x=\frac{77}{72}\)

Vậy \(x=15\) Vậy \(x=\frac{77}{72}\)

6) \(\left(\frac{2}{3}x+2,5\right):2\frac{2}{6}=6\)

\(\Rightarrow\)\(\left(\frac{2}{3}x+2,5\right):\frac{14}{6}=6\)

\(\Rightarrow\) \(\frac{2}{3}x+2,5=6.\frac{14}{6}\)

\(\Rightarrow\frac{2}{3}x+2,5=14\)

\(\Rightarrow\frac{2}{3}x=\frac{23}{2}\)

\(\Rightarrow x=\frac{23}{2}:\frac{2}{3}\)

\(\Rightarrow x=\frac{69}{4}\)

Vậy \(x=\frac{69}{4}\)

Bài 1:

1) \(\frac{7}{5}+\frac{-8}{5}=-\frac{1}{5}\)

2) \(-\frac{6}{5}.\frac{15}{24}=-\frac{3}{4}\)

3) \(\left(\frac{2}{3}+1,5\right)-3,5:7\frac{1}{2}=\)\(\frac{13}{6}-\frac{7}{15}=\frac{17}{10}\)

4) \(\frac{5}{8}-\frac{-7}{9}=\frac{5}{8}+\frac{7}{9}=\frac{101}{72}\)

5)\(\frac{-7}{3}.\frac{12}{28}=-1\)

              Bài làm :

a)\(=-\frac{3}{5}+\frac{28}{5}\times\frac{9}{14}=-\frac{3}{5}+\frac{18}{5}=3\)

b)\(=\frac{55}{126}+\frac{5}{42}+\frac{4}{9}=1\)

c)\(=-\frac{51}{13}-\frac{27}{13}=-6\)

d)\(=\frac{7}{3}-11\frac{1}{4}\times\frac{2}{15}=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\)

e)\(=1\times\frac{8}{3}\times0,25=\frac{2}{3}\)