$\left(1989.1990+3978\right):\left(1992.1991-3984\right)$

$=\left[1989.\left(1990+2\right)\right]:\left[1992\left(1991-2\right)\right]=\left(1989.1992\right):\left(1992.1989\right)=1$

\(\left(1989.1990+3978\right):\left(1992.1991-3984\right)\)

\(=\left[1989.\left(1990+2\right)\right]:\left[1992\left(1991-2\right)\right]=\left(1989.1992\right):\left(1992.1989\right)=1\)

1989 . 1990 + 3978 1992 . 1991 − 3984  ⇒  1989 . 1990 + 1989 . 2 1992 . 1991 − 1992 . 2  ⇒  1989 . ( 1990 + 2 ) 1992 . ( 1991 + 2 )    ⇒  1989 . 1992 1992 . 1989  ⇒  1

dấu chấm là dấu nhân

\(\dfrac{1989\times1990+3978}{1992\times1991-3984}\)

\(=\dfrac{1989\times1990+1989\times2}{1992\times1991-1992\times2}\)

\(=\dfrac{1989\times\left(1990+2\right)}{1992\times\left(1991+2\right)}\)

\(=\dfrac{1989\times1992}{1992\times1989}\)

\(=1\)

\(\left(1989\times1990+3978\right):\left(1992\times1991-3984\right)\\ =\left(1989\times1990+1989\times2\right):\left(1992\times1991-1992\times2\right)\\ =\left(1989\times1992\right):\left(1992\times1989\right)\\ =1\)

\(\frac{1989\times1990+3978}{1992\times1991-3984}=\frac{1989\times1990+1989\times2}{1992\times1991-1992\times2}=\frac{1989\times\left(1990+2\right)}{1992\times\left(1991-2\right)}=\frac{1989\times1992}{1992\times1989}=1\)

Đáp số: 1.

Đúng 100% luôn!

Ai tk cho mình mình tk lại.

bằng 1 nha!

= 1 nhé bn

a) ( 1989 x 1990 + 3978 ) : ( 1992 x 1991 - 3984 )

= 3 962 088 : 3 962 088

= 1

3972036,001 hoặc 3976023,985

Mik sửa lại đề

\(\frac{1989.1990+3978}{1992\cdot1991-3984}\)

Trả lời

\(\frac{1989.1990+3978}{1992.1991-3984}\)

\(=\frac{1989.1990+1989\cdot2}{1992.1991-1992.2}\)

\(=\frac{1989.\left(1992-2\right)}{1992\left(1991-2\right)}\)

\(=\frac{1989.1990}{1992.1989}\)

\(=\frac{1990}{1992}\)

\(=\frac{995}{996}\)

-)1998*1990+3978=3976020+3978= 3979998

-)1992*1991-3984=3966072-3984=3962088

tich ủng hộ mình nha