c=2004*2002+2004*2

d= 2002*2004+2002*2

vay c>d

2006 x 2007 lớn hơn 

thế này này:

2005*2008 =2005*(2007+1)=2005*2007+2005*1

2006*2007=2007*(2005+1)=2007*2005+2007*1

vì 2005*1<2007*1 nên 2005*2008<2006*2007

2006x2007 lon hon

A = 2004 x 2004 và B = 2002 x 2006

A = [ 2002 + 2 ] x 2004 = 2002 x 2004 + 2 x 2004

B = 2002 x [ 2004 + 2 ] = 2002 x 2004 + 2 x 2002

Suy ra A > B

A=4016016;B=4016012

vậy A>B

\(A=2004x2004\)

\(A=\left(2002+2\right).\left(2006-2\right)\)

\(A=2002\left(2006-2\right)+2\left(2006-2\right)\)

\(A=2002.2006-4004+4012-4\)

\(A=2002.2006+4\) 

Mà \(B=2002.2006\)

\(\Rightarrow A>B\)

2002/2001>:,2003/2002>1.....

CÓ 8 PHÂN SỐ MỖI PHÂN SỐ CÓ GIÁ TRỊ LỚN HƠN 1 VÂY TỔNG CỦA 8 PHÂN SỐ LỚN HƠN 1 SẼ LỚN HƠN 8.

\(A=\frac{2002}{2001}+\frac{2003}{2002}+\frac{2004}{2003}+\frac{2005}{2004}+\frac{2006}{2005}+\frac{2007}{2006}+\frac{2008}{2007}+\frac{2009}{2008}>\frac{2001}{2001}+\frac{2002}{2002}+\frac{2003}{2003}+\frac{2004}{2004}+\frac{2005}{2005}+\frac{2006}{2006}+\frac{2007}{2007}+\frac{2008}{2008}\)

\(A=\frac{2002}{2001}+\frac{2003}{2002}+\frac{2004}{2003}+\frac{2005}{2004}+\frac{2006}{2005}+\frac{2007}{2006}+\frac{2008}{2007}+\frac{2009}{2008}>1+1+1+1+1+1+1+1\)\(A=\frac{2002}{2001}+\frac{2003}{2002}+\frac{2004}{2003}+\frac{2005}{2004}+\frac{2006}{2005}+\frac{2007}{2006}+\frac{2008}{2007}+\frac{2009}{2008}>8\)

\(A>8\)

Ta có:

\(M=2007\times2007=\left(2004+3\right)\times2007=2004\times2007+3\times2007\)

\(N=2004\times2008=2004\times\left(2007+1\right)=2004\times2007+2004\times1\)

\(3\times2007=6021;2004\times1=2004\)

Vì \(2004\times2007=2004\times2007\)và\(6021>2004\)nên \(M>N\).

M<N 
 

m = 2007 x 2007 = (2004 + 3) x 2007 = 2004 x 2007 + 3 x 2007 = 2004 x 2007 + 6021

n = 2004 x 2008 = 2004 x (2007 + 1) = 2004 x 2007 + 2004 x 1 = 2004 x 2007 + 2004

Ta có : 2004 x 2007 + 6021 \(>\) 2004 x 2007 + 2004

Nên, m \(>\) n.

2002/2004= 1 - 2/2004

2004/2006= 1 - 2/2006

Vì: 2/2004> 2/2006 

nên: 1 - 2/2004 < 1 - 2/2006

Vậy: 2002/2004 < 2004/2006

\(A=\dfrac{2002}{2004}=\dfrac{2004-2}{2004}=1-\dfrac{2}{2004}\)

\(B=\dfrac{2004}{2006}=\dfrac{2006-2}{2006}=1-\dfrac{2}{2006}\)

Vì \(\dfrac{2}{2004}>\dfrac{2}{2006}\)  (So sánh 2 phân số cùng tử)

Nên A < B

A=20042002​=20042004−2​=1−20042​

B=20042006=2006−22006=1−22006B=20062004​=20062006−2​=1−20062​

Vì 22004>2200620042​>20062​  (So sánh 2 phân số cùng tử)

Nên A < B