Cho A = \(1\times2+2\times3+3\times4+...+19\times20\)
Tính \(A\times3\)
\(\frac{2}{1\times2}+\frac{2}{2\times3}+\frac{2}{3\times4}+...+\frac{2}{18\times19}+\frac{2}{19\times20}\)
Tính nhanh
\(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+.......+\frac{2}{18.19}+\frac{2}{19.20}.\)
\(=2\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+........+\frac{1}{18.19}+\frac{1}{19.20}\right)\)
\(=2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}\right)\)
\(=2\left(1-\frac{1}{20}\right)=\frac{2.19}{20}=\frac{19}{10}\)
\(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{18.19}+\frac{2}{19.20}\)
\(=1+\frac{1}{2}-\frac{1}{2}+\frac{1}{3}-\frac{1}{3}+\frac{1}{4}-\frac{1}{4}+...-\frac{1}{19}+\frac{1}{20}\)
\(=1+\frac{1}{20}\)
\(=\frac{1}{20}\)
\(\frac{2}{1\times2}+\frac{2}{2\times3}+\frac{2}{3\times4}+......+\frac{1}{19\times20}\)
\(=2\left(\frac{1}{1\times2}+\frac{1}{2\times3}+..........+\frac{1}{19\times20}\right)\)
\(=2\left(1-\frac{1}{2}+\frac{1}{2}-......+\frac{1}{19}-\frac{1}{20}\right)\)
\(=2\left(1-\frac{1}{20}\right)\)
\(=2.\frac{19}{20}=\frac{19}{10}\)
Bài 1: Tính
a) \(\dfrac{2\times3\times6\times7}{12\times7\times9\times2}\)
b) \(\dfrac{3\times4\times30\times56}{9\times8\times7\times8\times20}\)
(Các bạn tách ra rồi tính)
Cho biểu thức A= \(\frac{1}{1\times2\times3}\)+ \(\frac{1}{2\times3\times4}\)+ \(\frac{1}{3\times4\times5}\)+...+ \(\frac{1}{18\times19\times20}\). So sánh A với \(\frac{1}{4}\).
Cho biểu thức A= 11×2×3 + 12×3×4 + 13×
4×5 +...+ 118×19×20 . So sánh A với 14 .
Dương Đình Hưởng
cố lên mà k
Chứng minh rằng: \(\frac{1}{2\times2}+\frac{1}{3\times3}+\frac{1}{4\times4}+....+\frac{1}{19\times19}+\frac{1}{20\times20}
\(\frac{1}{2\times2}+\frac{1}{3\times3}+....+\frac{1}{20\times20}
Chứng tỏ rằng:\(\frac{3}{1^2\times2^2}+\frac{5}{2^2\times3^2}+\frac{7}{3^2\times4^2}+...+\frac{39}{19^2\times20^2}\)< 1
\(\frac{3}{1^2x2^2}\)+\(\frac{5}{2^2x3^2}\)+...+\(\frac{39}{19^2x20^2}\)<1
=\(\frac{3}{1.4}\)+\(\frac{5}{4x9}\)+...+\(\frac{39}{361x400}\)<1
=1-\(\frac{1}{4}\)+\(\frac{1}{4}\)-...-\(\frac{1}{361}\)+\(\frac{1}{361}\)-\(\frac{1}{400}\)<1
vì 1-\(\frac{1}{400}\)<1 nên \(\frac{3}{1^2x2^2}\)+\(\frac{5}{2^2x3^2}\)+...+\(\frac{39}{39^2x40^2}\)<1
vậy..............................................
tính nhanh: \(\frac{1\times3\times2\times4\times3\times5\times4\times6\times5\times7}{2\times2\times3\times3\times4\times4\times5\times5\times6\times6}\)
Cho B= \(\frac{1\times2}{1\times2\times3}+\frac{1\times2}{1\times2\times4}+\frac{1\times2}{1\times2\times3\times4}+\frac{1\times2}{1\times2\times3\times4\times5}+....+\frac{1\times2}{n,giao}\left(n\in N,n\ge3\right)\)
chứng tỏ B nhỏ hơn 3
Cho \(A=1\times2+2\times3+3\times4+4\times5+...+100\times101\)
\(B=1\times3+2\times4+3\times5+4\times6+...+100\times102\)
Tính B-A
Ta có: B-A=1x3+2x4+3x5+4x6+...+100x102-(1x2+2x3+3x4+4x5+...+100x101)
=1x3+2x4+3x5+4x6+...100x102-1x2-2x3-3x4-4x5-...-100x101
=1+2+3+4+...+100
=((100-1):1+1)x((100-1):2)
=100x(101:2)
=5050
Tính\(\frac{1}{1\times2\times3}+\frac{1}{2\times3\times4}+\frac{1}{3\times4\times5}+...\frac{1}{2014\times2015\times2016}\)
\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{2014.2015.2016}\)
\(=\frac{1}{2}\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{2014.2015.2016}\right)\)
\(=\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{2014.2015}-\frac{1}{2015.2016}\right)\)
\(=\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{2015.2016}\right)\)