Ta có: \(x-\frac{20}{11\cdot13}-\frac{20}{13\cdot15}-...-\frac{20}{53\cdot55}=\frac{3}{11}\)

\(\Leftrightarrow x-10\cdot\left(\frac{2}{11\cdot13}+\frac{2}{13\cdot15}+...+\frac{2}{53\cdot55}\right)=\frac{3}{11}\)

\(\Leftrightarrow x-10\cdot\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{53}-\frac{1}{55}\right)=\frac{3}{11}\)

\(\Leftrightarrow x-10\cdot\left(\frac{1}{11}-\frac{1}{55}\right)=\frac{3}{11}\)

\(\Leftrightarrow x-10\cdot\frac{4}{55}=\frac{3}{11}\)

\(\Leftrightarrow x-\frac{8}{11}=\frac{3}{11}\)

\(\Leftrightarrow x=\frac{3}{11}+\frac{8}{11}\)

\(\Leftrightarrow x=1\)

Vậy \(x=1\)thỏa mãn đề. 

\(a,\)\(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}=-\frac{37}{45}\)

  \(x+\left(\frac{9-5}{5.9}+\frac{13-9}{9.13}+\frac{17-13}{13.17}+...+\frac{45-41}{41.45}\right)=-\frac{37}{45}\)

  \(x+\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+....+\frac{1}{41}-\frac{1}{45}\right)-\frac{37}{45}\)

 \(x+\left(\frac{1}{5}-\frac{1}{45}\right)=-\frac{37}{45}\)

 \(x+\frac{8}{45}=-\frac{37}{45}\)

\(x=-\frac{37}{45}-\frac{8}{45}\)

\(x=-1\)

thế phần b, c đâu bạn

\(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...-\frac{20}{53.55}=\frac{3}{11}\)

\(x-10\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+...+\frac{2}{53.55}\right)=\frac{3}{11}\)

\(x-10\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{53}-\frac{1}{55}\right)=\frac{3}{11}\)

\(x-10.\frac{4}{55}=\frac{3}{11}\)

\(x=1\)

a) \(\left(3\frac{1}{2}-2x\right).3\frac{1}{3}=7\frac{1}{3}\)

 \(\left(\frac{7}{2}-2x\right).\frac{10}{3}=\frac{22}{3}\)

  \(\frac{7}{2}-2x=\frac{11}{5}\)

              \(2x=\frac{13}{10}\)

                \(x=\frac{13}{20}\)

Vậy ...

b) \(\frac{4}{9}x=\frac{9}{8}-0,125\)

   \(\frac{4}{9}x=1\)

         \(x=\frac{9}{4}\)

Vậy...

mình ko ghi đầu bài đâu nhé

a, 7/2-2x=22/3:10/3

   7/2-2x=11/5

  2x=7/2-11/5

  2x=13/10

  x=13/10:2

 x=13/20

\(\frac{x-2}{12}+\frac{x-2}{20}+\frac{x-2}{30}+\frac{x-2}{42}+\frac{x-2}{56}+\frac{x-2}{72}=\frac{16}{9}\)

\(\left(x-2\right)\cdot\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)

\(\left(x-2\right)\cdot\left(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}\right)=\frac{16}{9}\)

\(\left(x-2\right)\cdot\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\right)=\frac{16}{9}\)

\(\left(x-2\right)\cdot\left(\frac{1}{3}-\frac{1}{9}\right)=\frac{16}{9}\)

\(\left(x-2\right)\cdot\left(\frac{3}{9}-\frac{1}{9}\right)=\frac{16}{9}\)

\(\left(x-2\right)\cdot\frac{2}{9}=\frac{16}{9}\)

\(x-2=\frac{16}{9}:\frac{2}{9}\)

\(x-2=\frac{16}{9}\cdot\frac{9}{2}\)

\(x-2=8\)

\(x=8+2\)

\(x=10\)

Vậy \(x=10\)

\(\left(x-2\right)\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\right)=\)\(=\frac{16}{9}\)

\(\left(x-2\right)\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}+\frac{1}{8}-\frac{1}{9}\right)=\frac{16}{9}\)

\(\left(x-2\right)\left(\frac{1}{3}-\frac{1}{9}\right)=\frac{16}{9}\)

\(\left(x-2\right)\left(\frac{2}{9}\right)=\frac{16}{9}\)

2(x-2)=16

x-2=8

x=10
 

a)  \(2\frac{1}{4}x-9\frac{1}{4}=20\)

\(\frac{9}{4}x=20+\frac{37}{4}\)

\(\frac{9}{4}x=\frac{80}{4}+\frac{37}{4}\)

\(\frac{9}{4}x=\frac{117}{4}\)

\(x=\frac{117}{4}:\frac{9}{4}\)

\(x=\frac{117}{4}.\frac{4}{9}\)

\(x=13\)

Vậy x=13

a) \(2\frac{1}{4}x-9\frac{1}{4}=20\)

\(\Rightarrow\frac{9}{4}x-\frac{37}{4}=20\)

\(\Rightarrow\frac{9}{4}x=20+\frac{37}{4}\)

\(\Rightarrow\frac{9}{4}x=\frac{117}{4}\)

\(\Rightarrow x=\frac{117}{4}:\frac{9}{4}\)

\(\Rightarrow x=13\)

Vậy x = 13

b) \(0,25x-\frac{1}{5}x=\frac{13}{20}\)

\(\Rightarrow\left(0,25-\frac{1}{5}\right)x=\frac{13}{20}\)

\(\Rightarrow\frac{1}{20}x=\frac{13}{20}\)

\(\Rightarrow x=\frac{13}{20}:\frac{1}{20}\)

\(\Rightarrow x=13\)

Vậy x = 13

\(b,\)\(0,25x-\frac{1}{5}x=\frac{13}{20}\)

\(\Leftrightarrow x\left(0,25-\frac{1}{5}\right)=\frac{13}{20}\)

\(\Rightarrow x.\frac{1}{20}=\frac{13}{20}\)

\(\Rightarrow x=\frac{13}{20}:\frac{1}{20}\)

\(x=13\)