tìm x biết :
x +1,75:0,12=1+2-3+4-5+6-........+118-119+120
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Tìm x :
(x + 1,75) : 0,12 = 1+2-3+4-5+6- ...+118-119+120
x+1,75):0,12=1+2-3+4-5+6...+118-119+120
(x+1,75):0,12=1+(-1)+.......+(-1)+120
(60 số âm 1)
(x+1,75):0,12=1+(-60)+120
(x+1,75):0,12=-59+120
(x+1,75):0,12=61
(x+1,75) =61x0,12
x+1,75 =7,32
x =7,32-1,75
x =5,57
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Tìm x
a) [(3.x-3/5):0,75].1/2/3+1/3=1
b) 1999.2001-1/1998+1999.2000 . 7/5.x=1
c) 11,13 + 13,15 + 15,17 + ... +31,33 = 5.x+11,13
d) (x+1,75):0,12=1+2-3+4-5+6- ... +118-119+120
e) (2/11.13 + 2/13.15 + ... + 2/19.21 ) . 462 - [2,04 : ( x + 1,05 ) ] : 0,12 = 11,5
(x+1,750):0,12=1+2-3+4-5+6...+118-119+120
Tính: B=1-2-3+4-5-6+...+118-119-120
C=1-2-3-+5-6-7-8+....+117-118-119-120
Tính: B=1-2-3+4-5-6+...+118-119-120
C=1-2-3-+5-6-7-8+....+117-118-119-120
B=1-2-3+4-5-6+...+118-119-120
=(1-2-3)+(4-5-6)+...+(118-119-120)
=(-4) + (-4) +...+(-4)
60 số (-4)
=(-4).60
= -240
Vậy B= -240
C=1-2-3-4+5-6-7-8+...+117-118-119-120
= (1-2-3-4)+(5-6-7-8)+...+(117-118-119-120)
=(-8) +(-8) +...+(-8)
60 số (-8)
=(-8).60
= -480
Vậy C= -480
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Tìm x: \(\frac{x-1}{117}+\frac{x-2}{118}+\frac{x-3}{119}=\frac{x-4}{120}+\frac{x-5}{121}+\frac{x-6}{122}\)
Tìm x biết :
a)\(\frac{2}{3}x-50\%x-\left(-\frac{4}{5}\right):1\frac{3}{5}=-0,12\)\(+1\frac{3}{25}\)
b)\(\left(-1\frac{1}{6}+\frac{2}{3}-\frac{3}{4}\right):x+\left(-1\frac{11}{12}\right).1\frac{21}{23}=-6\frac{1}{3}\)
c)\(50\%x-\frac{1}{3}x-\left(\frac{-2}{3}\right)^2.\left(-1\frac{1}{8}\right)=-119\frac{3}{4}+120\frac{5}{6}\)
Tìm x biết
\(\frac{x-1}{117}+\frac{x-2}{118}+\frac{x-3}{119}=\frac{x-4}{120}+\frac{x-5}{121}+\frac{x-6}{122}\)
mình cần gấp
\(\Leftrightarrow\frac{x-1}{117}+1+\frac{x-2}{118}+1+\frac{x-3}{119}=\frac{x-4}{120}+1+\frac{x-5}{121}+1+\frac{x-6}{122}+1\)
\(\Leftrightarrow\frac{x+116}{117}+\frac{x+116}{118}+\frac{x+116}{119}-\frac{x+116}{120}-\frac{x+116}{121}-\frac{x+116}{122}=0\)
\(\Leftrightarrow\left(x+116\right)\left(\frac{1}{117}+\frac{1}{118}+\frac{1}{119}-\frac{1}{120}-\frac{1}{121}-\frac{1}{122}\right)=0\)
\(\Leftrightarrow x+116=0\Leftrightarrow x=-116\)
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\(\frac{x-1}{117}+\frac{x-2}{118}+\frac{x-3}{119}=\frac{x-4}{120}+\frac{x-5}{121}+\frac{x-6}{122}\)
\(\Leftrightarrow\frac{x-1}{117}+1+\frac{x-2}{118}+1+\frac{x-3}{119}+1=\frac{x-4}{120}+1+\frac{x-5}{121}+1+\frac{x-6}{122}+1\)
\(\Leftrightarrow\frac{x+116}{117}+\frac{x+116}{118}+\frac{x+116}{119}-\frac{x+116}{120}-\frac{x+116}{121}-\frac{x+116}{122}=0\)
\(\Leftrightarrow\left(x+116\right)\left(\frac{1}{117}+\frac{1}{118}+\frac{1}{119}-\frac{1}{120}-\frac{1}{121}-\frac{1}{122}\right)=0\)
Vì \(\frac{1}{117}+\frac{1}{118}+\frac{1}{119}-\frac{1}{120}-\frac{1}{121}-\frac{1}{122}\ne0\)
Nên x + 116 = 0
<=> x = -116
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1+2-3-4+5+6-7-8+...+117+118-119-120
1+(2-3-4+5)+(6-7-8+9)+...(118-119-120+121)-121
=1+0+0+...+0-121
=-120
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(1+3+5+....+119)+(2+4+6+...+120)
số bị trừ có số hang:(119-1):2+1=60(số hạng)
số bị trừ là:(1+119)x60:2=3600
số bị trừ có số hang:(120-2):2+1=60(số hạng)
số bị trừ là:(2+120)x60:2=3600
cón lại:3600-3600=0
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=1+(2-3-4+5)+(6-7-8+9)+...+(118-119-120+121)-121
=1+0+0+...+0-121
=-120
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