S= 1/2 + 1/6 + 1/12 + ...+ 1/90

S=1/1.2 + 1/2.3 +1/3.4+...+1/9.10

S=1-1/2 + 1/2-1/3 + 1/3-1/4+...+1/9-1/10

S=(1-1/10)+(1/2-1/2)+(1/3-1/3)+...+(1/9-1/9)

S=9/10+0+0+...+0

S=9/10Chúc bn học tốt =))

=1/2 + (1/2*3+1/3*4) + (1/4*5+1/5*6) + (1/6*7+1/7*8) + (1/8*9+1/9*10)
=1/2 + 1/2*3.(1+1/2) + 1/2*5.(1/2+1/3) + 1/2*7.(1/3+1/4) + 1/2*9.(1/4+1/5)
=1/2 + 1/2*3.(3/2) + 1/2*5.(5/6) + 1/2*7.(7/12) + 1/2*9.(9/20)
=1/2 + 1/4 + 1/12 + 1/24 + 1/40
=9/10

6 = 2 x 2 + 2 = 2(2+1)
12 = 3 x 3 + 3 = 3(3+1)
20 = 4 x 4 + 4 = 4(4+1)
...
90 = 9 x 9 + 9 = 9(9+1)

Ta có đồng nhất thức sau 
1/[n(n+1)] = 1/n - 1/(n+1)

Vậy
     1/6 = 1/2 - 1/3
     1/12 = 1/3 - 1/4
     1/20 = 1/4 - 1/5
....
     1/90 = 1/9 - 1/110

S =  1/2 -1/3+1/3-1/4+..............+1/9 -1/10

Tổng là 1/2 + 1/2 - 1/10 = 1 - 1/10 = 9/10
 

\(S=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\)

\(\Rightarrow S=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\)

       \(S=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\)(áp dụng quy tắc dấu ngoặc )

       \(S=\frac{1}{2}-\left(\frac{1}{3}-\frac{1}{3}\right)-\left(\frac{1}{4}-\frac{1}{4}\right)-...-\left(\frac{1}{9}-\frac{1}{9}\right)-\frac{1}{10}\)

      \(S=\frac{1}{2}-\frac{1}{10}\) 

      \(S=\frac{2}{5}\)

Giải hộ mik nha mấy bạn

\(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\)

\(\frac{1}{6}+\frac{1}{12}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{90}\)

\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-...+\frac{1}{9}-\frac{1}{10}\)

\(=1-\frac{1}{10}\)

\(=\frac{9}{10}\)

=1/1x2+1/2x3+1/3x4+.....+1/9x10

=1/1-1/2+1/2-1/3+1/3-1/4+.........-1/10

=1/1-1/10

=1/9

1/2+1/6+....+1/90

=1/1.2 +1/2.3 +1/3.4+.....+1/9.10

=1-1/2+1/2-1/3+1/3-1/4+...+1/9-1/10

=1-1/10=9/10

k 3 cái sao đc

Phân tích phân số ra 

Mình Đi học đã gợi ý đó

A = 1/90 - 1/72 - 1/56 - 1/42 - 1/30 - 1/20 - 1/12 - 1/6 - 1/2

A = 1/90 - ( 1/72 + 1/56 + 1/42 + 1/30 + 1/20 + 1/12 + 1/6 + 1/2)

A = 1/90 - ( 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72)

A = 1/90 - ( 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9)

A = 1/90 - ( 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/8 - 1/9)

A = 1/90 - ( 1 - 1/9)

 A = 1/90 - 8/9

A = 1/90 - 80/90 = -79/90

A=1/90-1/72-1/56-1/42-1/30-1/20-1/12-1/6-1/2

A=1/90-(1/72+1/56+1/42+1/30+1/20+1/12+1/6+1/2)

A=1/90-(1-1/9)

A=1/90-8/9=1/90-80/90=-79/90

\(A=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{8.9}=\frac{1}{9.10}\)

tới đây chắc bạn giải đc rồi ha!

nếu k biết cứ nhắn hỏi mình

bn giải giùm mình ghi các bước ra nha

bn giải hết giùm mình

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{90}\)

\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)

\(=\frac{1}{1}-\frac{1}{10}\)

\(=\frac{9}{10}\)

\(\frac{1}{6}+\frac{1}{12}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{90}\)

\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-...+\frac{1}{9}-\frac{1}{10}\)

\(=1-\frac{1}{10}\)

\(=\frac{9}{10}\)

\(\frac{1}{6}+\frac{1}{12}+\frac{1}{30}+...+\frac{1}{90}\)

\(=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\)

\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\)

\(=\frac{1}{2}-\frac{1}{10}\)

\(=\frac{2}{5}\)