2^x-1+5.2^x-2=7/32

=>2.2^x-2+5.2^x-2=7/32

=7.2^x-2=7/32

=>2^x-2=1/32

=>2^x-2=2^-5

=>x-2=-5

=>x=-3

vậy x=-3

k nha

\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)

\(\Rightarrow2.2^{x-2}+5.2^{x-2}=\frac{7}{32}\)

\(=7.2^{x-2}=\frac{7}{32}\)

\(\Rightarrow2^{x-2}=\frac{1}{32}\)

\(=2^{x-2}=2^{-5}\)

\(\Rightarrow x-2=-5\)

\(\Rightarrow x=-3\)

2
x-1+5.2
x-2=7/32
=>2.2
x-2+5.2
x-2=7/32
=7.2
x-2=7/32
=>2
x-2=1/32
=>2
x-2=2
-5
=>x-2=-5
=>x=-3
vậy x=-3

a. 2^x-1+ 5.2^x-1:2=7/32

=> 2^x+1.(1+5/2)=7/32

=>2^x+1.7/2=7/32

=> 2^x+1=1/16=1/2⁴

=> x+1=-4=>x=-5

\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)

\(\Rightarrow2^{x-1}+5.2^{x-1}.2^3=\frac{7}{32}\)

\(\Rightarrow2^{x-1}.\left(1+5.2^3\right)=\frac{7}{32}\)

\(\Rightarrow2^{x-1}.41=\frac{7}{32}\)

\(\Rightarrow2^{x-1}=\frac{7}{1312}\)

\(\Rightarrow\)   Ko có x thỏa mãn

ai ko bt = -3 giải rõ ràng đi              

\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)

\(2.2^{x-1}+5.2^{x-2}=\frac{7}{32}\)

      \(2^{x-2}.\left(5+2\right)=\frac{7}{32}\)

                   \(2^{x-2}.7=\frac{7}{32}\)

                       \(2^{x-2}=\frac{7}{32}:7\)

                       \(2^{x-2}=\frac{1}{32}\)

               \(\Rightarrow x-2=-5\)

                              \(x=-5+2\)

Vậy                           \(x=-3\)

\(2^{x-1}+5.2^{x-1}=\frac{7}{32}\)

=> \(2^{x-1}\left(1+5\right)=\frac{7}{32}\)

=> \(2^{x-1}.6=\frac{7}{32}\)

=> \(2^{x-1}=\frac{7}{32}:6=\frac{7}{192}\)

ĐỀ SAI RỒI BẠN !

2^x-1+5.2^x-2=2.2^x-2+5.2^x-2=2^x-2.(5+2)=2^x-2.7=7/32

=>2^x-2=7/32:7=1/32

=>x-2=-5

=>x=-3

=> x =3

\(2^{\left(x-1\right)}+5.2^{\left(x-2\right)}=\frac{7}{32}\)

\(\Leftrightarrow2.2^{x-2}+5.2^{x-2}=\frac{7}{32}\)

\(\Leftrightarrow\left(2+5\right).2^{x-2}=\frac{7}{32}\)

\(\Leftrightarrow7.2^{x-2}=\frac{7}{32}\)

\(\Leftrightarrow2^{x-2}=\frac{7}{32}:7\)

\(\Leftrightarrow2^{x-2}=\frac{1}{32}=2^{-5}\)

\(\Leftrightarrow x-2=-5\)

\(\Leftrightarrow x=\left(-5\right)+2\)

\(\Leftrightarrow x=-3\)

Vậy \(x=-3\).

Chúc bạn học tốt!