2710+95
C= --------------
913+272
Tính giá trị biểu thức sau:
D = 2 1 4 + 1 3 5 + 1 3 5 − 2 7 10 − 2 7 10
191/210+161/240+129/272+95/306
Tính nhan : 191/210+161/204+129/272+95/306
Tinh : B = 191/210 + 161/240 + 129/272 + 95/306
Tinh nhanh 191/210+161/240+129/272+95/306
Bấm máy tính là nhanh nhất!
Kết quả là: 149/63
Tính B =191/210 + 161/240 + 129 /272 + 95/306
tính nhanh
n=191/210+161/240+129/272+95/306
Tính hợp lý nhất
a, 1/210+1/240+1/272+1/306
b, 191/210+161/240+129/272+95/306
giúp mình với huhuhu
a, 1/210+1/240+1/272+1/306
= 1/14.15 + 1/15.16 + 1/16.17 +1/17.18
= 1/14 - 1/15 + 1/15 - 1/16 +1/16 - 1/17 + 1/17 - 1/18
= 1/14 - 1/18 = 1/63
a) \(\frac{1}{210}+\frac{1}{240}+\frac{1}{272}+\frac{1}{306}\)
=\(\frac{1}{14.15}+\frac{1}{15.16}+\frac{1}{16.17}+\frac{1}{17.18}\)
=\(\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{16}+\frac{1}{16}-\frac{1}{17}+\frac{1}{17}-\frac{1}{18}\)
=\(\frac{1}{14}-\frac{1}{18}=\frac{1}{63}\)
b)\(\frac{191}{210}+\frac{161}{240}+\frac{129}{272}+\frac{95}{306}\)
=\(\frac{191}{14.15}+\frac{161}{15.16}+\frac{129}{16.17}+\frac{95}{17.18}\)
=\(\frac{191}{14}-\frac{191}{15}+\frac{161}{15}-\frac{161}{16}+\frac{129}{16}-\frac{129}{17}+\frac{95}{17}-\frac{95}{18}\)
tự làm tiếp
\(B=\frac{191}{210}+\frac{161}{240}+\frac{129}{272}+\frac{95}{306}\)
tÍNH TỔNG