tìm x biết
\(x\times\left(4.6+\frac{3}{5}\right)+7.2-8.15\)\(42+\frac{3}{7}\times\left[3\times-1\right]=12\) \(\left[2\times x-1\right]=\left[x+2\right]\) \(\frac{x+2}{5}=\frac{2-3\times x}{3}\)Tìm x \(\frac{2}{\left(x-1\right)\times\left(x-3\right)}+\frac{5}{\left(x-3\right)\times\left(x-8\right)}+\frac{12}{\left(x-8\right)\times\left(x-20\right)}-\frac{1}{x-20}=-\frac{3}{4}\)-3/4
Tìm x biết:
\(\frac{-1}{2}\times\left(3x-1\right)+\frac{3}{4}\left(3-2x\right)=-3\times\left(\frac{x}{2}-1\right)-\left(\frac{4}{5}\right)^{-1}\)
Bài 15: Tìm x biết:
a, \(-\frac{3}{5}\times x=\frac{1}{4}+0,75\)
b, \(\left(\frac{1}{7}-\frac{1}{3}\right)\times x=\frac{28}{3}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)
c, \(\frac{5}{7}\times x=\frac{9}{8}-0,125\)
d, \(\left(\frac{2}{11}+\frac{1}{3}\right)\times x=\left(\frac{1}{7}-\frac{1}{8}\right)\times36\)
\(a,\)\(-\frac{3}{5}\cdot x=\frac{1}{4}+0,75\)
\(-\frac{3}{5}\cdot x=\frac{1}{4}+\frac{3}{4}=\frac{4}{4}=1\)
\(x=1\div\left(-\frac{3}{5}\right)\)
\(x=-\frac{5}{3}\)
\(b,\)\(\left(\frac{1}{7}-\frac{1}{3}\right)\cdot x=\frac{28}{5}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)
\(\left(\frac{3}{21}-\frac{7}{21}\right)\cdot x=\frac{28}{5}\cdot\left(\frac{7}{28}-\frac{4}{28}\right)\)
\(-\frac{4}{21}\cdot x=\frac{28}{5}\cdot\frac{3}{28}\)
\(-\frac{4}{21}\cdot x=\frac{3}{5}\)
\(x=\frac{3}{5}\div\left(-\frac{4}{21}\right)\)
\(x=-\frac{63}{20}\)
\(c,\)\(\frac{5}{7}\cdot x=\frac{9}{8}-0,125\)
\(\frac{5}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)
\(\frac{5}{7}\cdot x=1\)
\(x=1\div\frac{5}{7}\)
\(x=\frac{7}{5}\)
\(d,\)\(\left(\frac{2}{11}+\frac{1}{3}\right)\cdot x=\left(\frac{1}{7}-\frac{1}{8}\right)\cdot36\)
\(\left(\frac{6}{33}+\frac{11}{33}\right)\cdot x=\left(\frac{8}{56}-\frac{7}{56}\right)\cdot36\)
\(\frac{17}{33}\cdot x=\frac{1}{56}\cdot36\)
\(\frac{17}{33}\cdot x=\frac{9}{14}\)
\(x=\frac{9}{14}\div\frac{17}{33}\)
\(x=\frac{9}{14}\cdot\frac{33}{17}=\frac{297}{238}\)
a)\(\frac{3}{5}\times x=1\)
\(x=1\div\frac{3}{5}\)
\(x=\frac{5}{3}\)
Mình chỉ làm duoc câu a thôi
tìm x , biết :
\(\frac{4}{5}x^2\times\left(\frac{x}{3}-\frac{1}{2}\right)-\left(\frac{1}{5}x-\frac{2}{3}\right)\times\left(\frac{4x^2}{3}+1\right)=\frac{22}{45}x^2\)
\(\Leftrightarrow\frac{4x^2}{5}\times\frac{2x-3}{6}-\frac{3x-10}{15}\times\frac{4x^2+3}{3}=\frac{22x^2}{45}\)
\(\Leftrightarrow\frac{4x^2\left(2x-3\right)}{30}-\frac{\left(3x-10\right)\left(4x^2+3\right)}{45}=\frac{22x^2}{45}\)
\(\Leftrightarrow\frac{12x^2\left(2x-3\right)}{90}-\frac{2\left(3x-10\right)\left(4x^2+3\right)}{90}=\frac{44x^2}{90}\)
\(\Leftrightarrow12x^2\left(2x-3\right)-2\left(3x-10\right)\left(4x^2+3\right)=44x^2\)
\(\Leftrightarrow24x^2-36x^2-2\left(12x^3+9x-40x^2-30\right)=44x^2\)
\(\Leftrightarrow24x^2-36x^2-24x^3-18x+80x^2+60=44x^2\)
\(\Leftrightarrow24x^3-36x^2-24x^3-18x+80x^2-44x^2=-60\)
\(\Leftrightarrow\left(24x^3-24x^3\right)+\left(-36x^2+80x^2-44x^2\right)-18x=-60\)
\(\Leftrightarrow-18x=-60\)
\(\Leftrightarrow x=\frac{-60}{-18}\)
\(\Leftrightarrow x=\frac{10}{3}\)
tìm x:
\(\left|x\right|-5\frac{3}{7}\times\left|x\right|-\frac{3}{4}=2\times\left|x\right|+\frac{-15}{2}\)
\(50\%+\frac{2}{3}x=x+4\)
\(0,5x-\frac{2}{3}\left(x+1\right)=\frac{-1}{12}\)
\(\frac{1}{2}\left(x-\frac{2}{3}\right)-\frac{2}{5}\left(2-x\right)=\frac{1}{9}\)
Tìm x:
a.\(\frac{1}{3}\times\left(x-1\right)+\frac{2}{5}\times\left(x+1\right)=0\)
b.\(4x-\left(x+\frac{1}{2}\right)=2x-\left(\frac{1}{2}x-5\right)\)
c.\(\left(x+\frac{1}{2}\right)\times\left(x-\frac{3}{4}\right)=0\)
Các bn ơi giúp mk với chiều mk đi học rồi!!!!!!!!!!!!
Rút gọn \(B=\left(x^4-x+\frac{x-3}{x^3+1}\times\frac{\left(x^3-2x^2+2x-1\right)\left(x+1\right)}{x^9+x^7-3x^2-3}+1-\frac{2\left(x+6\right)}{x^2+1}\right)\times\frac{4x^2+6x+1}{\left(x+3\right)\left(4-x\right)}\)
1/Tính
a)
\(\frac{2}{5}+\frac{1}{5}\times\left(\frac{3}{4}\right)\)
b)\(\frac{5}{12}\times\left(\frac{-3}{4}\right)+\frac{7}{12}\times\left(\frac{-3}{4}\right)\)
c)\(\frac{2^{15}\times9^4}{6^6\times8^3}\)
2/Tìm x biết:
a)\(\frac{5}{7}+\frac{2}{7}x=1\)
b)0,2+\(\left|x-1,3=1,5\right|\)
c)\(2^x+5=37\)
d)\(2^x+2^{x+1}=48\)
Bài 1:
a) \(\frac{2}{5}+\frac{1}{5}.\left(\frac{3}{4}\right)\)
= \(\frac{2}{5}+\frac{3}{20}\)
= \(\frac{11}{20}\)
b) \(\frac{5}{12}.\left(-\frac{3}{4}\right)\) + \(\frac{7}{12}.\left(-\frac{3}{4}\right)\)
= \(\left(\frac{5}{12}+\frac{7}{12}\right).\left(-\frac{3}{4}\right)\)
= 1.\(\left(-\frac{3}{4}\right)\)
= \(-\frac{3}{4}\)
Còn câu c) đang nghĩ.
Bài 2:
a) \(\frac{5}{7}+\frac{2}{7}\)x = 1
1.x = 1
x = 1 : 1
x = 1
Vậy x = 1.
b) 0,2 + | x - 1, 3 = 1, 5|
0,2 + x = 1, 5 + 1, 3
0,2 + x = 2, 8
x = 2, 8 - 0, 2
x = 2, 6
Vậy x = 2, 6.
c) 2x + 5 = 37
2x = 37 - 5
2x = 32
2x = 25
=> x = 5
Vậy x = 5.
d) 2x + 2x + 1 = 48
2x . 1 + 2x . 21 = 48
2x . ( 1 + 2) = 48
2x . 3 = 48
2x = 48 : 3
2x = 16
2x = 24
=> x = 4
Vậy x = 4.
Chúc bạn học tốt!
làm bước trung gian giùm mình luôn nhé
thanks trước những bạn làm giùm nhé
mình đang cần gấp lắm sáng mai là mình cần ai đang on làm giùm mình nhé
thanks
Thuy Huynh mk làm nốt câu c bạn ấy chưa làm:
c/ \(\frac{2^{15}.9^4}{6^5.8^3}\)
\(=\frac{2^{15}.\left(3^2\right)^4}{\left(3.2\right)^5.\left(2^3\right)^3}\)
\(=\frac{2^{15}.3^8}{3^5.2^5.2^9}\)
\(=\frac{2^{15}.3^8}{3^5.2^{14}}\)
\(=2.3^3\)
= 2.27
= 54
\(\frac{2}{3}\times\left(x+3\right)-\frac{1}{2}\times\left(x-4\right)=\frac{5}{6}-x\)
làm nhanh hộ mk cái , mk đang cần lắm
\(\Rightarrow\frac{2}{3}\times x+\frac{2}{3}\times3-\frac{1}{2}\times x+\frac{1}{2}\times4=\frac{5}{6}-x\)
\(\Rightarrow\frac{1}{6}\times x+4=\frac{5}{6}-x\)
\(\Rightarrow\frac{7}{6}\times x=\frac{-19}{6}\)
\(\Rightarrow x=\frac{-19}{7}\)
Có gì không hiểu thì nhắn tin hỏi mình nha