\(\frac{-x}{21}=\frac{20}{7}\) Tìm x
tìm x, biết :
\(\frac{-x}{21}=\frac{20}{7}\)
\(\frac{-x}{21}=\frac{20}{7}\)
\(\Rightarrow-x.7=21.20\)
\(\Rightarrow-x.7=420\)
\(\Rightarrow-x=420:7\)
\(\Rightarrow-x=-60\)
\(\frac{-x}{21}=\frac{20}{7}\)
\(\Rightarrow-x.7=20.21\)
\(\Rightarrow-7x=420\)
\(\Rightarrow x=420:-7\)
\(\Rightarrow x=-60\)
Vậy \(x=-60\)
Chúc bạn học tốt !!!
\(\frac{-x}{21}=\frac{20}{7}\)
\(\Leftrightarrow-x.7=20.21\)
\(\Leftrightarrow-x.7=210\)
\(\Leftrightarrow-x=30\)
\(\Leftrightarrow x=30\)
Tìm giá trị nguyên lớn nhất của x thỏa mãn:
\(-\frac{20}{21}< x+\frac{4}{7}< \frac{7}{12}\)
Bài giải
\(-\frac{20}{21}< x+\frac{4}{7}< \frac{7}{12}\)
\(-\frac{20}{21}-\frac{4}{7}< x+\frac{4}{7}-\frac{4}{7}< \frac{7}{12}-\frac{4}{7}\)
\(-\frac{32}{21}< x< \frac{1}{84}\)
\(-1,5...< x< 0,01...\)
\(\Rightarrow\text{ }x=-1\)
tìm x,y
\(\frac{x}{7}=\frac{6}{21}\)
\(\frac{-5}{y}=\frac{20}{28}\)
\(\frac{x}{7}=\frac{6}{21}\)
\(\Rightarrow x=\frac{7.6}{21}\)
\(\Rightarrow x=2\)
\(-\frac{5}{y}=\frac{20}{28}\)
\(\Rightarrow y=\frac{-5.28}{20}\)
\(\Rightarrow y=-7\)
tìm x
a,\(\left(3\frac{1}{2}-2.x\right).3\frac{1}{3}=7\frac{1}{3}\)
b, \(\frac{4}{9}.x=\frac{9}{8}-0,125\)
c,\(\frac{-x}{21}=\frac{20}{7}\)
a) \(\left(3\frac{1}{2}-2x\right).3\frac{1}{3}=7\frac{1}{3}\)
\(\left(\frac{7}{2}-2x\right).\frac{10}{3}=\frac{22}{3}\)
\(\frac{7}{2}-2x=\frac{11}{5}\)
\(2x=\frac{13}{10}\)
\(x=\frac{13}{20}\)
Vậy ...
b) \(\frac{4}{9}x=\frac{9}{8}-0,125\)
\(\frac{4}{9}x=1\)
\(x=\frac{9}{4}\)
Vậy...
mình ko ghi đầu bài đâu nhé
a, 7/2-2x=22/3:10/3
7/2-2x=11/5
2x=7/2-11/5
2x=13/10
x=13/10:2
x=13/20
Bài 1: Tìm x;
x - \(\frac{20}{11.13}\) - \(\frac{20}{13.15}\) -...- \(\frac{20}{53.55}\) = \(\frac{3}{11}\)
\(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
Bài 2: Tìm A biết:
A= \(\frac{7}{10}\)+\(\frac{7}{10^2}\)+ \(\frac{7}{10^3}\)+......
Bài 1:
a) \(x-\frac{20}{11.13}-\frac{20}{13.15}-...-\frac{20}{53.55}=\frac{3}{11}\)
\(x-\left(\frac{20}{11.13}+\frac{20}{13.15}+...+\frac{20}{53.55}\right)=\frac{3}{11}\)
\(x-\frac{20}{2}.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{53}-\frac{1}{55}\right)=\frac{3}{11}\)
\(x-10.\left(\frac{1}{11}-\frac{1}{55}\right)=\frac{3}{11}\)
\(x-10\cdot\frac{4}{55}=\frac{3}{11}\)
\(x-\frac{8}{11}=\frac{3}{11}\)
\(x=1\)
b) \(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
\(\frac{2}{42}+\frac{2}{56}+\frac{2}{72}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
\(\frac{2}{6.7}+\frac{2}{7.8}+\frac{2}{8.9}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
\(2.\left(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{2}{9}\)
\(2.\left(\frac{1}{6}-\frac{1}{x+1}\right)=\frac{2}{9}\)
\(\frac{1}{6}-\frac{1}{x+1}=\frac{1}{9}\)
\(\frac{1}{x+1}=\frac{1}{18}\)
=> x + 1 =18
x = 17
bài 2 ko bk lm, xl nha
Mình cần gấp bài này !!!
1/Tìm x, biết :
a/ \(\frac{7}{\left(x+3\right)\left(x+10\right)}+\frac{11}{\left(x+10\right)\left(x+21\right)}+\frac{13}{\left(x+21\right)\left(x+34\right)}+\frac{x}{\left(x+3\right)\left(x+34\right)}\)
b/ \(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(x-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=\frac{-1}{20}\)
Tìm x : \(2x+\frac{7}{6}+\frac{13}{12}+\frac{21}{20}+\frac{31}{30}+\frac{43}{42}+\frac{57}{56}+\frac{73}{72}+\frac{91}{90}=10\)10
\(2x+\frac{7}{6}+\frac{13}{12}+\frac{21}{20}+\frac{31}{30}+\frac{43}{42}+\frac{57}{56}+\frac{73}{72}+\frac{91}{90}=10\)
=> \(2x+\frac{6+1}{6}+\frac{12+1}{12}+....+\frac{90+1}{90}=10\)
=> \(2x+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}+10=10\)
=> \(2x+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}=0\)
=>\(2x+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}=0\)
=>\(2x+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}=0\)
=> \(2x-\frac{1}{10}=0\)
=>2x=\(\frac{1}{10}\)=> x=1/20
mình có bị nhầm chỗ dấu suy ra thứ 3. đáng lẽ ra biểu thức đó cộng 8 chứ k phải cộng 10 do mình sơ ý nên bạn hãy sủa lại chỗ ấy
Bài 1 Tìm x biết
a ) \(\frac{5}{6}=\frac{x}{24}\)
b) \(\frac{4}{7}=\frac{12}{x}\)
c) \(\frac{3}{x}=\frac{7}{21}\)
d) \(\frac{x}{-4}=\frac{20}{16}\)
\(\frac{5}{6}=\frac{15}{24}\)
\(\frac{4}{7}=\frac{12}{21}\)
\(\frac{3}{9}=\frac{7}{21}\)
\(\frac{-5}{-4}=\frac{20}{16}\)
5/6 = x/24 = 5*24 = 6*x = 120 = 6*x suy ra x= 120:6=20
4/7 = 12/x = 4*x = 7*12 = 4*x = 84 suy ra x= 84:4=21
3/x = 7/21 = 3/x = 1/3 = 3*3 = 1*x = 9 = 1*x suy ra x=9:1=9
x/-4 = 20/16 = x/-4 = 5/4 = x*4 = -4*5 = x*4 = -20 suy ra x=-20:4=-5
a) \(\frac{5}{6}\)= \(\frac{x}{24}\)
\(\Rightarrow\)\(x.6=24.5\)
x = \(\frac{24\cdot5}{6}\)
x=20
Vậy x = 20
b)\(\frac{4}{7}\)=\(\frac{20}{x}\)
\(\Rightarrow\)\(4\cdot x=20\cdot7\)
x= \(\frac{20\cdot7}{4}\)
x=35
Vậy x = 35
c)\(\frac{3}{x}\)=\(\frac{7}{21}\)
\(\Rightarrow\)\(x\cdot7=3\cdot21\)
x= \(\frac{3\cdot21}{7}\)
x= 9
Vậy x =9
d) \(\frac{x}{-4}\)=\(\frac{20}{16}\)
\(\Rightarrow\)\(x\cdot16=-4\cdot20\)
x= \(\frac{\left(-4\right)\cdot20}{16}\)
x =16
Vậy x = 16
CHÚC BẠN HỌC GIỎI
tìm x biết \(2x+\frac{7}{6}+\frac{13}{12}+\frac{21}{20}+\frac{31}{30}+\frac{43}{42}+\frac{57}{56}+\frac{73}{72}+\frac{91}{90}=10\)