571100 đúng 100%

( 198 : 18 - 143 : 13 ) x ( 16996 - 1110 : 30 x 305 )

= ( 11 - 11 ) x ( 16996 - 1110 : 30 x 305 )

= 0 x ( 16996 - 1110 : 30 x 305 )

= 0

 Kết quả là 0

MÌnh vừa làm xong 

[1998: 18 - 1443 : 13 ] nhân [16996 - 1110 ; 30 nhân 305 ] = 0

cho linh

\(A=2016:4+4048:2\\ =504+2024\\ =2528\\ B=37064-64\cdot\left(82+42966:2017\right)\\ =37064-64\cdot\left(82+21,30193356\right)\\ =37064-64\cdot103,3019336\\ =37064-6611,323748\\ =30452,67625\\ C=\left(100+92\cdot42\right)+\left(200-58\right)\cdot58\\ =\left(100+3864\right)+142\cdot58\\ =3964+8236\\ =12200\\ D=\left(1998:18-1443:13\right)\cdot\left(16996-1110:30\cdot305\right)\\ =\left(111-111\right)\cdot\left(16996-1110:30\cdot305\right)\\ =0\cdot\left(16996-1110:30\cdot305\right)\\ =0\)

a.

\(\left(100+42\right)\times42+\left(200-58\right)\times58=142\times42+142\times58=142\times\left(42+58\right)=142\times100=14200\)

b.

\(\left(1998\div18-1443\div13\right)\times\left(16996-1110\div30\times305\right)=\left(111-111\right)\times\left(16996-1110\div30\times305\right)\)

\(=0\times\left(16996-1110\div30\times305\right)=0\)

c.

\(5^3_5+1,75+6^1_8+4^1_4+3,875+3,4=5,6+1,75+6,125+4,25+3,875+3,4\)

\(=\left(5,6+3,4\right)+\left(1,75+4,25\right)+\left(6,125+3,875\right)=9+6+10=25\)

Giải theo cách lớp 5

a)(100+42)x42+(200-58)x58

=142x42-142x58

=(42-58)x142

=(-16).142

=-2272

b)(1998:18-1443:13)x(16996-1110:30x305)

=(111-111)x(16996-1110:30x305)

=0x(16996-1110:30x305)

=0

c)\(5\frac{3}{5}\)+1,75+\(6\frac{1}{8}\)+\(4\frac{1}{4}\)+3,875+3,4

=(1,75+\(4\frac{1}{4}\))+(3,875+\(6\frac{1}{8}\))+(3,4+\(5\frac{3}{5}\))

=6+10+9

=25

A) \(\frac{131313}{151515}+\frac{131313}{353535}+\frac{131313}{636363}+\frac{131313}{999999}\)

\(=\frac{10101\times13}{10101\times15}+\frac{10101\times13}{10101\times35}+\frac{10101\times13}{10101\times63}+\frac{10101\times13}{10101\times99}\)

\(=\frac{13}{15}+\frac{13}{35}+\frac{13}{63}+\frac{13}{99}\)

\(=13\times\left(\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}\right)\)

\(=13\times\frac{4}{33}=\frac{52}{33}\)

B) \(\left(1998:18-1443:13\right)\times\left(16996-1110:30\times305\right)\)

\(=\left(111-111\right)\times\left(16996-1110:30\times305\right)\)

\(=0\times\left(16996-1110:30\times305\right)\)

\(=0\)

( TẤT CẢ MỌI SỐ NHÂN VỚI 0 ĐỀU BẰNG 0)

C) \(\left(\frac{575757}{424242}+\frac{575757}{565656}+\frac{575757}{727272}\right)\times18\)

\(=\left(\frac{10101\times57}{10101\times42}+\frac{10101\times57}{10101\times56}+\frac{10101\times57}{10101\times72}\right)\times8\)

\(=\left(\frac{57}{42}+\frac{57}{56}+\frac{57}{72}\right)\times8\)

\(=\left(\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)\times57\times8\)

\(=\frac{1}{169344}\times57\times8\)

\(=\frac{19}{7056}\)

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 a, = 13/15 + 13/35 + 13/63 + 13/99

    = 13.( 1/15 + 1/35 + 1/63 + 1/99 )

   = 13.( 1/ 3.5 + 1/5.7 + 1/7.9 + 1/ 9.11)

 = 13 . ( 1/3 - 1/5 +1/5 - 1/7 + 1/7 - 1/9 + 1/9 - 1/11)

 = 13 . ( 1/3 - 1/11)

= 13 . 3/11 = 39/11

\(\left(a\right)37064-64\left(82+\frac{42966}{217}\right)\)

\(=37064-64\left(82+198\right)\)

\(=37064-64\cdot280\)

\(=30764-17920=19144\)

\(\left(b\right)320-\left(120,5+95,25+5,25\right)+\frac{84}{12}\cdot12,5\)

\(=320-\left(120,5+100,5\right)+7\cdot12,5\)

\(=320-221+87,5=11,5\)

\(\left(c\right)\left(4\frac{2}{5}+2\frac{3}{7}\right)-\left(2\frac{2}{5}-5\frac{4}{7}\right)\)

\(=4\frac{2}{5}-2\frac{2}{5}+2\frac{3}{7}+5\frac{4}{7}\)

\(=2+8=10\)

\(\left(d\right)\left(\frac{1998}{18}-\frac{1443}{13}\right)\left(16996-\frac{1110}{30}\cdot305\right)\)

\(=\left(111-111\right)\left(16996-\frac{1110}{30}\cdot305\right)\)

\(=0\left(16996-\frac{1110}{30}\cdot305\right)=0\)

\(\left(e\right)5\frac{3}{5}+1,75+6\frac{1}{8}+4\frac{1}{4}+3,875+3,4\)

\(=5\frac{3}{5}+1\frac{3}{4}+6\frac{1}{8}+4\frac{1}{4}+3\frac{7}{8}+3\frac{2}{5}\)

\(=5\frac{3}{5}+3\frac{2}{5}+1\frac{3}{4}+4\frac{1}{4}+6\frac{1}{8}+3\frac{7}{8}\)

\(=9+6+10=25\)