10A = 10^2018+10/10^2018+1 = 1 + 9/10^2018 + 1

10B = 10^2017+10/10^2017+1 = 1 + 9/10^2017+1

Vì : 2^2018 <> 2^2017 => 2^2018+1 > 2^2017+1

=> 9/10^2018+1 < 9/10^2017+1

=> 10A < 10B

=> A < B

Tk mk nha

Ko phải là 2017 + 1

vì (-21/10) mũ 2016 có số mũ dương => (-21/10) mũ 2016 = (21/10) mũ 2016

=> A= (21/10) mũ 2016 - (12/10) mũ 2017

vì (-12/10) mũ 2016 có số mũ dương => (-12/10) mũ 2016 = (12/10) mũ 2016

=> B=(12/10) mũ 2016 - (21/10) mũ 2017
So sánh: A có số trừ lớn hơn B
              A có số bị trừ nhỏ hơn B 

=> A > B

P/s: (-12/10) mũ 2016 là trừ 12 phần 10 mũ 2016 nhé :V

thánh nó trl

\(\text{So sánh : }\)

\(A=2017^{10}+2017^9=1,1149984e33\)

\(B=2018^{10}=1,11998349e33\)

\(\text{Vì : }1,1149984e33< 1,11998349e33\text{ nên }A< B\)

ko tính kết quả

\(A=\frac{2017^{2018+1}}{2017^{2018-3}}\)và \(B=\frac{2017^{2018-1}}{2017^{2018-5}}\)

Có \(A=\frac{2017^{2019}}{2017^{2015}}\)và \(B=\frac{2017^{2017}}{2017^{2013}}\)

Mà\(\frac{2017^{2019}}{2017^{2015}}>\frac{2017^{2018}}{2017^{2015}}\)và\(\frac{2017^{2017}}{2017^{2013}}>\frac{2017^{2017}}{2017^{2015}}\)

Vì \(\frac{2017^{2018}}{2017^{2015}}>\frac{2017^{2017}}{2017^{2015}}\)

Vậy A>B

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a) Lập bảng

Ta có: 2018 : 4 = 504 (dư 2)

Suy ra \(2017^{2018}+2019^{2018}= \overline{...9}+\overline{...1}=\overline{...0}\)

Vậy 2017²⁰¹⁸ + 2019²⁰¹⁸ chia hết cho 10

b) Làm tương tự như câu a)