Giai Phuong Trinh :
\(\frac{3}{5x-1}\)+\(\frac{2}{3-5x}\)=\(\frac{4}{\left(1-5x\right)\left(x-3\right)}\)
Những câu hỏi liên quan
Giai phuong trinh:
a)\(\frac{4+9x}{9x^21}=\frac{3}{3x+1}-\frac{2}{1-3x}\)
b)\(\frac{2x-3}{x+1}+\frac{x^2-5x+10}{\left(x+1\right)\left(x-3\right)}=\frac{3x-5}{x-3}\)
c)\(\frac{x\left(x+4\right)}{2x-3}=\frac{x^2+4}{2x-3}+1-\frac{2}{3-2x}\)
d)\(\frac{1}{x+2}+\frac{x}{x-3}=1-\frac{5x}{\left(x+2\right)\left(3-x\right)}-\frac{1}{x+2}\)
giai phuong trinh a) \(\left(\frac{x+3}{x+2}\right)^2+6\cdot\left(\frac{x-3}{x-2}\right)^2-5\cdot\frac{x^2-9}{x^2-4}=0\)
b)(12x-1)*(x-1)*(4x-1)*(3x-1)=330
c)\(\frac{4x}{x^2+5x+3}+\frac{5x}{x^2-5x+3}=\frac{-3}{2}\)
giai phuong trinh
a)\(\frac{x+1}{x-1}-\frac{x-1}{x+1}=3x\left(1-\frac{x-1}{x+1}\right)\)
b)\(x^4+5x^3+12x^2+5x+13=0\)
c)\(\frac{3x-1}{x-1}-\frac{2x+5}{x+3}+\frac{4}{x^2+2x-3}=1\)
a)\(\Leftrightarrow-\frac{x}{x+1}+\frac{1}{x+1}+\frac{x}{x-1}+\frac{1}{x-1}=-\frac{3x^2}{x+1}+\frac{3x}{x+1}+3x\)
\(\Rightarrow\frac{3x^2}{x+1}-\frac{4x}{x+1}+\frac{1}{x+1}+\frac{x}{x-1}-3x+\frac{1}{x-1}=0\)
\(\Leftrightarrow-\frac{2x\left(3x-5\right)}{\left(x-1\right)\left(x+1\right)}=0\)
\(\Rightarrow\int^{\frac{x-1}{1}=0}_{\frac{x+1}{1}=0}\Rightarrow x=0\)
=>3x=5
\(\Rightarrow x=\frac{3}{5}\)
vậy \(x=\frac{3}{5}\) hoặc 0
b)x = -(20309916*i+23555105)/9277755;
x = -(985155752*i-35635815)/916564140;
x = (985155752*i+35635815)/916564140;
x = (20309916*i-23555105)/9277755;
c)\(\Leftrightarrow\frac{x+2}{x-1}=\frac{1}{1}\Rightarrow\left(x+2\right)1=\left(x-1\right)1\)
vì \(\left(x+2\right)1\ne\left(x-1\right)1\)
=>x vô nghiệm hoặc đề sai
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Xem thêm câu trả lời
26 ,giải phương trình.
a,\(\frac{1}{x-1}+\frac{2}{x^2+x+1}=\frac{3x^2}{x^3-1}\)
b,\(\frac{x}{2\left(x-3\right)}+\frac{x}{2\left(x+1\right)}=\frac{2x}{\left(x+1\right)\left(x-3\right)}\)
c,\(\frac{x-1}{x+2}+\frac{x-2}{x+1}=\frac{2\left(x^2+2\right)}{x^2-4}\)
d,\(\frac{3}{5x-1}+\frac{2}{3-5x}=\frac{4}{\left(1-5x\right)\left(x-3\right)}\)
https://i.imgur.com/V92CPVX.jpg
https://i.imgur.com/yXrzVbQ.jpg
\(\frac{x\left(x+1\right)}{2\left(x+1\right)\left(x-3\right)}+\frac{x\left(x-3\right)}{2\left(x+1\right)\left(x-3\right)}=\frac{4x}{2\left(x+1\right)\left(x-3\right)}\)
\(\Leftrightarrow x^2+x+x^2-3x=4x\Leftrightarrow2x^2-6x=0\Leftrightarrow2x\left(x-3\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)
Xem thêm câu trả lời
\(\frac{3}{5x-1}+\frac{2}{3-5x}=\frac{4}{\left(5x-1\right)\left(3-5x\right)}\)
\(\frac{3}{\left(5x-1\right)}+\frac{2}{3-5x}=\frac{4}{\left(5x-1\right)\left(3-5x\right)}\)
\(\Rightarrow9-15x+10x-2=4\)
\(\Leftrightarrow3-5x=0\)
\(\Leftrightarrow x=\frac{3}{5}\)
\(\frac{3}{\left(5x-1\right)}+\frac{2}{3-5x}=\frac{4}{\left(5x-1\right)\left(3-5x\right)}\)
⇒9 − 15x + 10x − 2 = 4
⇔3 − 5x = 0
⇔x =\(\frac{3}{5}\)
\(\frac{3}{5x-1}-\frac{2}{3-5x}=\frac{4}{\left(1-5x\right)\left(5x-3\right)}\)
\(ĐKXĐ:x\ne\frac{1}{5},x\ne\frac{3}{5}\)
Ta có : \(\frac{3}{5x-1}=\frac{2}{3-5x}=\frac{4}{\left(1-5x\right)\left(5x-3\right)}\)
\(\Leftrightarrow\frac{3\left(3-5x\right)}{\left(5x-1\right)\left(3-5x\right)}-\frac{2\left(5x-1\right)}{\left(5x-1\right)\left(3-5x\right)}+\frac{4}{\left(5x-1\right)\left(5x-3\right)}=0\)
\(\Rightarrow9-15x-10x+2+4=0\)
\(\Leftrightarrow-25x=-15\)
\(\Leftrightarrow x=\frac{3}{5}\) ( không thỏa mãn \(ĐKXĐ\) )
Vậy pt đã cho vô nghiệm
1)2x(25x-4)-(5x-2)(5x+1)8 / 5)2left(x-2right)-3left(3x-1right)left(x-3right)
2)x(4x-3)-(2x-2)(2x-1)5 / 6)frac{2}{x+1}-frac{1}{x-2}frac{3x-11}{left(x+1right)left(x-2right)}
3)frac{5}{2x+3}+frac{3}{9-x^2}frac{8}{7left(x3right)} / 7)frac{5x-2}{6}+frac{3-4x}{2}2-frac{x+7}{3}
4)frac{2}{3left(x-2right)}+frac{5}{12-3x^2}frac{3}{4left(x+2right)} /...
Đọc tiếp
1)2x(25x-4)-(5x-2)(5x+1)=8 / 5)\(2\left(x-2\right)-3\left(3x-1\right)=\left(x-3\right)\)
2)x(4x-3)-(2x-2)(2x-1)=5 / 6)\(\frac{2}{x+1}-\frac{1}{x-2}=\frac{3x-11}{\left(x+1\right)\left(x-2\right)}\)
3)\(\frac{5}{2x+3}+\frac{3}{9-x^2}=\frac{8}{7\left(x=3\right)}\) / 7)\(\frac{5x-2}{6}+\frac{3-4x}{2}=2-\frac{x+7}{3}\)
4)\(\frac{2}{3\left(x-2\right)}+\frac{5}{12-3x^2}=\frac{3}{4\left(x+2\right)}\) / 8)\(\frac{2}{x+1}-\frac{1}{x-2}=\frac{3x-11}{\left(x+1\right)\left(x-2\right)}\)
Đây là lớp 8 nha các b giúp mk với
Do mk viết nhầm
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\(\frac{\left(x-2\right)^2}{3}-\frac{2x-1}{4}=4-\frac{\left(2x-3\right)^2}{6}\)
Giai phuong trinh
\(\frac{\left(x-2\right)^2}{3}-\frac{2x-1}{4}=4-\frac{\left(2x-3\right)^2}{6}.\)
\(\Rightarrow\frac{4\left(x-2\right)^2}{12}-\frac{3\left(2x-1\right)^2}{12}=\frac{48}{12}-\frac{2\left(2x-3\right)^2}{12}\)
\(\Rightarrow4\left(x^2-4x+4\right)-3\left(4x^2-4x+1\right)=48-2\left(4x^2-12x+9\right)\)
\(\Rightarrow4x^2-16x+16-12x^2+12x-3=48-8x^2+24x-18\)
\(\Rightarrow-16x+12x+16-3=24x+48-18\)
\(\Rightarrow28x=-17\Leftrightarrow x=-\frac{17}{28}\)
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\(\frac{\left(x-2\right)^2}{3}-\frac{2x+1}{4}=4-\frac{\left(2x-3\right)^2}{6}\)
Giai phuong trinh
-------------------ko chép đề nha---------
\(\Leftrightarrow\frac{4\left(x^2-4x+4\right)-3\left(2x+1\right)}{12}=\frac{12-2\left(4x^2-12x+9\right)}{12}\)
\(\Rightarrow4x^2+16x+16-6x-3=12-8x^2+24x-18\)
\(\Leftrightarrow4x^2+10x+13=-8x^2+24x-6\)
\(\Leftrightarrow4x^2+8x^2+10x-24x+13+6=0\)
\(\Leftrightarrow12x-14x+19=0\)
Ta có :\(\Delta'=7^2-12.19=-179< 0\)
\(\Rightarrow\)phương trình vô nghiệm
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