2/7x9/7-18/49x1/2
2/5 x 7+2/7x9+2/9x11+...+2/13x15
2/5x7+2/7x9+2/9x11+...+2/13x15
=1/5x7+1/7x9+1/9x11+...+1/13x15
=1/5-1/15
=3/15-1/15
=2/15
A = \(\dfrac{2}{5\times7}\)+ \(\dfrac{2}{7\times9}\)+ \(\dfrac{2}{9\times11}\)+.........+ \(\dfrac{2}{13\times15}\)
A = \(\dfrac{1}{5}\)- \(\dfrac{1}{7}\)+ \(\dfrac{1}{7}\) -\(\dfrac{1}{9}\)+ \(\dfrac{1}{9}\) - \(\dfrac{1}{11}\)+ .......\(\dfrac{1}{13}\) - \(\dfrac{1}{15}\)
A = \(\dfrac{1}{5}\) - \(\dfrac{1}{15}\)
A = \(\dfrac{3-1}{15}\)
A = \(\dfrac{2}{15}\)
tim x: 1/5 x 7+1/7x9+...+1/X(x+2)=7/95
Đặt VT=A
\(2A=\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{x\left(x+2\right)}\)
\(2A=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{x}-\frac{1}{x+2}\)
\(A=\left(\frac{1}{5}-\frac{1}{x+2}\right):2\)
Thay A vào VT ta đc:
\(\left(\frac{1}{5}-\frac{1}{x+2}\right):2=\frac{7}{95}\)
\(\frac{1}{5}-\frac{1}{x+2}=\frac{14}{95}\)
\(\frac{1}{x+2}=\frac{1}{19}\)
\(\Rightarrow x+2=19\)
\(\Rightarrow x=17\)
\(\text{Đặt VT=A }\)
\(2A=\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{x\left(x+2\right)}\)
\(2A=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{x}-\frac{1}{x+2}\)
\(A=\left(\frac{1}{5}-\frac{1}{x+2}\right):2\)
\(\text{Thay A vào VT ta đc: }\)
\(\left(\frac{1}{5}-\frac{1}{x+2}\right):2=\frac{7}{95}\)
\(\frac{1}{5}-\frac{1}{x+2}=\frac{14}{95}\)
\(\frac{1}{x+2}=\frac{1}{19}\)
\(\Rightarrow x+2=19\)
\(\Rightarrow x=17\)
Dũng thực hiện phép tính nhân 7x9, sau đó Dũng thêm vào 1 trong 2 thừa số 2 đơn vị thì thấy tích tăng thêm 18 đơn vị. Hỏi Dũng đã thêm 2 đơn vị vào thừa số nào?
Tích ban đầu là : \(7\times9=63\)
Tích lúc sau là : \(63+18=81\)
Ta thấy : \(81=9\times9\)mà thừa số thứ hai là 9 rồi, vậy 2 đơn vị đó sẽ được thêm vào thừa số thứ nhất
a,\((\) 1\(-\) \(\dfrac{1}{3}\)\()\)x\((\)1\(-\)\(\dfrac{2}{5}\)\()\)x\((\)1\(-\)\(\dfrac{2}{7}\)\()\)x\((\)1\(-\)\(\dfrac{2}{9}\)\()\)
b,\(\dfrac{1}{1x3}\) + \(\dfrac{1}{3x5}\) + \(\dfrac{1}{5x7}\) + \(\dfrac{1}{7x9}\)
a) \(\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{2}{5}\right)\times\left(1-\dfrac{2}{7}\right)\times\left(1-\dfrac{2}{9}\right)\)
\(=\left(\dfrac{3}{3}-\dfrac{1}{3}\right)\times\left(\dfrac{5}{5}-\dfrac{2}{5}\right)\times\left(\dfrac{7}{7}-\dfrac{2}{7}\right)\times\left(\dfrac{9}{9}-\dfrac{2}{9}\right)\)
\(=\dfrac{2}{3}\times\dfrac{3}{5}\times\dfrac{5}{7}\times\dfrac{7}{9}\)
\(=\dfrac{2\times3\times5\times7}{3\times5\times7\times9}\)
\(=\dfrac{2}{9}\)
b) \(\dfrac{1}{1\times3}+\dfrac{1}{3\times5}+\dfrac{1}{5\times7}+\dfrac{1}{7\times9}\)
\(=1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}\)
\(=1-\dfrac{1}{9}\)
\(=\dfrac{9}{9}-\dfrac{1}{9}\)
\(=\dfrac{8}{9}\)
a . -15:5/4
b. 3/5*15/7-15/7*8/5
c x*3/2=âm 7/6
d S=2/5x7 + 2/7x9 + 2/9x11 +...+2/93x95
cảm ơn trước nha !!! cs j kb vs mik
Câu1: -12
Câu 2: -15/7
Cau3: -7/9
Caau4: 36/95
a.7x9 b.6x4 [Mẫu : a.7x9=7+7+7+7+7+7+7+7+7=63)
c.4x9 d.9x9
10 nhaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
A. 7 x 9 = 63
B. 6 x 4 = 24
C. 4 x 9 = 36
D. 9 x 9 = 81
HT~~
a) (137x25-25x37):10
b) 2/7x21/4-2/7:13/4
c)(124x237+152):(870+235x122)
d)27x43+27x57/2+4+6+.....+16
e) 5/7x2/11 + 5/7x9/11x9/7
a) (137x25-25x37):10
=25x(137-37):10
=25x100:10
=2500:10
=250
b) 2/7x21/4-2/7:13/4
=2/7x21/4-2/7x4/13
=2/7x(21/4-4/13)
=2/7x257/52
=257/182
c)(124x237+152):(870+235x122)
=(29388+152):(870+28670)
=29540:29540
=1
a) (137 x 25 - 25 x 37 ) : 10 = (25 x (137 - 37) ) : 10
= (25 x 100) : 10
= 2500 : 10
= 250
a) (137x25-25x37):10
b) 2/7x21/4-2/7:13/4
c)(124x237+152):(870+235x122)
d)27x43+27x57/2+4+6+.....+16
e) 5/7x2/11 + 5/7x9/11x9/7
a)=(3425-925):10
=25200:10
=250
b)=3/2-8/91
=257/182
c)=(29388+152):(870+28670)
=29540:29540
=1
d)=1161+1539/72
=2700/72=75/2
e)=10/77+45/77x9/7
=10/77+405/539
=475/539
li ke cho mình nha Lam Le thi