a/

\(b=\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{97.99}\)

\(2b=\dfrac{3-1}{1.3}+\dfrac{5-3}{3.5}+\dfrac{7-5}{5.7}+...+\dfrac{99-97}{97.99}=\)

\(=1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{97}-\dfrac{1}{99}=\)

\(=1-\dfrac{1}{99}=\dfrac{98}{99}\Rightarrow b=\dfrac{98}{2.99}=\dfrac{49}{99}\)

b/

\(c=\dfrac{3-1}{1.2.3}+\dfrac{4-2}{2.3.4}+\dfrac{5-3}{3.4.5}+...+\dfrac{100-98}{98.99.100}=\)

\(=\dfrac{1}{1.2}-\dfrac{1}{2.3}+\dfrac{1}{2.3}-\dfrac{1}{3.4}+\dfrac{1}{3.4}-\dfrac{1}{4.5}+\dfrac{1}{98.99}-\dfrac{1}{99.100}=\)

\(=\dfrac{1}{2}-\dfrac{1}{99.100}\)

c/

\(\dfrac{2}{5}.d=\dfrac{4-2}{2.3.4}+\dfrac{5-3}{3.4.5}+...+\dfrac{100-98}{98.99.100}+\dfrac{101-99}{99.100.101}=\)

\(=\dfrac{1}{2.3}-\dfrac{1}{3.4}+\dfrac{1}{3.4}-\dfrac{1}{4.5}+...+\dfrac{1}{98.99}-\dfrac{1}{99.100}+\dfrac{1}{99.100}-\dfrac{1}{100.101}=\)

\(=\dfrac{1}{2.3}-\dfrac{1}{100.101}\Rightarrow d=\left(\dfrac{1}{2.3}-\dfrac{1}{100.101}\right):\dfrac{2}{5}\)

\(\left(\dfrac{1}{1.2.3}+\dfrac{1}{2.3.4}+\dfrac{1}{3.4.5}+...+\dfrac{1}{98.99.100}\right)x=-3\)

\(\dfrac{1}{2}\left(\dfrac{1}{1.2}-\dfrac{1}{2.3}+\dfrac{1}{2.3}-\dfrac{1}{3.4}+...+\dfrac{1}{98.99}-\dfrac{1}{99.100}\right)x=-3\)

\(\dfrac{1}{2}.\left(\dfrac{1}{2}-\dfrac{1}{9900}\right)x=-3\)

\(\dfrac{1}{2}.\dfrac{4949}{9900}x=-3\)

\(\dfrac{4949}{19800}x=-3\)

\(x=-3:\dfrac{4949}{19800}\)

\(x=-\dfrac{59400}{4949}\)

Tính 

a,1.2.3+2.3.4+3.4.5+......+ 98.99.100

b,1 bình +2 bình +3 bình +....+100 bình

Giải:Đặt A=1.2.3+2.3.4+..........+98.99.100

4A=1.2.3.4+2.3.4.5-1.2.3.4+...........+98.99.100.101-97.98.99.100

4A=98.99.100.101=97990200\(\Rightarrow A=24497550\)

b,Đặt B=1²+2²+................+100²

B=1.(2-1)+2.(3-1)+.............+100.(101-1)

B=1.2+2.3+.......+100.101-1-2-..........-100

Đặt C=1.2+2.3+........+100.101

3C=1.2.3+2.3.4-1.2.3+........+100.101.102-99.100.101

3C=100.101.102=1030200\(\Rightarrow C=343400\)

\(\Rightarrow B=343400-\frac{100.101}{2}=343400-5050=338350\)

\(S:3.2=\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+....+\frac{2}{98.99.100}\)

\(\frac{1}{1.2}-\frac{1}{2.3}=\frac{2}{1.2.3}\)

\(\frac{1}{2.3}-\frac{1}{3.4}=\frac{2}{2.3.4}\)

Tương tự nhé ta có

\(\frac{2S}{3}=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...-\frac{1}{99.100}=\frac{1}{2}-\frac{1}{9900}=\frac{4949}{9900}\)

\(S=\frac{4949}{6600}\)

A= 1.2.3 + 2.3.4 + 3.4.5 +.....+ 98.99.100

4A = 98.99.100.4 + .....+ 3.4.5.4 + 2.3.4.4 + 1.2.3.4

4A = 98.99.100.(101-97) +... + 2.3.4.(5-1) + 1.2.3.4

4A = 98.99.100.101 - 97.98.99.100+......+2.3.4.5 - 1.2.3.4 + 1.2.3.4

4A = 98.99.100.101

  A = 98.99.100.101 : 4

  A = 24497550

\(S=1.2.3+2.3.4+...+98.99.100.\)

\(\Rightarrow4S=4\left(1.2.3+2.3.4+...+98.99.100\right)\)

\(=1.2.3.4+2.3.4.4+...+98.99.100.4\)

\(=1.2.3.\left(4-0\right)+2.3.4.\left(5-1\right)+...+98.99.100.\left(101-97\right)\)

\(=1.2.3.4-0.1.2.3+2.3.4.5-1.2.3.4+...+98.99.100.101-97.98.99.100\)

\(=98.99.100.101\)

\(\Rightarrow S=\frac{98.99.100.101}{4}=24497550\)

thanks

Coi A = 1.2.3 + 2.3.4 +... + 98.99.100

 4A = 1.2.3.4 + 2.3.4.4 +... + 98.99.100.4

 4A = 1.2.3.4 + 2.3.4.(5-1) +... + 98.99.100.(101-97)

4A = 1.2.3.4+2.3.4.5-1.2.3.4 + ... + 98.99.100.101-97.98.99.100

4A = 98.99.100.101

4A =97990200

A = 97990200: 4

A=24497550

cảm ơn bạn