\(=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=1+1=2\)

2

= 2

( 7/4+5/4) x 5/3= 12/4 x 5/3 = 3 x 5/3= 5

5

5

=2/3+2/3=4/3

\(\dfrac{2}{3}+\dfrac{4}{5}\times\dfrac{5}{6}=\dfrac{2}{3}+\dfrac{2}{3}=\dfrac{4}{3}\)

`4/15-1/5`

`= 4/15- 3/15`

`=(4-3)/15`

`=1/15`

4/15 - 1/5 = 4/15 - 3/15 = (4 - 3)/15 = 1/15

4/15 - 1/5

= 4/15 - 3/15

=1/15

Ta có: \(S=\left(5-\frac{2}{3}+\frac{3}{2}\right)-\left(7-\frac{5}{4}-\frac{1}{2}\right)-\left(1-\frac{4}{3}+\frac{2}{5}\right).\)

\(\Rightarrow S=\left(\frac{13}{3}+\frac{3}{2}\right)-\left(\frac{23}{4}-\frac{1}{2}\right)-\left(\frac{-1}{3}+\frac{2}{5}\right)\)

\(\Rightarrow S=\frac{35}{6}-\frac{21}{4}-\frac{1}{15}\)

\(\Rightarrow S=\frac{7}{12}-\frac{1}{15}=\frac{31}{60}\)

Vậy \(S=\frac{31}{60}\)

`8/9xx8/5`

`=(8xx8)/(9xx5)`

`=64/45`

\(=\dfrac{8x8}{9x5}=\dfrac{64}{45}\)

8/9 x 8/5 = 8 x 8 / 9 x 5

=  64 /45

\(\dfrac{9}{4}\times\dfrac{15}{11}+\dfrac{3}{4}:\dfrac{11}{7}-\dfrac{3}{4}\times\dfrac{8}{11}\)
\(=\dfrac{3}{4}\times3\times\dfrac{15}{11}+\dfrac{3}{4}\times\dfrac{7}{11}-\dfrac{3}{4}\times\dfrac{8}{11}\)
\(=\dfrac{3}{4}\times\dfrac{45}{11}+\dfrac{3}{4}\times\dfrac{7}{11}-\dfrac{3}{4}\times\dfrac{8}{11}\)
\(=\dfrac{3}{4}\times\left(\dfrac{45}{11}+\dfrac{7}{11}-\dfrac{8}{11}\right)\)
\(=\dfrac{3}{4}\times4\)
\(=3\)

`9/4xx15/11+3/4:11/7-3/4xx8/11`

`=3/4xx15/11xx3+3/4xx7/11-3/4xx8/11`

`=3/4xx45/11+3/4xx7/11-3/4xx8/11`

`=3/4xx(45/11+7/11-8/11)`

`=3/4xx4`

`=3`