cho a = 1/201+1/2002+1/203+...+1/300.chứng minh a>11/30
cho a = 1/201+1/202+1/203+...+1/300. chứng minh a>11/30
s=1/201+1/202+1/203+.........+1/299+1/300 Chứng tỏ S>11/30
Cho A = 1/200+1/201+1/202+1/203+.......+1/300 . Chứng minh rằng A <9/20
Cho A=1/201+1/202+1/203+......+1/300.Chứng tỏ A<9/20
Giúp mik nhanh nha
Cho S = 1/201 + 1/202 + 1/203 + ... + 1/299 + 1/300. Chứng minh rằng 1/3 < S < 1/2
Cho S = 1/201 + 1/202 + 1/203 + ... + 1/299 + 1/300. Chứng minh rằng 1/3 < S < 1/2
1/201>1/300,1/202>1/300.................1/300=1/300 =>S>1/300.100=1/3 1/201<1/200, 1/202<1/300.................1/300<1/200=>S<1/200.100=1/2
Ai làm đc(ghi cả lời giải chi tiết) nhan tin riêng mình xin hậu tạ 50k ạ
Cho A= 1/201+1/202+1/203+...+1/300.
Chứng minh rằng A<9/20
Ta chia A ra lam 2 khoang la tu B=1/201+1/202+...+1/250 (50 so hang)va tu C=1/251+1/252+...+1/300 (50 so hang)
ta thay 1/201=1/201, 1/202<1/201,....1/250<1/201
cong ca 2 ve cua 50 bat dang thuc cung chieu ta duoc B<50.1/201=> B<50/201
ta cung thay 1/251=1/251,1/252<1/251,....1/300<1/251
cong 2 ve cua 50 bat dang thuc cung chieu ta lai duoc C<50.1/251=> C<50/251
Ta thay A= B+C
suy ra A< 50/201+50/251=> A<0,448
ma tha thay 0,448<9/20
SUY RA A<9/20 (dpcm)
Thoi mik ko lay tien cua ban dau
Co gang len! Chuc ban hoc tot!
Cho A=\(\frac{1}{201}\)+\(\frac{1}{202}\)+\(\frac{1}{203}\)+...+\(\frac{1}{300}\).Chứng minh rằng A<\(\frac{9}{20}\)? Làm ơn giúp mik nha!
Ta có: A=1/201+1/202+1/203+...+1/300
=(1/201+1/202+...+1/250)+(1/251+1/252+...+1/300)
Ta có
1/201+1/202+...+1/250<1/200+1/200+...+1/200=50.1/200=50/200=1/4 (1)
1/251+1/252+...+1/300<1/250+1/250+...+1/250=50.1/250=50/250=1/5 (2)
từ (1) và (2)=> A<1/4+1/5=>A<9/20
Vậy A<9/20
~~~CHÚC BẠN HỌC GIỎI~~~
=>A=
Ta có: A=1/201+1/202+1/203+...+1/300
=(1/201+1/202+...+1/250)+(1/251+1/252+...+1/300)
Ta có
1/201+1/202+...+1/250<1/200+1/200+...+1/200=50.1/200=50/200=1/4 (1)
1/251+1/252+...+1/300<1/250+1/250+...+1/250=50.1/250=50/250=1/5 (2)
từ (1) và (2)=> A<1/4+1/5=>A<9/20
Vậy A<9/20
Cho A= 1/201 +1/202+1/203 +...+1/500 . Chứng minh A>5/7 , A>3/4