Ta co:4x+720/x=70/1/2

4x+720/x=140

Gặp cả 2 vế lên x lan,ta co

4x+720=140x

720=136x(bớt cả 2 vế đi 4x)

x=720/136=

\(70:\frac{4x+720}{x}=\frac{1}{2}\)

\(\frac{4x+720}{x}=70:\frac{1}{2}\)

\(\frac{4x+720}{x}=140\)

\(4x+720=140x\)

\(4x-140x=-720\)

\(-136x=-720\)

\(x=\frac{-720}{-136}\)

\(x=\frac{90}{17}\)

\(\frac{70x}{4x+720}=\frac{1}{2}\)

\(140x=4x+720\)

\(136x=720\)

        \(x=720:136\)

        \(x=\frac{90}{17}\)

\(70\div\frac{4x+720}{x}=\frac{1}{2}\)

=> \(70\cdot\frac{x}{4x+720}=\frac{1}{2}\)

=> \(\frac{70x}{4x+720}=\frac{1}{2}\)

=> \(70x\cdot2=4x+720\)

=> \(140x=4x+720\)

=> \(140x-4x=720\)

=> \(136x=720\)

=> \(x=\frac{720}{136}=\frac{90}{17}\)

\(70:\frac{4x+720}{x}=\frac{1}{2}\)

\(\Rightarrow\frac{4x+720}{x}=70:\frac{1}{2}=70.2=140\)

\(\Rightarrow4x+720=140.x\)

\(\Rightarrow720=136.x\)

\(\Rightarrow x=720:36=20\)

70:(4x+720/x)=1/2

<=>4x+720/x=140

=>4x+720=140x

<=>720=136x

<=>90=17x(chia hai vế cho 8)

<=>90/17=x

Vậy x=90/17

90/17

1111111111111111111111111111111111111111111111111111111111111111111111111111111

\(\frac{4x+720}{70\times x}=\frac{1}{2}\Rightarrow2\left(4x+720\right)=70x\)

<=>8x+1440=70x

 =>8x-70x=0-1440

=>-62x=-1440

=>x=\(\frac{720}{31}\)

\(1\)) \(70:\frac{4x+720}{x}=\frac{1}{2}\)

\(\Leftrightarrow\frac{4x+720}{x}=70:\frac{1}{2}\)

\(\Leftrightarrow\frac{4x+720}{x}=140\)

\(\Leftrightarrow\left(4x+720\right):x=140\)

\(\Leftrightarrow4x+720=140.x\)

\(\Leftrightarrow4x-140x=-720\)

\(\Leftrightarrow x.\left(-136\right)=-720\)

\(\Leftrightarrow x=-720:\left(-136\right)\)

\(\Leftrightarrow x=\frac{90}{17}\)

\(2\)) Mình đang nghĩ

x=20

\(70:\dfrac{4x+720}{x}=\dfrac{1}{2}\)

\(\Rightarrow\dfrac{4x+720}{x}=70:\dfrac{1}{2}=140\)

\(\Rightarrow4x+720=140.x\)

\(\Rightarrow720=36.x\)

\(\Rightarrow720:36=x\)

\(\Rightarrow x=20\)

Đk : x khác 0 

=> 35/2x + 720/x = 1/2

=> 35+1440/2x = 1/2

=> 1475/2x = 1/2

=> 1475 = 1/2 . 2x = x

Vậy x = 1475

k mk nha

X=1475

a)    (2x + 1)(3x - 2) = (5x - 8)(2x + 1)

 <=> 6x² - x - 2 = 10x² - 11x - 8

<=>  6x² - 10x² - x + 11x -2 + 8 = 0

<=>  -4x² + 10x + 6  = 0

<=> -2 (2x² - 5x - 3) = 0

<=> 2x² - 5x - 3 = 0 

<=> 2x² - 6x + x - 3 = 0

<=> x (2x + 1) - 3 (2x + 1) = 0

<=> (x - 3) (2x + 1) = 0

* x - 3 = 0  => x = 3

* 2x + 1 = 0 => x = -1/2 

S = {-1/2; 3}

b) 4x² – 1 = (2x +1)(3x -5)

<=> 4x² – 1 - (2x +1)(3x -5) = 0

<=> (2x - 1) (2x + 1) - (2x + 1)(3x - 5) = 0

<=>  (2x + 1) (2x - 1 - 3x + 5) = 0

<=>  (2x + 1) (-x + 4) = 0

* 2x + 1 = 0  <=> x = -1/2

* -x + 4 = 0 <=> x = 4

S = {-1/2; 4}

c) (x + 1)² = 4(x² – 2x + 1)

<=> (x + 1)² - 4(x² – 2x + 1) = 0

<=> (x + 1)² - 4(x² – 1)² = 0

* (x + 1)² = 0   <=> x = -1

* 4(x² - 1)² = 0  <=> x = 1 và x = -1

S = {-1;  1}

d) 2x³ + 5x² – 3x = 0

<=> x (2x² + 5x - 3) = 0

<=> x (2x² + 6x - x - 3) = 0

<=> x [x(2x - 1) + 3 (2x - 1)] = 0

<=> x (2x - 1) (x + 3) = 0

* x = 0

* 2x - 1 = 0  <=> x = 1/2

* x + 3 = 0  <=> x = -3

S = { -3; 0; 1/2}

\(\frac{1}{x^2+5x+4}+\frac{1}{x^2+11x+28}+\frac{1}{x^2+17x+70}=\frac{3}{4x-2}\)

\(\Leftrightarrow\frac{1}{\left(x+1\right)\left(x+4\right)}+\frac{1}{\left(x+4\right)\left(x+7\right)}+\frac{1}{\left(x+7\right)\left(x+10\right)}=\frac{3}{4x-2}\)

\(\Leftrightarrow3x^2+21x+36=0\)

\(\Leftrightarrow x=-3\)

70:4x + 720/x = 1/2

=> 70/4x + 2880/4x = 1/2

=> 2950/4x = 1/2

=> x = 1475