số bé:61,04-9,12=51,92

số lớn:51,92+9,12=143,12

Bài 8:

\(B=\frac{a}{ab+a+abc}+\frac{b}{bc+b+1}+\frac{2c}{ac+2c+abc}\\ =\frac{1}{b+1+bc}+\frac{b}{bc+b+1}+\frac{2}{a+2+ab}\\ =\frac{1}{b+1+bc}+\frac{b}{bc+b+1}+\frac{abc}{a+abc+ab}\\ =\frac{1}{b+1+bc}+\frac{b}{bc+b+1}+\frac{bc}{1+bc+b}\\ =\frac{1+b+bc}{b+1+bc}=1\)

Bài 9:

\(A=\frac{a}{ab+a+1}+\frac{ba}{abc+ab+a}+\frac{c.ab}{ac.ab+c.ab+ab}\\ =\frac{a}{ab+a+1}+\frac{ab}{1+ab+a}+\frac{1}{a+1+ab}\\ =\frac{ab+a+1}{ab+a+1}=1\)

Bài 10:

\((x-1)^{20}\geq 0, \forall x; (y+2)^{20}\geq 0, \forall y\)

Do đó để tổng $(x-1)^{20}+(y+2)^{20}=0$ thì $(x-1)^{20}=(y+2)^{20}=0$

$\Rightarrow x=1; y=-2$

Khi đó:

$A=2.1^5-5.(-2)^3+4=46$

\(x\times\left(0,1+4+2,9+2+1\right)=25,2\)

\(10x=25,2\)

\(x=2,52\)

\(x\times0,1+x\times4+x\times2,9+x\times2+x=25,2\)

\(x\times\left(0,1+4+2,9+2+1\right)=25,2\)

\(x\times10=25,2\)

\(x=25,2:10\)

\(x=2,52\)

tìm x mè giải thích sao :v?

tìm X hay tính thuận tiện

89888888

2 x 3 x 4 x 8 + 0.5 x 0.25 x 0.25

= 6 x 4 x 8 + 0.5 x 0.25 x 0.25

= 24 x 8 + 0.125 x 0.25

= 192 + 0.0625

= 192.0625

=192,03125

= 192,03125 nha bạn

a) \(2,4:0,25+5,6:4+2\times\frac{1}{4}\)

\(=2,4\times\frac{1}{4}+5,6\times\frac{1}{4}+2\times\frac{1}{4}\)

\(=\left(2,4+5,6+2\right)\times\frac{1}{4}\)

\(=10\times\frac{1}{4}=\frac{5}{2}\)

b)\(3,47\times\frac{1}{2}-2,47:2+0,5\)

\(=3,47\times\frac{1}{2}-2,47\times\frac{1}{2}+\frac{1}{2}\times1\)

\(=\left(3,47-2,47+1\right)\times\frac{1}{2}\)

\(=2\times\frac{1}{2}=1\)

#Y/n